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13 Jun 2017, 06:12
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C
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74% (02:00) correct
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Seven years ago, Lisa was three times as old as Christine. In two years, Lisa will be twice as old as Christine. Lisa is how many years older than Christine?
A. 9
B. 14
C. 18
D. 21
E. 27
A. 9
B. 14
C. 18
D. 21
E. 27
13 Jun 2017, 06:24
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Bunuel
Seven years ago, Lisa was three times as old as Christine. In two years, Lisa will be twice as old as Christine. Lisa is how many years older than Christine?
A. 9
B. 14
C. 18
D. 21
E. 27
A. 9
B. 14
C. 18
D. 21
E. 27
Lisa current age = L
Christine current age = C
Seven years ago lisa = L-7
L-7 = 3(C-7)
L = 3C -14
Two years hence
L+2 = 2 (C+2)
L = 2C + 2
Now we know
3C -14 = 2C + 2
i.e. C = 16
i.e. L = 34
Differnece = 34-16 = 18
Answer: Option C
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Schools: ISB '19 IIMB IIMA XLRI HEC Sept19 intake Rotman '21 NUS '21 NTU '20 Trinity MBA '20 Bocconi '21 Smurfit "21
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13 Jun 2017, 07:19
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Bunuel
Seven years ago, Lisa was three times as old as Christine. In two years, Lisa will be twice as old as Christine. Lisa is how many years older than Christine?
A. 9
B. 14
C. 18
D. 21
E. 27
A. 9
B. 14
C. 18
D. 21
E. 27
Let present ages of Lisa's be L and Christine's be C respectively.
Seven years ago;
L - 7 = 3(C-7) = 3C - 21
3C - L = 21 - 7
3C - L = 14 ----------- (i)
In Two years from now;
L + 2 = 2(C + 2) = 2C + 4
2C - L = 2 - 4
2C - L = -2 ------------ (ii)
Subtracting (i) from (ii), we get;
C = 14 + 2 = 16
Substituting value of C in (ii), we get;
2(16) - L = -2
L = 32 + 2 = 34
Therefore difference of age between Lisa and Christine is = 34 - 16 =18. Answer C...
