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The average (arithmetic mean) score on a test taken by 10 students was

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The average (arithmetic mean) score on a test taken by 10 students was x. If the average score for 5 of the students was 8, what was the average score, in terms of x, for the remaining 5 students who took the test?

A) 2x – 8
B) x – 4
C) 8 – 2x
D) 16 – x
E) 8 – (\(\frac{2}{x}\))
[Reveal] Spoiler: OA

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New post 15 Jun 2016, 08:02
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Given : The average (arithmetic mean) score on a test taken by 10 students was x. Therefore, sum of all scores = 10*x = 10x.
the average score for 5 of the students was 8. Thus, the total score contribution for these 5 students = 8*5 = 40.
Contribution of other 5 students = 10x - 40.
The average score, in terms of x, for the remaining 5 students = (10x - 40)/5 = 2x - 8. Hence A.

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Re: The average (arithmetic mean) score on a test taken by 10 students was [#permalink]

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New post 05 Dec 2016, 18:26
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AbdurRakib wrote:
The average (arithmetic mean) score on a test taken by 10 students was x. If the average score for 5 of the students was 8, what was the average score, in terms of x, for the remaining 5 students who took the test?

A) 2x – 8
B) x – 4
C) 8 – 2x
D) 16 – x
E) 8 – (\(\frac{2}{x}\))


We are given that the average score on a test taken by 10 students was x and need to find the average score in terms of x if the average score for 5 of those students was 8.

Thus, the overall sum was 10x and the sum for the 5 students was (5)(8)= 40.

We need to determine the average of the 5 remaining students.

The sum for the 5 remaining students was 10x - 40, and thus the average is:

(10x - 40)/5 = 10x/5 - 40/5 = 2x - 8

Answer: A
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Re: The average (arithmetic mean) score on a test taken by 10 students was [#permalink]

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New post 06 Dec 2016, 08:23
AbdurRakib wrote:
The average (arithmetic mean) score on a test taken by 10 students was x. If the average score for 5 of the students was 8, what was the average score, in terms of x, for the remaining 5 students who took the test?

A) 2x – 8
B) x – 4
C) 8 – 2x
D) 16 – x
E) 8 – (\(\frac{2}{x}\))


Total = 10x

Total of first 5 = 40

So, Average of remaining 5 students is \(\frac{10x - 40}{5}\) = \(2x – 8\)

Hence, answer will be (A) \(2x – 8\)

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Re: The average (arithmetic mean) score on a test taken by 10 students was [#permalink]

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New post 04 Apr 2017, 22:56
Say B is the average grade for the 5 students:

\(\cfrac { w1 }{ w2 } =\cfrac { A2-Aavg }{ Aavg-A1 } \\ \cfrac { 5 }{ 5 } =\cfrac { 8-x }{ x-B } \\ \cfrac { 1 }{ 1 } =\cfrac { 8-x }{ x-B } \\ x-A=8-x\\ 2x-8=B\)
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The average (arithmetic mean) score on a test taken by 10 students was [#permalink]

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New post 05 Aug 2017, 07:35
Think of this as a weighted average problem.

If first 5 students make the average 8 we are told to find out the average of the last 5.

Since the weights are 5 each lets assume that midpoint (Given as average of all = x) for all the students is 10
i.e x = 10

Creating a weighted average:

8(given).......................................................12 (assumed)
|_________________10(x assumed)_________________|


Substituting x = 10 should give us the value of 12

Only A gives us this answer.

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Re: The average (arithmetic mean) score on a test taken by 10 students was [#permalink]

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New post 05 Aug 2017, 07:46
Given:
Sum of 10 students' marks= 10x
Average of 5 of the students = 8 --> sum of 5 students' marks= 8*5= 40

Let S be the sum of remaining students' marks.
40+S = 10x --> S= 10x-40
Thus, average of remaining 5 student's marks= (10x-40)/5 ==> 2x-8
Answer: A
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Re: The average (arithmetic mean) score on a test taken by 10 students was   [#permalink] 05 Aug 2017, 07:46
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