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Roses can be purchased individually for $4.30, one dozen for

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Roses can be purchased individually for $4.30, one dozen for  [#permalink]

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New post 05 Nov 2013, 23:34
2
10
00:00
A
B
C
D
E

Difficulty:

  45% (medium)

Question Stats:

70% (02:37) correct 30% (02:42) wrong based on 231 sessions

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Roses can be purchased individually for $4.30, one dozen for $36, or two dozen for $50. What is the greatest number of roses that can be purchased for $680?

(A) 156
(B) 162
(C) 318
(D) 324
(E) 325

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Re: Roses can be purchased individually for $4.30, one dozen for  [#permalink]

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New post 06 Nov 2013, 02:13
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accincognito wrote:
Roses can be purchased individually for $4.30, one dozen for $36, or two dozen for $50. What is the greatest number of roses that can be purchased for $680?

(A) 156
(B) 162
(C) 318
(D) 324
(E) 325


Buy as many $50 deals as possible. We can by 650/50=13 two dozen roses, thus total of 13*24 = 312 roses.

We are left with 680 - 650 = $30. We can buy 30/4.3 = ~6 roses for that amount.

Total = 312 + 6 = 318.

Answer: C.
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Re: Roses can be purchased individually for $4.30, one dozen for  [#permalink]

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New post 06 Nov 2013, 02:37
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accincognito wrote:
Roses can be purchased individually for $4.30, one dozen for $36, or two dozen for $50. What is the greatest number of roses that can be purchased for $680?

(A) 156
(B) 162
(C) 318
(D) 324
(E) 325


as max roses are bought with max profit at $50 for two dozens so 13*50 = 650 $
for 650$ we will have 13*24= 312
Now 4.3*6 = 25.8$< 30

so in total we will have 312 + 6 = 318 roses
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Re: Roses can be purchased individually for $4.30, one dozen for  [#permalink]

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New post 06 Nov 2013, 07:40
$50 deals is the best. 650/50=13 two dozen roses

10*24 = 240 roses
3*24 = 72 roses

Total is 312 (close to 318) answer is assumed C
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Re: Roses can be purchased individually for $4.30, one dozen for  [#permalink]

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New post 08 Jan 2016, 02:11
One rose for 4.30$
12 for 36$ i.e., 1 rose for 3$
24 for 50$ i.e., 1 rose for 2$ approx...........cheapest price

So we need greatest number of roses, we need to buy maximum for less price i.e., we should buy them at 24 for 50$ as much as we can.
Given,
680$=650$(multiple of 50$) + 30$
=50$(13)(multiple of 50$ i.e., number of 24 rose sets for 50$) +30$(we can only buy roses individually with this price.)

For 650$,
since we get 24 roses for 50$ and we get total such 13 sets of roses whereas each set has 24 roses i.e.,
\(13*24=(10+3)24=240+72=312 roses\)
for 650$ we can buy maximum 312 roses

For 30$,
at individual price of 4.3$, we can buy \(\frac{30}{4.3}\)i.e., 6 roses at maximum.

So in total the greatest number of roses we can buy for 680$ is 312+6=318 roses
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Re: Roses can be purchased individually for $4.30, one dozen for  [#permalink]

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New post 01 Mar 2018, 11:45
I can understand that C is the answer. However, I disagree with the word "for $680?". Such word is not as same as "with $680" That means we have to find the precise cost.
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Roses can be purchased individually for $4.30, one dozen for  [#permalink]

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New post 03 Mar 2018, 17:37
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chesstitans wrote:
I can understand that C is the answer. However, I disagree with the word "for $680?". Such word is not as same as "with $680" That means we have to find the precise cost.

chesstitans , I am not sure I understand your distinction. It seems as if you are saying that the phrase "for $X" means only something such as, "I bought three dresses for $887.93."

Where did your interpretation(s) come from? Can you give an example?

In English, when given an amount of money, a price per item, and a question that asks us to find the number of items, "with $680" and "for $680" mean the same thing. They mean, "How many roses will $680 allow you to buy?"

$680 is the upper limit. You do not have to spend all the money, but you cannot spend more.

Does that make sense, or have I misunderstood you?
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Roses can be purchased individually for $4.30, one dozen for  [#permalink]

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New post 04 Mar 2018, 00:05
accincognito wrote:
Roses can be purchased individually for $4.30, one dozen for $36, or two dozen for $50. What is the greatest number of roses that can be purchased for $680?

(A) 156
(B) 162
(C) 318
(D) 324
(E) 325


Since the $50 one are the cheapest on per unit basis, we will try to buy maximum of such roses first till the point we can then move on to buy the $36 ones and so on.

[680/50] = 13 , [] stands for the greatest integer less than or equal to that number.

Since, (680-50*13)=30

Also, [30/4.3] = 6 , [] stands for the greatest integer less than or equal to that number.

So max. no. of roses that can be purchased = 13*24 + 6 =318
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Re: Roses can be purchased individually for $4.30, one dozen for  [#permalink]

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New post 12 Aug 2019, 19:33
accincognito wrote:
Roses can be purchased individually for $4.30, one dozen for $36, or two dozen for $50. What is the greatest number of roses that can be purchased for $680?

(A) 156
(B) 162
(C) 318
(D) 324
(E) 325


Note first that the cheapest price per rose is obtained by buying a 2-dozen bouquet. Thus, we want to buy as many 2-dozen bouquets as possible.

Since 650/50 = 13, 13 x 24 = 312 roses can be purchased for 650 dollars when buying them 2 dozen at a time.

With the remaining 30 dollars, 6 more roses can be purchased, for a total of 318 roses.

Answer: C
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Re: Roses can be purchased individually for $4.30, one dozen for   [#permalink] 12 Aug 2019, 19:33
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