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we have 3 critical points here 2,-2,-5 since the overall inequality is less than <0 then x<2 satisfy the inequality B

E doesn’t account for the values between 2 and -2 which also make the equation less than 0. Hence wrong since ot covers only partial scope

Hello everyone ! Here is today’s (May 9) DI Butler Question: the-graph-shows-the-estimated-number-of-users-for-3-hyper-growth-inter-444960.html#p3567394

could someone please provide explanation for CR 1, 9th may?

The last GMAT Club Tests questions left unanswered: at-a-certain-company-event-the-snack-table-offered-only-sandwiches-444472.html

A mining team made a plan to mine up to 300 m in a certain number of days. After working as per plan for 5 days, they added new members to the team and hence could mine 5 m more per day. In this way, 4 days before the planned date, they had mined 295 m. How many meters of mining was initially planned for each day? A. 30 m B. 12.5 m C. 15 m D. 7.5 m E. 2.5m in this ques : if we make the equation as >> ( 300/x + 5 )*(x-4+1) = 300 i get the answer as x = 15, so 300/15 = 20. I did + 1 because they completed 295 4 days before so for 300m , 3 days before. whats wrong..

Can you please explain the reasoning behind this?

I don’t think this is the correct equation. This is the equation (1500/x)+(300/x+5)(x-9)=295 Where x is the total number of days. See if you are able to make a sense of this equation. Solving this should give you x=20, and then 300/20 would be 15

yeah i removed that comment because of the same..

Alternate approach efficiency = *a* mt /day total *t* days a*t = 300 a*5 + (a+5)*(t-4-5)=295 a5+at -a9 +5t -45 = 295 300 -a4 +5t = 340 5t -a4 = 40___ equation putting options a = 30 ,so t = 31, 31*30=900+ # a = 12.5. t = 18. 18*12.5 = 225 # a = 15 t = 20 ___15*20=300 hence. a= 15 m/day

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