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Scott takes a trip and drives 6 hours from Town X to Town Z at a rate

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Math Expert
Joined: 02 Sep 2009
Posts: 51243
Scott takes a trip and drives 6 hours from Town X to Town Z at a rate  [#permalink]

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20 Mar 2016, 22:51
00:00

Difficulty:

5% (low)

Question Stats:

96% (01:20) correct 4% (02:03) wrong based on 207 sessions

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Scott takes a trip and drives 6 hours from Town X to Town Z at a rate of 50 miles per hour. On his way back, Scott drives 75 miles per hour and stops in Town Y which is midway between Town X and Town Z. How many hours does it take Scott to drive from Town Z to Town Y?

A. 1.0
B. 1.25
C. 1.5
D. 1.75
E. 2.0

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Re: Scott takes a trip and drives 6 hours from Town X to Town Z at a rate  [#permalink]

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20 Mar 2016, 23:40
distance from X to Z =6 hr* 50 mph= 300 miles
hence distance from Y to Z= 1/2*300=150
time=150/75=2 hr

IMO: E
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Re: Scott takes a trip and drives 6 hours from Town X to Town Z at a rate  [#permalink]

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20 Mar 2016, 23:42
distance from X to Z =6 hr* 50 mph= 300 miles
hence distance from Y to Z= 1/2*300=150
time=150/75=2 hr

IMO: E

m i missing something? this que seems pretty straight forward.
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Joined: 17 Mar 2016
Posts: 3
Re: Scott takes a trip and drives 6 hours from Town X to Town Z at a rate  [#permalink]

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22 Mar 2016, 07:46
1
You can solve the question by referring to the distance/speed/time tabular which helps you visualize the problem.

1) Assign a variable for any unknown quantity (Try to express quantities in terms of other quantities already present, such as x and 0.5*x for the distance)
2) Solve for the required variable t

$$x=6*50=300 miles$$

$$0.5*300=75*t$$

$$t=2 hours$$

--> Answer should be E)
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Re: Scott takes a trip and drives 6 hours from Town X to Town Z at a rate  [#permalink]

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23 Jun 2017, 15:23

Simple approach

D=RxT
D=50x6
D=300 miles
X--------Z
<--300-->

Y is the mid point, i.e at the 150th mile.
At R=75, you will reach the 150th mile in, 150/75 = 2 hrs

Hence it will take 2 more hrs to reach Z which is another 150 miles away.
Answer is E
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Re: Scott takes a trip and drives 6 hours from Town X to Town Z at a rate  [#permalink]

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13 Aug 2017, 12:14
Bunuel wrote:
Scott takes a trip and drives 6 hours from Town X to Town Z at a rate of 50 miles per hour. On his way back, Scott drives 75 miles per hour and stops in Town Y which is midway between Town X and Town Z. How many hours does it take Scott to drive from Town Z to Town Y?

A. 1.0
B. 1.25
C. 1.5
D. 1.75
E. 2.0

This is simply a round trip question

The distance between X and Z obviously

Distance= rate * time
Distance= 50mph * 6hr
300=

75/150 = 2

E
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Posts: 9196
Re: Scott takes a trip and drives 6 hours from Town X to Town Z at a rate  [#permalink]

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22 Aug 2018, 02:19
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: Scott takes a trip and drives 6 hours from Town X to Town Z at a rate &nbs [#permalink] 22 Aug 2018, 02:19
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Scott takes a trip and drives 6 hours from Town X to Town Z at a rate

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