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Scott takes a trip and drives 6 hours from Town X to Town Z at a rate

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Scott takes a trip and drives 6 hours from Town X to Town Z at a rate  [#permalink]

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New post 20 Mar 2016, 23:51
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Scott takes a trip and drives 6 hours from Town X to Town Z at a rate of 50 miles per hour. On his way back, Scott drives 75 miles per hour and stops in Town Y which is midway between Town X and Town Z. How many hours does it take Scott to drive from Town Z to Town Y?

A. 1.0
B. 1.25
C. 1.5
D. 1.75
E. 2.0

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Re: Scott takes a trip and drives 6 hours from Town X to Town Z at a rate  [#permalink]

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New post 21 Mar 2016, 00:40
1
distance from X to Z =6 hr* 50 mph= 300 miles
hence distance from Y to Z= 1/2*300=150
time=150/75=2 hr

IMO: E
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Re: Scott takes a trip and drives 6 hours from Town X to Town Z at a rate  [#permalink]

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New post 21 Mar 2016, 00:42
distance from X to Z =6 hr* 50 mph= 300 miles
hence distance from Y to Z= 1/2*300=150
time=150/75=2 hr

IMO: E

m i missing something? this que seems pretty straight forward. :roll:
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Re: Scott takes a trip and drives 6 hours from Town X to Town Z at a rate  [#permalink]

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New post 22 Mar 2016, 08:46
1
You can solve the question by referring to the distance/speed/time tabular which helps you visualize the problem.

1) Assign a variable for any unknown quantity (Try to express quantities in terms of other quantities already present, such as x and 0.5*x for the distance)
2) Solve for the required variable t



\(x=6*50=300 miles\)

\(0.5*300=75*t\)

\(t=2 hours\)

--> Answer should be E)
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Re: Scott takes a trip and drives 6 hours from Town X to Town Z at a rate  [#permalink]

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New post 23 Jun 2017, 16:23

Simple approach


D=RxT
D=50x6
D=300 miles
X--------Z
<--300-->

Y is the mid point, i.e at the 150th mile.
At R=75, you will reach the 150th mile in, 150/75 = 2 hrs

Hence it will take 2 more hrs to reach Z which is another 150 miles away.
Answer is E
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Re: Scott takes a trip and drives 6 hours from Town X to Town Z at a rate  [#permalink]

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New post 13 Aug 2017, 13:14
Bunuel wrote:
Scott takes a trip and drives 6 hours from Town X to Town Z at a rate of 50 miles per hour. On his way back, Scott drives 75 miles per hour and stops in Town Y which is midway between Town X and Town Z. How many hours does it take Scott to drive from Town Z to Town Y?

A. 1.0
B. 1.25
C. 1.5
D. 1.75
E. 2.0


This is simply a round trip question

The distance between X and Z obviously

Distance= rate * time
Distance= 50mph * 6hr
300=

75/150 = 2

E
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Re: Scott takes a trip and drives 6 hours from Town X to Town Z at a rate  [#permalink]

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New post 29 Dec 2018, 13:04
Hi All,

We're told that Scott takes a trip and drives 6 hours from Town X to Town Z at a rate of 50 miles per hour. On his way back, Scott drives 75 miles per hour and stops in Town Y which is MIDWAY between Town X and Town Z. We're asked for the number of HOURS Scott takes to drive from Town Z to Town Y. This question is a multi-step 'rate' question; the individual steps aren't too difficult, so you just have to do the necessary work on your pad and keep track of your data.

To start, Scott drives 6 hours at 50 miles/hour... so he traveled (6)(50) = 300 miles
He then drives back at 75 miles/hour... so the trip back would take 300/75 = 4 hours
On the way back, he stops MIDWAY through, so he stops after 150 miles and 2 hours.
The rest of the trip will be the remaining 150 miles and 2 hours.

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Scott takes a trip and drives 6 hours from Town X to Town Z at a rate  [#permalink]

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New post 08 Dec 2019, 23:55
Bunuel wrote:
Scott takes a trip and drives 6 hours from Town X to Town Z at a rate of 50 miles per hour. On his way back, Scott drives 75 miles per hour and stops in Town Y which is midway between Town X and Town Z. How many hours does it take Scott to drive from Town Z to Town Y?

A. 1.0
B. 1.25
C. 1.5
D. 1.75
E. 2.0


The distance between X and Z =50mph * 6hr = 300 Miles

Distance= rate * time
Distance= 50mph * 6hr
300

On his return, he stops in a town which is halfway ie @150 Kms so New D =150 and Speed = 75 Miles per hour so Time is ?


150/75 = 2

E
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Scott takes a trip and drives 6 hours from Town X to Town Z at a rate   [#permalink] 08 Dec 2019, 23:55
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