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The average (arithmetic mean) score on a test taken by 10 students was [#permalink]

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15 Jun 2016, 01:18

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The average (arithmetic mean) score on a test taken by 10 students was x. If the average score for 5 of the students was 8, what was the average score, in terms of x, for the remaining 5 students who took the test?

A) 2x – 8 B) x – 4 C) 8 – 2x D) 16 – x E) 8 – (\(\frac{2}{x}\))

Re: The average (arithmetic mean) score on a test taken by 10 students was [#permalink]

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15 Jun 2016, 08:02

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Given : The average (arithmetic mean) score on a test taken by 10 students was x. Therefore, sum of all scores = 10*x = 10x. the average score for 5 of the students was 8. Thus, the total score contribution for these 5 students = 8*5 = 40. Contribution of other 5 students = 10x - 40. The average score, in terms of x, for the remaining 5 students = (10x - 40)/5 = 2x - 8. Hence A.

The average (arithmetic mean) score on a test taken by 10 students was x. If the average score for 5 of the students was 8, what was the average score, in terms of x, for the remaining 5 students who took the test?

A) 2x – 8 B) x – 4 C) 8 – 2x D) 16 – x E) 8 – (\(\frac{2}{x}\))

We are given that the average score on a test taken by 10 students was x and need to find the average score in terms of x if the average score for 5 of those students was 8.

Thus, the overall sum was 10x and the sum for the 5 students was (5)(8)= 40.

We need to determine the average of the 5 remaining students.

The sum for the 5 remaining students was 10x - 40, and thus the average is:

(10x - 40)/5 = 10x/5 - 40/5 = 2x - 8

Answer: A
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Re: The average (arithmetic mean) score on a test taken by 10 students was [#permalink]

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06 Dec 2016, 08:23

AbdurRakib wrote:

The average (arithmetic mean) score on a test taken by 10 students was x. If the average score for 5 of the students was 8, what was the average score, in terms of x, for the remaining 5 students who took the test?

A) 2x – 8 B) x – 4 C) 8 – 2x D) 16 – x E) 8 – (\(\frac{2}{x}\))

Total = 10x

Total of first 5 = 40

So, Average of remaining 5 students is \(\frac{10x - 40}{5}\) = \(2x – 8\)

Hence, answer will be (A) \(2x – 8\)

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Re: The average (arithmetic mean) score on a test taken by 10 students was [#permalink]

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05 Aug 2017, 07:46

Given: Sum of 10 students' marks= 10x Average of 5 of the students = 8 --> sum of 5 students' marks= 8*5= 40

Let S be the sum of remaining students' marks. 40+S = 10x --> S= 10x-40 Thus, average of remaining 5 student's marks= (10x-40)/5 ==> 2x-8 Answer: A
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