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### Show Tags

05 Nov 2013, 22:34
1
8
00:00

Difficulty:

45% (medium)

Question Stats:

73% (02:37) correct 27% (02:50) wrong based on 244 sessions

### HideShow timer Statistics

Roses can be purchased individually for $4.30, one dozen for$36, or two dozen for $50. What is the greatest number of roses that can be purchased for$680?

(A) 156
(B) 162
(C) 318
(D) 324
(E) 325

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Re: Roses can be purchased individually for $4.30, one dozen for [#permalink] ### Show Tags 06 Nov 2013, 01:13 2 accincognito wrote: Roses can be purchased individually for$4.30, one dozen for $36, or two dozen for$50. What is the greatest number of roses that can be purchased for $680? (A) 156 (B) 162 (C) 318 (D) 324 (E) 325 Buy as many$50 deals as possible. We can by 650/50=13 two dozen roses, thus total of 13*24 = 312 roses.

We are left with 680 - 650 = $30. We can buy 30/4.3 = ~6 roses for that amount. Total = 312 + 6 = 318. Answer: C. _________________ Manager Joined: 04 Sep 2012 Posts: 133 Re: Roses can be purchased individually for$4.30, one dozen for  [#permalink]

### Show Tags

06 Nov 2013, 01:37
1
accincognito wrote:
Roses can be purchased individually for $4.30, one dozen for$36, or two dozen for $50. What is the greatest number of roses that can be purchased for$680?

(A) 156
(B) 162
(C) 318
(D) 324
(E) 325

as max roses are bought with max profit at $50 for two dozens so 13*50 = 650$
for 650$we will have 13*24= 312 Now 4.3*6 = 25.8$< 30

so in total we will have 312 + 6 = 318 roses
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Re: Roses can be purchased individually for $4.30, one dozen for [#permalink] ### Show Tags 06 Nov 2013, 06:40$50 deals is the best. 650/50=13 two dozen roses

10*24 = 240 roses
3*24 = 72 roses

Total is 312 (close to 318) answer is assumed C
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Re: Roses can be purchased individually for $4.30, one dozen for [#permalink] ### Show Tags 08 Jan 2016, 01:11 One rose for 4.30$
12 for 36$i.e., 1 rose for 3$
24 for 50$i.e., 1 rose for 2$ approx...........cheapest price

So we need greatest number of roses, we need to buy maximum for less price i.e., we should buy them at 24 for 50$as much as we can. Given, 680$=650$(multiple of 50$) + 30$=50$(13)(multiple of 50$i.e., number of 24 rose sets for 50$) +30$(we can only buy roses individually with this price.) For 650$,
since we get 24 roses for 50$and we get total such 13 sets of roses whereas each set has 24 roses i.e., $$13*24=(10+3)24=240+72=312 roses$$ for 650$ we can buy maximum 312 roses

For 30$, at individual price of 4.3$, we can buy $$\frac{30}{4.3}$$i.e., 6 roses at maximum.

So in total the greatest number of roses we can buy for 680$is 312+6=318 roses SVP Joined: 12 Dec 2016 Posts: 1607 Location: United States GMAT 1: 700 Q49 V33 GPA: 3.64 Re: Roses can be purchased individually for$4.30, one dozen for  [#permalink]

### Show Tags

01 Mar 2018, 10:45
I can understand that C is the answer. However, I disagree with the word "for $680?". Such word is not as same as "with$680" That means we have to find the precise cost.
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Posts: 2347
Roses can be purchased individually for $4.30, one dozen for [#permalink] ### Show Tags 03 Mar 2018, 16:37 1 chesstitans wrote: I can understand that C is the answer. However, I disagree with the word "for$680?". Such word is not as same as "with $680" That means we have to find the precise cost. chesstitans , I am not sure I understand your distinction. It seems as if you are saying that the phrase "for$X" means only something such as, "I bought three dresses for $887.93." Where did your interpretation(s) come from? Can you give an example? In English, when given an amount of money, a price per item, and a question that asks us to find the number of items, "with$680" and "for $680" mean the same thing. They mean, "How many roses will$680 allow you to buy?"

$680 is the upper limit. You do not have to spend all the money, but you cannot spend more. Does that make sense, or have I misunderstood you? _________________ Never look down on anybody unless you're helping them up. --Jesse Jackson Intern Joined: 15 Oct 2016 Posts: 30 Roses can be purchased individually for$4.30, one dozen for  [#permalink]

### Show Tags

03 Mar 2018, 23:05
accincognito wrote:
Roses can be purchased individually for $4.30, one dozen for$36, or two dozen for $50. What is the greatest number of roses that can be purchased for$680?

(A) 156
(B) 162
(C) 318
(D) 324
(E) 325

Since the $50 one are the cheapest on per unit basis, we will try to buy maximum of such roses first till the point we can then move on to buy the$36 ones and so on.

[680/50] = 13 , [] stands for the greatest integer less than or equal to that number.

Since, (680-50*13)=30

Also, [30/4.3] = 6 , [] stands for the greatest integer less than or equal to that number.

So max. no. of roses that can be purchased = 13*24 + 6 =318