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Set X consists of eight consecutive integers. Set Y consists of all th
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25 Jun 2018, 05:35
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Set X consists of eight consecutive integers. Set Y consists of all the integers that result from adding 4 to each of the integers in set X and all the integers that result from subtracting 4 from each of the integers in set X. How many more integers are there in set Y than in set X ? A. 0 B. 4 C. 8 D. 12 E. 16 NEW question from GMAT® Official Guide 2019 (PS00087)
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Re: Set X consists of eight consecutive integers. Set Y consists of all th
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28 Jun 2018, 18:06
Bunuel wrote: Set X consists of eight consecutive integers. Set Y consists of all the integers that result from adding 4 to each of the integers in set X and all the integers that result from subtracting 4 from each of the integers in set X. How many more integers are there in set Y than in set X ?
A. 0 B. 4 C. 8 D. 12 E. 16 Since set Y consists of all the integers that result from adding 4 to each of the integers in set X and all the integers that result from subtracting 4 from each of the integers in set X, it must have 8 integers each is 4 more than the ones in X and other 8 integers each is 4 less than the ones in X, unless there are overlaps in the elements obtained in each step. To verify that there are no overlaps, let the smallest element in X be x. After adding 4 to each element in the set, the smallest element obtained in this way is x + 4. If x is the smallest element in X, then x + 7 is the largest element in X (since there are 8 consecutive integers in X). Thus, the largest element obtained after subtracting 4 from each element is x + 3. In other words, there are no overlaps and Y has 8 + 8 = 16 integers, so it has 16  8 = 8 integers more than X. Alternate Solution: Let’s assume that set X contains 1, 2, 3, 4, 5, 6, 7, 8. Adding 4 to each term yields 5, 6, 7, 8, 9, 10, 11, 12. Now, we do the same thing, but instead we subtract 4 from each term of the original set; thus, we have 3, 2, 1, 0, 1, 2, 3, 4. We see that we have a total of 8 + 4 + 4 = 16 elements in set Y. This is 16  8 = 8 more elements than the number of elements in set X. Answer: C
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Re: Set X consists of eight consecutive integers. Set Y consists of all th
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25 Jun 2018, 05:45
Solution Given:• Set X consists of eight consecutive integers • Set Y consists of all the integers that result from adding 4 to each of the integers in set X and all the integers that result from subtracting 4 from each of the integers in set X To find:• How many more integers are there in set Y than in set X Approach and Working:• Let us assume the elements in Set X = {n, n+1, n+2, n+3, n+4, n+5, n+6, n+7} • Therefore, the elements in Set Y = {n+4, n+5, n+6, n+7, n+8, n+9, n+10, n+11, n4, n3, n2, n1, n, n+1, n+2, n+3} = {n4, n3, n2, n1, n, n+1, n+2, n+3, n+4, n+5, n+6, n+7, n+8, n+9, n+10, n+11} The number of more elements in set Y than in set X = 16 – 8 = 8 Hence, the correct answer is option C. Answer: CNote: The question can also be solved assuming any value in place of n
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Re: Set X consists of eight consecutive integers. Set Y consists of all th
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03 Jul 2018, 08:52
Hi ScottTargetTestPrepThe question says Set X consists of eight consecutive integers and Set Y contains all i.e "8 integers + 4" to each and again all i.e "8 integers + 4" to each. So its pretty clear set Y has 8 more integers in set X ? Isn't it very clear that the answer is 8. Also, I was unable to understand what you meant by overlap.



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Re: Set X consists of eight consecutive integers. Set Y consists of all th
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30 Sep 2018, 20:25
X = 11, 12, 13, 14, 15, 16, 17, 18,
Subtract 4 from each= 7, 8, 9, 10, 11, 12, 13, 14
Add 4 with each = 15, 16, 17, 18, 19, 20, 21, 22
So, Y= 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22
The bold numbers are in also x. So they are repeated. The new more numbers are the remaining 8.



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Re: Set X consists of eight consecutive integers. Set Y consists of all th
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04 Nov 2018, 15:46
Bunuel wrote: Set X consists of eight consecutive integers. Set Y consists of all the integers that result from adding 4 to each of the integers in set X and all the integers that result from subtracting 4 from each of the integers in set X. How many more integers are there in set Y than in set X ? A. 0 B. 4 C. 8 D. 12 E. 16 NEW question from GMAT® Official Guide 2019 (PS00087) Bunuel, For a question like this, I believe that we don't care about the repetition. A set {1,1,1,1,1} contains 5 integers. So we can easily answer C in this case. Is my understanding correct? Thanks!
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Re: Set X consists of eight consecutive integers. Set Y consists of all th
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05 Nov 2018, 07:25
septwibowo wrote: Bunuel wrote: Set X consists of eight consecutive integers. Set Y consists of all the integers that result from adding 4 to each of the integers in set X and all the integers that result from subtracting 4 from each of the integers in set X. How many more integers are there in set Y than in set X ? A. 0 B. 4 C. 8 D. 12 E. 16 NEW question from GMAT® Official Guide 2019 (PS00087) Bunuel, For a question like this, I believe that we don't care about the repetition. A set {1,1,1,1,1} contains 5 integers. So we can easily answer C in this case. Is my understanding correct? Thanks! Hi!! The question says set X has consecutive integers. Therefore all the integers in the set will be different integers. Posted from my mobile device



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Re: Set X consists of eight consecutive integers. Set Y consists of all th
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15 Feb 2019, 01:29
Bunuel wrote: Set X consists of eight consecutive integers. Set Y consists of all the integers that result from adding 4 to each of the integers in set X and all the integers that result from subtracting 4 from each of the integers in set X. How many more integers are there in set Y than in set X ? A. 0 B. 4 C. 8 D. 12 E. 16 NEW question from GMAT® Official Guide 2019 (PS00087) How many more is the question Set X : a b c d e f g h Set Y: consists of all the integers that result from adding 4 to each of the integers in set X and all the integers that result from subtracting 4 from each of the integers in set X Total 16 168 C
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Re: Set X consists of eight consecutive integers. Set Y consists of all th
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03 May 2019, 08:42
this question is pretty straight. we do not even need to add 4 or subtract 4 to get set Y. set Y will have double the integer than X. so we can just subtract set X from Set Y.




Re: Set X consists of eight consecutive integers. Set Y consists of all th
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03 May 2019, 08:42






