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21 Oct 2015, 21:40
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D
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Difficulty:
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Question Stats:
92% (00:51) correct
8%
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wrong
based on 2534
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Square ABCD is inscribed in circle O. What is the area of square region ABCD?
(1) The area of circular region O is 64π.
(2) The circumference of circle O is 16π.
(1) The area of circular region O is 64π.
(2) The circumference of circle O is 16π.
21 Oct 2015, 22:28
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1.
Area of circle = pi*r^2 = 64 pi
=> r= 8
Diameter = 2*8= 16
Diagonal of the square is equal to diameter of the circle.
Now applying pythagorean theorem ,
Let s = side length
(s)^2 + (s)^2 = (diagonal)^2
=> 2 *(s)^2 = 256
=>(s)^2 =128
Sufficient.
2 . 2*pi*r= 16 * pi
=> r = 8
We can calculate the area as in 1 .
Sufficient.
Answer D
Area of circle = pi*r^2 = 64 pi
=> r= 8
Diameter = 2*8= 16
Diagonal of the square is equal to diameter of the circle.
Now applying pythagorean theorem ,
Let s = side length
(s)^2 + (s)^2 = (diagonal)^2
=> 2 *(s)^2 = 256
=>(s)^2 =128
Sufficient.
2 . 2*pi*r= 16 * pi
=> r = 8
We can calculate the area as in 1 .
Sufficient.
Answer D
22 Oct 2015, 03:16
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Bunuel
Square ABCD is inscribed in circle O. What is the area of square region ABCD?
(1) The area of circular region O is 64π.
(2) The circumference of circle O is 16π.
Kudos for a correct solution.
(1) The area of circular region O is 64π.
(2) The circumference of circle O is 16π.
Kudos for a correct solution.
Given: A square is inscribed in a circle. Therefore, the Diameter of circle = Diagonal of the square
Area of \(square = \frac{diagonal^2}{2}\)
Hence, all we need to know is the diameter of the circle.
S1- Given the area of circle, We can obtain the radius and hence, the diameter. - Sufficient
S2- Given the circumference, like S1 we can obtain diameter. - Sufficient
Both statements alone are sufficient- D
