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Sam’s car was fined when he gave Joe and Peter a ride, so they decided
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12 Mar 2015, 05:46
Question Stats:
72% (02:39) correct 28% (02:58) wrong based on 149 sessions
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Re: Sam’s car was fined when he gave Joe and Peter a ride, so they decided
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12 Mar 2015, 10:59
Joe=1/4f+3 Peter= 1/3f3
Sam=1/2f4
We can find F=48
Thus Sam paid 244=20
Answer C



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Re: Sam’s car was fined when he gave Joe and Peter a ride, so they decided
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12 Mar 2015, 13:31
the answer is C let say the total fine=T so Joe paid 3+T/4 Peter paid T/33 sam paied T/24 T=(3+T/4)+(T/33)+(T/24) T=48 sam paied=20
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Re: Sam’s car was fined when he gave Joe and Peter a ride, so they decided
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12 Mar 2015, 15:17
Bunuel wrote: Sam’s car was fined when he gave Joe and Peter a ride, so they decided to help Sam pay the fine. Joe paid $3 more than 1/4 of the fine and Peter paid $3 less than 1/3 of the fine, leaving pay $4 less than 1/2 the fine to complete the payment. What fraction of the fine did Sam pay?
A. $13 B. $15 C. $20 D. $28 E. $48
Kudos for a correct solution. (1/4)x + 3 + (1/3)x  3 + (1/2)x 4 = x x=48 1/2(48)  4 = 20 Answer: C



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he gave Joe and Peter a ride, so they decided
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12 Mar 2015, 20:04
Answer = C. $20 Sam .......... Joe ................. Peter .................. Total \(\frac{x}{2}  4\) ......... \(\frac{x}{4} + 3\) ........... \(\frac{x}{3}  3\) ............ x (Say total fine = x) Setting up the equation with above variables \(\frac{x}{2} + \frac{x}{4} + \frac{x}{3}  x = 4\) x = 48 Sam's contribution = 244 = 20
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Re: Sam’s car was fined when he gave Joe and Peter a ride, so they decided
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15 Mar 2015, 20:38
Bunuel wrote: Sam’s car was fined when he gave Joe and Peter a ride, so they decided to help Sam pay the fine. Joe paid $3 more than 1/4 of the fine and Peter paid $3 less than 1/3 of the fine, leaving pay $4 less than 1/2 the fine to complete the payment. What fraction of the fine did Sam pay?
A. $13 B. $15 C. $20 D. $28 E. $48
Kudos for a correct solution. MAGOOSH OFFICIAL SOLUTION:Call the fine F. Joe paid (1/4)F + 3 and Peter paid (1/3)F – 3, leaving (1/2)F – 4 left. If we add those three up, they should add up to F. F = [(1/4)F + 3] + [(1/3)F – 3] + [(1/2)F – 4] F = (1/4)F + (1/3)F + (1/2)F – 4 Multiply all terms by 12 to clear the fractions. 12F = 3F + 4F + 6F – 48 12F = 13 F – 48 –F = – 48 F = 48 Well, if the fine cost $48, then Sam paid the part not covered by Joe or Peter. Half the fine is $24, and Sam paid $4 less than this: $20. Answer = (C)
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Re: Sam’s car was fined when he gave Joe and Peter a ride, so they decided
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24 Jul 2015, 10:38
Bunuel wrote: Sam’s car was fined when he gave Joe and Peter a ride, so they decided to help Sam pay the fine. Joe paid $3 more than 1/4 of the fine and Peter paid $3 less than 1/3 of the fine, leaving pay $4 less than 1/2 the fine to complete the payment. What fraction of the fine did Sam pay?
A. $13 B. $15 C. $20 D. $28 E. $48
Kudos for a correct solution. I did the same way as most of the people have done. I have also solved in the following way, a little bit reverse thing, please let me know if I am doing wrong here. As given sam' payment is [1][/2]*Fine 4 i.e Total Fine = 2 * (Sam's payment + 4) Now, as everything looks integer, Fine should be able to divide by 4 and 3 . Because Joe's contribution has 1/4 of the fine and Peter's contribution has 1/3 of the fine So, that leads me to following : Options , Sam's pay , Total Fine (F) , F/4 , F/3 A) , 13 , 34 , No i.e 34/4 , No i.e 34/3 B) , 14 , 38 , No , No C) , 20 , 48 , Yes Yes , No need to further go on as we have got F/4 and F/3 correct, just for confirmation we go further D) , 28 , 64 , Yes , No E) , 48 , 104 , Yes , No So we can see the Option C has the correct values



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Re: Sam's car was fined for parking when he gave Joe and Peter a ride
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06 Jun 2017, 22:32
mkrishnabdrr wrote: Sam's car was fined for parking when he gave Joe and Peter a ride, so they decided to help Sam pay the fine. Joe paid $3 more than 1/4 of the fine and Peter paid $3 less than 1/3 of the fine, leaving Sam $4 less than 1/2 the fine to complete the payment. How much did Sam pay? A. 48 B. 24 C. 20 D. 15 E. 50 Let the fine be \(x\) Joe paid = \(\frac{1}{4}x\) + 3
Peter paid = \(\frac{1}{3}x\)  3
Sam has to pay = \(\frac{1}{2}x\)  4
From the question; \(x = \frac{1}{4}x + 3 + \frac{1}{3}x  3 + \frac{1}{2}x  4\)
\(x = \frac{1}{4}x + \frac{1}{3}x + \frac{1}{2}x  4\)
\(x = \frac{3x + 4x + 6x}{12}  4\) = \(\frac{13x}{12}  4\)
\(\frac{13x}{12}  x = 4\)
\(\frac{13x  12x}{12}\) = \(\frac{x}{12} = 4\)
\(x = 12 * 4 = 48\) . Answer A... _________________ Kindly press "+1 Kudos" to appreciate



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Sam’s car was fined when he gave Joe and Peter a ride, so they decided
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07 Jun 2017, 06:16
sashiim20 wrote: mkrishnabdrr wrote: Sam's car was fined for parking when he gave Joe and Peter a ride, so they decided to help Sam pay the fine. Joe paid $3 more than 1/4 of the fine and Peter paid $3 less than 1/3 of the fine, leaving Sam $4 less than 1/2 the fine to complete the payment. How much did Sam pay? A. 48 B. 24 C. 20 D. 15 E. 50 Let the fine be \(x\) Joe paid = \(\frac{1}{4}x\) + 3
Peter paid = \(\frac{1}{3}x\)  3
Sam has to pay = \(\frac{1}{2}x\)  4
From the question; \(x = \frac{1}{4}x + 3 + \frac{1}{3}x  3 + \frac{1}{2}x  4\)
\(x = \frac{1}{4}x + \frac{1}{3}x + \frac{1}{2}x  4\)
\(x = \frac{3x + 4x + 6x}{12}  4\) = \(\frac{13x}{12}  4\)
\(\frac{13x}{12}  x = 4\)
\(\frac{13x  12x}{12}\) = \(\frac{x}{12} = 4\)
\(x = 12 * 4 = 48\) . Answer A... Question stem asks for how much did sam pay: So, Sam has to pay = \(\frac{1}{2}x\)  4 =1/2 x 48 4 =244 =20 Hence, Ans is C. You found out the fine. _________________ Kindly press "+1 Kudos" to appreciate
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Re: Sam’s car was fined when he gave Joe and Peter a ride, so they decided
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10 Jun 2017, 06:33
Bunuel wrote: Sam’s car was fined when he gave Joe and Peter a ride, so they decided to help Sam pay the fine. Joe paid $3 more than 1/4 of the fine and Peter paid $3 less than 1/3 of the fine, leaving pay $4 less than 1/2 the fine to complete the payment. What fraction of the fine did Sam pay?
A. $13 B. $15 C. $20 D. $28 E. $48 We can let t = the total amount of the fine. Joe’s payment = 3 + (1/4)t Peter’s payment = (1/3)t  3 Sam’s payment = (1/2)t  4 We can create the following equation to determine t: 3 + (1/4)t + (1/3)t  3 + (1/2)t  4 = t (1/4)t + (1/3)t + (1/2)t  4 = t Multiplying by 12, we have: 3t + 4t + 6t  48 = 12t 48 = t Thus, Sam paid (1/2)(48)  4 = 24  4 = $20. Answer: C
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Re: Sam’s car was fined when he gave Joe and Peter a ride, so they decided
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10 Jun 2017, 14:52
[quote="Bunuel"]Sam’s car was fined when he gave Joe and Peter a ride, so they decided to help Sam pay the fine. Joe paid $3 more than 1/4 of the fine and Peter paid $3 less than 1/3 of the fine, leaving pay $4 less than 1/2 the fine to complete the payment. What fraction of the fine did Sam pay?
A. $13 B. $15 C. $20 D. $28 E. $48/quote]
let f=amount of fine 13/12*f4=f f=$48 Sam's share=f/24=$20 C



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Re: Sam’s car was fined when he gave Joe and Peter a ride, so they decided
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23 Sep 2017, 02:45
Bunuel wrote: Bunuel wrote: Sam’s car was fined when he gave Joe and Peter a ride, so they decided to help Sam pay the fine. Joe paid $3 more than 1/4 of the fine and Peter paid $3 less than 1/3 of the fine, leaving pay $4 less than 1/2 the fine to complete the payment. What fraction of the fine did Sam pay?
A. $13 B. $15 C. $20 D. $28 E. $48
Kudos for a correct solution. MAGOOSH OFFICIAL SOLUTION:Call the fine F. Joe paid (1/4)F + 3 and Peter paid (1/3)F – 3, leaving (1/2)F – 4 left. If we add those three up, they should add up to F. F = [(1/4)F + 3] + [(1/3)F – 3] + [(1/2)F – 4] F = (1/4)F + (1/3)F + (1/2)F – 4 Multiply all terms by 12 to clear the fractions. 12F = 3F + 4F + 6F – 48 12F = 13 F – 48 –F = – 48 F = 48 Well, if the fine cost $48, then Sam paid the part not covered by Joe or Peter. Half the fine is $24, and Sam paid $4 less than this: $20. Answer = (C) Hi, I don't understand. Doesn't the question say what 'fraction' of the fine did sam say? Here, we're stating his share of the fine.
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Re: Sam’s car was fined when he gave Joe and Peter a ride, so they decided &nbs
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