January 26, 2019 January 26, 2019 07:00 AM PST 09:00 AM PST Attend this webinar to learn how to leverage Meaning and Logic to solve the most challenging Sentence Correction Questions. January 27, 2019 January 27, 2019 07:00 AM PST 09:00 AM PST Attend this webinar to learn a structured approach to solve 700+ Number Properties question in less than 2 minutes.
Author 
Message 
TAGS:

Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 52431

Set S consists of all the positive multiples of 5 that are less than K
[#permalink]
Show Tags
18 Mar 2015, 04:12
Question Stats:
53% (02:40) correct 47% (02:49) wrong based on 272 sessions
HideShow timer Statistics




Math Expert
Joined: 02 Sep 2009
Posts: 52431

Re: Set S consists of all the positive multiples of 5 that are less than K
[#permalink]
Show Tags
23 Mar 2015, 05:24
Bunuel wrote: Set S consists of all the positive multiples of 5 that are less than K, and K is a positive integer not divisible by 5. The mean of Set S is not divisible by 5. Let N be the number of members of the set. N is not divisible by 5. What does N equal?
(1) N < 52 (2) K/5 > 48
Kudos for a correct solution. MAGOOSH OFFICIAL SOLUTION:This is a tricky problem, because there are several constraints in the problem. first of all, the number of members is N, so the numbers in the set go from 5 to 5N. The integer K has the quality that 5N < K < (5N + 5), because K is bigger than the biggest member of the set, but 5N has to be the largest multiple of 5 less than K. We know that the mean of the set is not divisible by 5, and this is important. For an evenly spaced set, the mean & median are identical. If there were an odd number of members, the mean & median would simply be the middle number on the list, and this of course would be some multiple of 5. The fact that mean & median is not divisible by 5 necessarily means that there must be an even number of members on the list. This way, the mean & median would be the average of the middle two numbers, which would be a noninteger, certainly not an integer divisible by 5. Therefore, N is an even number. Finally, we are also told that N itself is not divisible by 5—an odd constraint that may be relevant. Statement #1: Here, N could be any even number less than 52, as long as it’s not divisible by 5. It could be {48, 46, 44, 42, 38, ….} Multiple possibilities. This statement, alone and by itself, is not sufficient. Statement #2: The statement tells us that K > 5*48, so it could be that N = 48, so that K would be between 5(48) and 5*(49). That’s a possibility, or N could be any larger even number that is not divisible by 5. N could be {48, 52, 54, 56, 68, 62, …} Again, multiple possibilities. This statement, alone and by itself, is not sufficient. Combined statements: with both constraints, the only possible value if N = 48. The statements together are sufficient. Answer = (C)
_________________
New to the Math Forum? Please read this: Ultimate GMAT Quantitative Megathread  All You Need for Quant  PLEASE READ AND FOLLOW: 12 Rules for Posting!!! Resources: GMAT Math Book  Triangles  Polygons  Coordinate Geometry  Factorials  Circles  Number Theory  Remainders; 8. Overlapping Sets  PDF of Math Book; 10. Remainders  GMAT Prep Software Analysis  SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS)  Tricky questions from previous years.
Collection of Questions: PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.
What are GMAT Club Tests? Extrahard Quant Tests with Brilliant Analytics




Intern
Joined: 08 Sep 2014
Posts: 17

Set S consists of all the positive multiples of 5 that are less than K
[#permalink]
Show Tags
18 Mar 2015, 13:25
From the problem statement,
5n < k < 5n+5 n < k/5 < n+1 (k/5)  1 < n <k/5
Since, mean of S is not divisible by 5, n has to be even. and since n is not divisible by 5, therefore it is not a multiple of 10.
(1) n < 52 This is clearly INSUFFICIENT since n can be any even no. < 52 as long as it's not a multiple of 10
(2) k/5 > 48 => k/51 > 47 => n > 47 This is INSUFFICIENT as well since n could take any even value > 47 as long as it is not a multiple of 10.
From (1) , (2)
47 < n < 52
So the only possible value of n can be 48. Hence, both together are SUFFICIENT.
Answer is C.



Intern
Joined: 22 Sep 2016
Posts: 15

Re: Set S consists of all the positive multiples of 5 that are less than K
[#permalink]
Show Tags
15 Jan 2017, 21:24
I don't understand why n>47. Why can't be N any even number less than 48? N could be also 40 or 32, why would it be wrong?



Intern
Joined: 07 Jul 2017
Posts: 4

Re: Set S consists of all the positive multiples of 5 that are less than K
[#permalink]
Show Tags
07 Aug 2017, 22:48
[quote="Bunuel"]Set S consists of all the positive multiples of 5 that are less than K, and K is a positive integer not divisible by 5. The mean of Set S is not divisible by 5. Let N be the number of members of the set. N is not divisible by 5. What does N equal?
(1) N < 52 (2) K/5 > 48
5N < K < (5N + 5) I didnt understand how you got this equation



Senior Manager
Joined: 06 Jul 2016
Posts: 367
Location: Singapore
Concentration: Strategy, Finance

Re: Set S consists of all the positive multiples of 5 that are less than K
[#permalink]
Show Tags
09 Aug 2017, 02:15
machiavelli wrote: Bunuel wrote: Set S consists of all the positive multiples of 5 that are less than K, and K is a positive integer not divisible by 5. The mean of Set S is not divisible by 5. Let N be the number of members of the set. N is not divisible by 5. What does N equal?
(1) N < 52 (2) K/5 > 48
5N < K < (5N + 5) I didnt understand how you got this equation Set S has N terms in it, and K is the highest term, which is not a multiple of 5. Set S = {5,10,15,.............,5N,K} => 5N is the highest multiple of 5 in the Set, and K is greater than 5N as per the constraints in the question => K > 5N Since K has to be the largest term in the set, and 5N has to the largest multiple of 5 in the set, we can write the equation as 5N + 5 > K > 5NE.g. S = {5,10,15,20,21} Here K = 21 5N = 20 (The largest multiple of 5 in the set) => N = 4 (# of Multiples of 5)Does this help?
_________________
Put in the work, and that dream score is yours!



Intern
Joined: 28 Jun 2017
Posts: 7

Re: Set S consists of all the positive multiples of 5 that are less than K
[#permalink]
Show Tags
20 Feb 2018, 16:14
akshayk wrote: machiavelli wrote: Bunuel wrote: Set S consists of all the positive multiples of 5 that are less than K, and K is a positive integer not divisible by 5. The mean of Set S is not divisible by 5. Let N be the number of members of the set. N is not divisible by 5. What does N equal?
(1) N < 52 (2) K/5 > 48
5N < K < (5N + 5) I didnt understand how you got this equation Set S has N terms in it, and K is the highest term, which is not a multiple of 5. Set S = {5,10,15,.............,5N,K} => 5N is the highest multiple of 5 in the Set, and K is greater than 5N as per the constraints in the question => K > 5N Since K has to be the largest term in the set, and 5N has to the largest multiple of 5 in the set, we can write the equation as 5N + 5 > K > 5NE.g. S = {5,10,15,20,21} Here K = 21 5N = 20 (The largest multiple of 5 in the set) => N = 4 (# of Multiples of 5)Does this help? The question does not say that K is one of the terms of set S. It clearly says that S consist of all positive multiples of 5, which are less than K. In your example above, S will be S={5,10,15,20} and K will be 21, separate from the set. I get the point that K/5>48, so K>5x48, so there should be at least 49 terms in K, greater than 48. But I don't understand why official answer says K could equal to at least 48, there is NO >= sign!



DS Forum Moderator
Joined: 21 Aug 2013
Posts: 1435
Location: India

Set S consists of all the positive multiples of 5 that are less than K
[#permalink]
Show Tags
20 Feb 2018, 21:48
Set S has N terms in it, and K is the highest term, which is not a multiple of 5.
Set S = {5,10,15,.............,5N,K} => 5N is the highest multiple of 5 in the Set, and K is greater than 5N as per the constraints in the question => K > 5N Since K has to be the largest term in the set, and 5N has to the largest multiple of 5 in the set, we can write the equation as 5N + 5 > K > 5N
E.g. S = {5,10,15,20,21} Here K = 21 5N = 20 (The largest multiple of 5 in the set) => N = 4 (# of Multiples of 5)
Does this help?[/quote]
The question does not say that K is one of the terms of set S. It clearly says that S consist of all positive multiples of 5, which are less than K. In your example above, S will be S={5,10,15,20} and K will be 21, separate from the set. I get the point that K/5>48, so K>5x48, so there should be at least 49 terms in K, greater than 48. But I don't understand why official answer says K could equal to at least 48, there is NO >= sign![/quote]
Hi
The official answer does not say that K is equal to at least 48, it rather says that 'N' is equal to at least 48. If K > 5*48, it means the positive multiples of 5 in K are at least 48 (starting from 5*1, 5*2, 5*3,..... to ... 5*48 at least).
And i agree with your first point, the example which was taken b{5, 10, 15, 20, 21} should not involve 21.. It should be {5, 10, 15, 20} and K=21 has to be separate from this set.



Intern
Joined: 28 Jun 2017
Posts: 7

Re: Set S consists of all the positive multiples of 5 that are less than K
[#permalink]
Show Tags
20 Feb 2018, 22:01
nevermind. I finally understood this! Let me try to explain it
Set S consists of all the positive multiples of 5 that are less than K, and K is a positive integer not divisible by 5. The mean of Set S is not divisible by 5. Let N be the number of members of the set. N is not divisible by 5. What does N equal?
(1) N < 52 (2) K/5 > 48
so set S could look like {5,10,15,20,25,.....5*N} where N is the total number of elements in the set S. We can also write this set as {5*1, 5*2, 5*3, 5*4, 5*5,.....5*N}. We have given that the last number which is 5*N is less than K. So we can write that K>5*N. So for example, if our set consists of only 4 numbers, i.e, {5,10,15,20} the K could be any number greater than 20 and not a multiple of 5 (or divisible by 5). Another thing to notice here is that mean of set S is not divisible by 5. Since its a set of all numbers that are at a constant distance of 5, the mean could be the middle number if a total number of elements are odd. For example, if the set has 3 terms, {5,10,15} the mean could be middle number 10. So if the set S is not divisible by 5, it means it must have even number of terms. So N is even.
So far we got N is even K>5*N We have to find the value of N?
Statement 1) N<52, so N could be any even number less than 52. NOT SUFFICIENT
Statement 2) K/5 > 48 or we can write: K > 5*48 Since we know that K>5*N and from above we get K>5*48, this suggests that N could 48 or any even number greater than 48, not divisible by 5. So N could be 48, 52, 54 etc. NOT SUFFICIENT
Taking 1) and 2) together,
From one we get N<52 and from statement 2, we get N could be 48 or higher so possible values of N could be 48, 49, 50, 51, but since N has to be even and not divisible by 5, the only value we are left with is 48. Thus answer (C).



Director
Joined: 31 Jul 2017
Posts: 518
Location: Malaysia
GPA: 3.95
WE: Consulting (Energy and Utilities)

Set S consists of all the positive multiples of 5 that are less than K
[#permalink]
Show Tags
20 Feb 2018, 22:03
amanvermagmat wrote: Set S has N terms in it, and K is the highest term, which is not a multiple of 5.
Set S = {5,10,15,.............,5N,K} => 5N is the highest multiple of 5 in the Set, and K is greater than 5N as per the constraints in the question => K > 5N Since K has to be the largest term in the set, and 5N has to the largest multiple of 5 in the set, we can write the equation as 5N + 5 > K > 5N
E.g. S = {5,10,15,20,21} Here K = 21 5N = 20 (The largest multiple of 5 in the set) => N = 4 (# of Multiples of 5)
Does this help? The question does not say that K is one of the terms of set S. It clearly says that S consist of all positive multiples of 5, which are less than K. In your example above, S will be S={5,10,15,20} and K will be 21, separate from the set. I get the point that K/5>48, so K>5x48, so there should be at least 49 terms in K, greater than 48. But I don't understand why official answer says K could equal to at least 48, there is NO >= sign![/quote] Hi The official answer does not say that K is equal to at least 48, it rather says that 'N' is equal to at least 48. If K > 5*48, it means the positive multiples of 5 in K are at least 48 (starting from 5*1, 5*2, 5*3,..... to ... 5*48 at least). And i agree with your first point, the example which was taken b{5, 10, 15, 20, 21} should not involve 21.. It should be {5, 10, 15, 20} and K=21 has to be separate from this set.[/quote] Hi amanvermagmatCan you please help me to clear my doubt. Let \(S = {5,10,......., 5n}\) \(5n < K\) As per question, Mean is not divisible by 5. May I know how is it possible? Sum of the Set S = \(\frac{n(5+5n)}{2} = \frac{5n(n+1)}{2}\) Mean = \(\frac{5(n+1)}{2}\)... So irrespective of n, mean is always divisible by 5.Am I Missing anything here?
_________________
If my Post helps you in Gaining Knowledge, Help me with KUDOS.. !!



DS Forum Moderator
Joined: 21 Aug 2013
Posts: 1435
Location: India

Set S consists of all the positive multiples of 5 that are less than K
[#permalink]
Show Tags
20 Feb 2018, 22:28
rahul16singh28 wrote: amanvermagmat wrote: Set S has N terms in it, and K is the highest term, which is not a multiple of 5.
Set S = {5,10,15,.............,5N,K} => 5N is the highest multiple of 5 in the Set, and K is greater than 5N as per the constraints in the question => K > 5N Since K has to be the largest term in the set, and 5N has to the largest multiple of 5 in the set, we can write the equation as 5N + 5 > K > 5N
E.g. S = {5,10,15,20,21} Here K = 21 5N = 20 (The largest multiple of 5 in the set) => N = 4 (# of Multiples of 5)
Does this help? The question does not say that K is one of the terms of set S. It clearly says that S consist of all positive multiples of 5, which are less than K. In your example above, S will be S={5,10,15,20} and K will be 21, separate from the set. I get the point that K/5>48, so K>5x48, so there should be at least 49 terms in K, greater than 48. But I don't understand why official answer says K could equal to at least 48, there is NO >= sign! Hi The official answer does not say that K is equal to at least 48, it rather says that 'N' is equal to at least 48. If K > 5*48, it means the positive multiples of 5 in K are at least 48 (starting from 5*1, 5*2, 5*3,..... to ... 5*48 at least). And i agree with your first point, the example which was taken b{5, 10, 15, 20, 21} should not involve 21.. It should be {5, 10, 15, 20} and K=21 has to be separate from this set.[/quote] Hi amanvermagmatCan you please help me to clear my doubt. Let \(S = {5,10,......., 5n}\) \(5n < K\) As per question, Mean is not divisible by 5. May I know how is it possible? Sum of the Set S = \(\frac{n(5+5n)}{2} = \frac{5n(n+1)}{2}\) Mean = \(\frac{5(n+1)}{2}\)... So irrespective of n, mean is always divisible by 5.Am I Missing anything here?[/quote] Hi Rahul
Yes you are correct that mean is = 5*(n+1)/2 But this is NOT always divisible by 5. Because if n is odd, then (n+1) is even and divisible by 2. The mean now is divisible by 5 as you said. BUT if n is even, then (n+1) is odd, and (n+1) will NOT be divisible by 2, thus (n+1)/2 will give a decimal, 5*(n+1)/2 will thus give a decimal value, and thus NOT divisible by 5.
You can check with any example where you take n as even. Eg, if n=4, then {5, 10, 15, 20}. Mean is 12.5, NOT divisible by 5



Manager
Joined: 29 Nov 2016
Posts: 83

Re: Set S consists of all the positive multiples of 5 that are less than K
[#permalink]
Show Tags
02 Mar 2018, 02:30
2nd condition says k>240 i.e. ,k can be 241,242..... 1st says n<52 @k=241 you get 48 multiples of 5, hence you can have 48,49,50 or 51 as ans ( combining the two equations)
Mean = 5 (n+1)/2 At n= 49 and 51, n+1 gets even and mean gets divisible by 2. Hence either n is 48 or 50. N can not be 50 as at n=50 n gets divisible by 5 which can not happen as per question.
Hence n=48 .
Ans C



Intern
Joined: 01 Feb 2018
Posts: 3

Re: Set S consists of all the positive multiples of 5 that are less than K
[#permalink]
Show Tags
13 Mar 2018, 04:25
From "Set S consists of all positive multiples of 5..."Do we just assume that the set is evenly spaced unless stated otherwise? Was thinking of other possibilities too like {5,5,5,..}



DS Forum Moderator
Joined: 21 Aug 2013
Posts: 1435
Location: India

Re: Set S consists of all the positive multiples of 5 that are less than K
[#permalink]
Show Tags
13 Mar 2018, 09:54
isabelleo wrote: From "Set S consists of all positive multiples of 5..."Do we just assume that the set is evenly spaced unless stated otherwise? Was thinking of other possibilities too like {5,5,5,..} Hello Yes, a set having positive multiples of 5 means an evenly spaced set only. And the question clearly states, "..consists of all the positive multiples of 5 that are less than K". So for any given positive value of k, we will have to consider ALL positive multiples of 5 before that. That obviously cannot mean something like {5,5,5,..} Eg, if k=27, then S = {5, 10, 15, 20, 25}




Re: Set S consists of all the positive multiples of 5 that are less than K &nbs
[#permalink]
13 Mar 2018, 09:54






