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Scott takes a trip and drives 6 hours from Town X to Town Z at a rate

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Scott takes a trip and drives 6 hours from Town X to Town Z at a rate  [#permalink]

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New post 20 Mar 2016, 23:51
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

94% (01:02) correct 6% (01:50) wrong based on 156 sessions

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Scott takes a trip and drives 6 hours from Town X to Town Z at a rate of 50 miles per hour. On his way back, Scott drives 75 miles per hour and stops in Town Y which is midway between Town X and Town Z. How many hours does it take Scott to drive from Town Z to Town Y?

A. 1.0
B. 1.25
C. 1.5
D. 1.75
E. 2.0

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Re: Scott takes a trip and drives 6 hours from Town X to Town Z at a rate  [#permalink]

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New post 21 Mar 2016, 00:40
distance from X to Z =6 hr* 50 mph= 300 miles
hence distance from Y to Z= 1/2*300=150
time=150/75=2 hr

IMO: E
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Re: Scott takes a trip and drives 6 hours from Town X to Town Z at a rate  [#permalink]

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New post 21 Mar 2016, 00:42
distance from X to Z =6 hr* 50 mph= 300 miles
hence distance from Y to Z= 1/2*300=150
time=150/75=2 hr

IMO: E

m i missing something? this que seems pretty straight forward. :roll:
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Re: Scott takes a trip and drives 6 hours from Town X to Town Z at a rate  [#permalink]

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New post 22 Mar 2016, 08:46
You can solve the question by referring to the distance/speed/time tabular which helps you visualize the problem.

1) Assign a variable for any unknown quantity (Try to express quantities in terms of other quantities already present, such as x and 0.5*x for the distance)
2) Solve for the required variable t



\(x=6*50=300 miles\)

\(0.5*300=75*t\)

\(t=2 hours\)

--> Answer should be E)
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Re: Scott takes a trip and drives 6 hours from Town X to Town Z at a rate  [#permalink]

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New post 23 Jun 2017, 16:23

Simple approach


D=RxT
D=50x6
D=300 miles
X--------Z
<--300-->

Y is the mid point, i.e at the 150th mile.
At R=75, you will reach the 150th mile in, 150/75 = 2 hrs

Hence it will take 2 more hrs to reach Z which is another 150 miles away.
Answer is E
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Re: Scott takes a trip and drives 6 hours from Town X to Town Z at a rate  [#permalink]

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New post 13 Aug 2017, 13:14
Bunuel wrote:
Scott takes a trip and drives 6 hours from Town X to Town Z at a rate of 50 miles per hour. On his way back, Scott drives 75 miles per hour and stops in Town Y which is midway between Town X and Town Z. How many hours does it take Scott to drive from Town Z to Town Y?

A. 1.0
B. 1.25
C. 1.5
D. 1.75
E. 2.0


This is simply a round trip question

The distance between X and Z obviously

Distance= rate * time
Distance= 50mph * 6hr
300=

75/150 = 2

E
Re: Scott takes a trip and drives 6 hours from Town X to Town Z at a rate &nbs [#permalink] 13 Aug 2017, 13:14
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