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# Scott takes a trip and drives 6 hours from Town X to Town Z at a rate

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Math Expert
Joined: 02 Sep 2009
Posts: 60727
Scott takes a trip and drives 6 hours from Town X to Town Z at a rate  [#permalink]

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20 Mar 2016, 23:51
00:00

Difficulty:

5% (low)

Question Stats:

96% (01:19) correct 4% (02:03) wrong based on 273 sessions

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Scott takes a trip and drives 6 hours from Town X to Town Z at a rate of 50 miles per hour. On his way back, Scott drives 75 miles per hour and stops in Town Y which is midway between Town X and Town Z. How many hours does it take Scott to drive from Town Z to Town Y?

A. 1.0
B. 1.25
C. 1.5
D. 1.75
E. 2.0

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Re: Scott takes a trip and drives 6 hours from Town X to Town Z at a rate  [#permalink]

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21 Mar 2016, 00:40
1
distance from X to Z =6 hr* 50 mph= 300 miles
hence distance from Y to Z= 1/2*300=150
time=150/75=2 hr

IMO: E
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Re: Scott takes a trip and drives 6 hours from Town X to Town Z at a rate  [#permalink]

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21 Mar 2016, 00:42
distance from X to Z =6 hr* 50 mph= 300 miles
hence distance from Y to Z= 1/2*300=150
time=150/75=2 hr

IMO: E

m i missing something? this que seems pretty straight forward.
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Re: Scott takes a trip and drives 6 hours from Town X to Town Z at a rate  [#permalink]

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22 Mar 2016, 08:46
1
You can solve the question by referring to the distance/speed/time tabular which helps you visualize the problem.

1) Assign a variable for any unknown quantity (Try to express quantities in terms of other quantities already present, such as x and 0.5*x for the distance)
2) Solve for the required variable t

$$x=6*50=300 miles$$

$$0.5*300=75*t$$

$$t=2 hours$$

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Re: Scott takes a trip and drives 6 hours from Town X to Town Z at a rate  [#permalink]

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23 Jun 2017, 16:23

Simple approach

D=RxT
D=50x6
D=300 miles
X--------Z
<--300-->

Y is the mid point, i.e at the 150th mile.
At R=75, you will reach the 150th mile in, 150/75 = 2 hrs

Hence it will take 2 more hrs to reach Z which is another 150 miles away.
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Re: Scott takes a trip and drives 6 hours from Town X to Town Z at a rate  [#permalink]

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13 Aug 2017, 13:14
Bunuel wrote:
Scott takes a trip and drives 6 hours from Town X to Town Z at a rate of 50 miles per hour. On his way back, Scott drives 75 miles per hour and stops in Town Y which is midway between Town X and Town Z. How many hours does it take Scott to drive from Town Z to Town Y?

A. 1.0
B. 1.25
C. 1.5
D. 1.75
E. 2.0

This is simply a round trip question

The distance between X and Z obviously

Distance= rate * time
Distance= 50mph * 6hr
300=

75/150 = 2

E
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Re: Scott takes a trip and drives 6 hours from Town X to Town Z at a rate  [#permalink]

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29 Dec 2018, 13:04
Hi All,

We're told that Scott takes a trip and drives 6 hours from Town X to Town Z at a rate of 50 miles per hour. On his way back, Scott drives 75 miles per hour and stops in Town Y which is MIDWAY between Town X and Town Z. We're asked for the number of HOURS Scott takes to drive from Town Z to Town Y. This question is a multi-step 'rate' question; the individual steps aren't too difficult, so you just have to do the necessary work on your pad and keep track of your data.

To start, Scott drives 6 hours at 50 miles/hour... so he traveled (6)(50) = 300 miles
He then drives back at 75 miles/hour... so the trip back would take 300/75 = 4 hours
On the way back, he stops MIDWAY through, so he stops after 150 miles and 2 hours.
The rest of the trip will be the remaining 150 miles and 2 hours.

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Scott takes a trip and drives 6 hours from Town X to Town Z at a rate  [#permalink]

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08 Dec 2019, 23:55
Bunuel wrote:
Scott takes a trip and drives 6 hours from Town X to Town Z at a rate of 50 miles per hour. On his way back, Scott drives 75 miles per hour and stops in Town Y which is midway between Town X and Town Z. How many hours does it take Scott to drive from Town Z to Town Y?

A. 1.0
B. 1.25
C. 1.5
D. 1.75
E. 2.0

The distance between X and Z =50mph * 6hr = 300 Miles

Distance= rate * time
Distance= 50mph * 6hr
300

On his return, he stops in a town which is halfway ie @150 Kms so New D =150 and Speed = 75 Miles per hour so Time is ?

150/75 = 2

E
Scott takes a trip and drives 6 hours from Town X to Town Z at a rate   [#permalink] 08 Dec 2019, 23:55
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