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Quick Sell Outlet sold a total of 40 televisions, each of
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14 Oct 2013, 08:51
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62% (01:31) correct 38% (01:31) wrong based on 966 sessions
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Quick Sell Outlet sold a total of 40 televisions, each of which was either a Model P television or a Model Q television. Each Model P television sold for $p and each Model Q sold for $q. The average (arithmetic mean) selling price of the 40 televisions was $141. How many of the 40 televisions were Model P televisions? 1) the Model P televisions sold for $30 less than the Model Q televisions 2) Either p=120 or q=120
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Re: Quick Sell Outlet sold a total of 40 televisions, each of
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14 Oct 2013, 09:13
Quick Sell Outlet sold a total of 40 televisions, each of which was either a Model P television or a Model Q television. Each Model P television sold for $p and each Model Q sold for $q. The average (arithmetic mean) selling price of the 40 televisions was $141. How many of the 40 televisions were Model P televisions?(average price) = (total sales)/(# of televisions sold) \(141 = \frac{px+q(40x)}{40}\), where x is the number of Model P televisions sold. (1) The Model P televisions sold for $30 less than the Model Q televisions > p=q30. Not sufficient to get x. (2) Either p=120 or q=120. Not sufficient. (1)+(2) If q=120, then p=90, so in this case both prices would be less than the average price ($141) which is not possible. Thus p=120 and q=150. When we substitute these values we'll have only one unknown x, so we can solve for it. Sufficient. Answer: C.
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Re: Quick Sell Outlet sold a total of 40 televisions, each of
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02 Dec 2014, 20:00
nice conceptual question and well explained by bunuel. 1 and 2 are clearly not sufficient. 1&2. if p = 120 then q = 90 then average cannot be 141 so its has to be p = 150 and q =120. bulletpoint wrote: Quick Sell Outlet sold a total of 40 televisions, each of which was either a Model P television or a Model Q television. Each Model P television sold for $p and each Model Q sold for $q. The average (arithmetic mean) selling price of the 40 televisions was $141. How many of the 40 televisions were Model P televisions?
1) the Model P televisions sold for $30 less than the Model Q televisions
2) Either p=120 or q=120
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Re: Quick Sell Outlet sold a total of 40 televisions, each of
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03 Jun 2015, 09:32
(1)+(2) If q=120, then p=90, so in this case both prices would be less than the average price ($141) which is not possible.
hi bunuel, i don't understand this can you pls elaborate



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Re: Quick Sell Outlet sold a total of 40 televisions, each of
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03 Jun 2015, 09:51
harDill wrote: Quick Sell Outlet sold a total of 40 televisions, each of which was either a Model P television or a Model Q television. Each Model P television sold for $p and each Model Q sold for $q. The average (arithmetic mean) selling price of the 40 televisions was $141. How many of the 40 televisions were Model P televisions?
1) the Model P televisions sold for $30 less than the Model Q televisions
2) Either p=120 or q=120
(1)+(2) If q=120, then p=90, so in this case both prices would be less than the average price ($141) which is not possible.
hi bunuel, i don't understand this can you pls elaborate You need to understand the following first, (average price) = (total sales)/(Number of televisions sold) Because Total Televisions Sold = 40 So Let, Total models of P television sold = x Then, Total models of Q television sold = 40x The Revenue earned by selling x television of type P = $p * x The Revenue earned by selling (40x) television of type Q = $q * (40x) Total Revenue Earned = Average Price per television * No. of televisions sold = $141 * (40) Hence, 141 * 40=px+q(40−x), where x is the number of Model P televisions sold. $5640 = px+q(40−x)Unknown Variable to be calculated = x = ?Statement 1: $p = $q  30i.e. $5640 = px+q(40−x) can be Rewritten as $5640 = (q30)x+q(40−x) But two unknown Variables q and x Hence, NOT SUFFICIENTStatement 2: Either p=120 or q=120@p = 120, q and x are unknown hence not sufficient @q = 120, p and x are unknown hence not sufficient Hence, NOT SUFFICIENTCombining Statement 1 and Statement 2 together:Either p=120 or q=120 AND $p = $q  30 AND $5640 = px+q(40−x) i.e. If p = 120, then q = 150 and then x = 12, A Unique value But if q = 120 then p = 90 and then x = 28 i.e. Negative Value which is IMPOSSIBLE Hence SUFFICIENTAnswer: Option
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Quick Sell Outlet sold a total of 40 televisions, each of
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16 Sep 2016, 16:37
harDill wrote: (1)+(2) If q=120, then p=90, so in this case both prices would be less than the average price ($141) which is not possible.
hi bunuel, i don't understand this can you pls elaborate If you only score 70 and 80 on tests in a class, is it possible for you to get an average test score of 90 in the class?



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Re: Quick Sell Outlet sold a total of 40 televisions, each of
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18 Nov 2017, 05:07
Bunuel wrote: Quick Sell Outlet sold a total of 40 televisions, each of which was either a Model P television or a Model Q television. Each Model P television sold for $p and each Model Q sold for $q. The average (arithmetic mean) selling price of the 40 televisions was $141. How many of the 40 televisions were Model P televisions?
(average price) = (total sales)/(# of televisions sold)
\(141 = \frac{px+q(40x)}{40}\), where x is the number of Model P televisions sold.
(1) The Model P televisions sold for $30 less than the Model Q televisions > p=q30. Not sufficient to get x.
(2) Either p=120 or q=120. Not sufficient.
(1)+(2) If q=120, then p=90, so in this case both prices would be less than the average price ($141) which is not possible. Thus p=120 and q=150. When we substitute these values we'll have only one unknown x, so we can solve for it. Sufficient.
Answer: C. HI, Even here when q=120 and p=150, the average still comes out to be less than 141. Hence how can we take this as a solution?



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Re: Quick Sell Outlet sold a total of 40 televisions, each of
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18 Nov 2017, 05:56
bulletpoint wrote: Quick Sell Outlet sold a total of 40 televisions, each of which was either a Model P television or a Model Q television. Each Model P television sold for $p and each Model Q sold for $q. The average (arithmetic mean) selling price of the 40 televisions was $141. How many of the 40 televisions were Model P televisions?
1) the Model P televisions sold for $30 less than the Model Q televisions
2) Either p=120 or q=120 Let number of P televisions be m, and Q Televisions be n. p*m + q*n/m+n = 141, m + n = 40 p*m + q*n = 5640 p = q  30 q*(m+n)  30*m = 5640. Now, when q = 120, m will be ve which is not possible. So, only p = 120, q = 150
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Re: Quick Sell Outlet sold a total of 40 televisions, each of
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18 Nov 2017, 06:11
bulletpoint wrote: Quick Sell Outlet sold a total of 40 televisions, each of which was either a Model P television or a Model Q television. Each Model P television sold for $p and each Model Q sold for $q. The average (arithmetic mean) selling price of the 40 televisions was $141. How many of the 40 televisions were Model P televisions? Average = \(\frac{{Total Sales}}{{No. of TVs sold}}\) Let No. of Model P TVs be a => Model Q TVs = (40a) We are given \(\frac{{ap + q(40a)}}{40}\) = 141 We need to find the value of a. Quote: 1) the Model P televisions sold for $30 less than the Model Q televisions
2) Either p=120 or q=120 S1) p = q30 => q(a+40)  a(30+q) = 5640 => Not enough information to find the value of a. Insufficient. S2) p = $120 or q = $120 => Clearly not enough information to find the value of a. Insufficient. Quote: Combining S1+S1 p = q30 if p = $120 then q = $150 if q = $120 then p = $90 => Not possible at the average is $141 [Ignore this case]Inputting values of p & q in \(\frac{{ap + q(40a)}}{40}\) = 141 => 120a + 150(40a)=5640 => we can find the value of a. Sufficient. The answer is C
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Re: Quick Sell Outlet sold a total of 40 televisions, each of
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18 Nov 2017, 06:20
kartzcool wrote: Bunuel wrote: Quick Sell Outlet sold a total of 40 televisions, each of which was either a Model P television or a Model Q television. Each Model P television sold for $p and each Model Q sold for $q. The average (arithmetic mean) selling price of the 40 televisions was $141. How many of the 40 televisions were Model P televisions?
(average price) = (total sales)/(# of televisions sold)
\(141 = \frac{px+q(40x)}{40}\), where x is the number of Model P televisions sold.
(1) The Model P televisions sold for $30 less than the Model Q televisions > p=q30. Not sufficient to get x.
(2) Either p=120 or q=120. Not sufficient.
(1)+(2) If q=120, then p=90, so in this case both prices would be less than the average price ($141) which is not possible. Thus p=120 and q=150. When we substitute these values we'll have only one unknown x, so we can solve for it. Sufficient.
Answer: C. HI, Even here when q=120 and p=150, the average still comes out to be less than 141. Hence how can we take this as a solution? Hi mate, You're assuming that 1 unit of both TVs was sold. if p = 120 and q = 150 then, for the average to be $141, more of model Q would need to be sold as the average is skewed towards 150. Hope this helps.
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