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Re: The average of four integers is 8. If the greatest of the four intege [#permalink]

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31 Aug 2017, 00:05

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Not getting this at all.

If the average of 4 integers is 32, then the sum of those 4 integers should be equal to 4*32 = 128

If the greatest of the 4 numbers is 16, then to minimize the smallest integer, I set the 2nd and 3rd integer to the highest that they could be (1 less than 16) = 15.

16+15+15 = 46.

Therefore to get the value of the smallest, i subtracted the sum of what all four should equal to get an avg of 32 (128), from the sum of the greatest 3 integers (46). I get 82 as an answer. This doesn't make any sense at all.

Re: The average of four integers is 8. If the greatest of the four intege [#permalink]

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31 Aug 2017, 00:43

Given data: Average(4 integers) : 8 Max number : 16

Since the average of 4 numbers is 8, the total must be 32. If the maximum possible value of the integers is 16, the minimum value could be -16 if the other 2 integers are also 16. Though -13,0 and 1 are also possible, since we are asked to find the minimum value, Option B stands out and is our answer!

Average = \(\frac{16+16+16-16}{4} = \frac{32}{4} = 8\)(Option B)
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The average of four integers is 8. If the greatest of the four intege [#permalink]

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31 Aug 2017, 00:59

Bunuel wrote:

The average of four integers is 8. If the greatest of the four integers is 16, what is the minimum possible value of the least of the four integers

A. -32 B. -16 C. -13 D. 0 E. 1

sum of all integers will be 8*4 = 32 Greatest of all integers is 16 -32 is not possible as -32+16=-16..we cannot construct 48 with two integers less than 16 -16 is not possible as we cannot construct 32 with two integers less than 16 -13 is possible as -13+16 = 3..we can construct 29 with two integers less than 16 (14 and 15)

The average of four integers is 8. If the greatest of the four intege [#permalink]

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31 Aug 2017, 01:02

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Bunuel wrote:

The average of four integers is 8. If the greatest of the four integers is 16, what is the minimum possible value of the least of the four integers

A. -32 B. -16 C. -13 D. 0 E. 1

Average of four integers is 8. Sum = 32. Greatest integer is 16, Sum of remaining 3 integers is 32-16 = 16

i.e. sum of ( the least of four integers + remaining 2 integers )= 16 Trial and error based on answer choices above.

A. -32 + x = 16 x = 48 . Sum of remaining two cannot be 48 since it is greater than overall sum. Eliminated B. -16 + x = 16 x = 32. Eliminated C. -13 + x = 16 x = 29. D. 0 +x = 16 x = 16. E. 1 + x = 16 x = 15.

Answer is C, since that is the lesser value compared D and E.

Last edited by shruthiarvindh on 31 Aug 2017, 01:05, edited 1 time in total.

Re: The average of four integers is 8. If the greatest of the four intege [#permalink]

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31 Aug 2017, 01:05

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shruthiarvindh wrote:

Bunuel wrote:

The average of four integers is 8. If the greatest of the four integers is 16, what is the minimum possible value of the least of the four integers

A. -32 B. -16 C. -13 D. 0 E. 1

Average of four integers is 8. Sum = 32. Greatest integer is 16, Sum of remaining 3 integers is 32-16 = 16

i.e. sum of ( the least of four integers + remaining 2 integers )= 16 Trial and error based on answer choices above.

A. -32 + x = 16 x = 48 . Sum of remaining two cannot be 48 since it is greater than overall sum. Eliminated B. -16 + x = 16 x = 32. Eliminated C. -13 + x = 16 x = 39. Eliminated D. 0 +x = 16 x = 16. E. 1 + x = 16 x = 15.

Answer is D, since that is the lesser value compared to E.

shruthiarvindh i think u missed -13 + x = 16 => x= 29 (14,15)
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The average of four integers is 8. If the greatest of the four intege [#permalink]

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31 Aug 2017, 02:42

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given : a+b+c+d /4 = 8 and let d be greatest and a be smallest number a+b+c+d =32

given greatest number d=16

greatest number =16 => means other numbers are less or equal to 16.

a+b+c+16 =32 => a+b+c =16

option 1 if a =-32 => b+c =16+32 = 48 . So basically 48/2 =24 will be minimum value of one of the variable. Not possible because d=16 is greatest.

option 2 of a=-16 => b+c=16+16 =32. . So basically 32/2 =16 will be minimum value of one of the variable. so both b and c can be 16. And in this condition also greatest number will remain 16. This satisfy given condition. Therefore minimum possible value of a =-16

The average of four integers is 8. If the greatest of the four intege [#permalink]

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31 Aug 2017, 14:36

Bunuel wrote:

The average of four integers is 8. If the greatest of the four integers is 16, what is the minimum possible value of the least of the four integers

A. -32 B. -16 C. -13 D. 0 E. 1

if the greatest integer=16, then the first three integers must sum to 16 assume least integer=-16 16-(-16)=32 thus, the two middle integers must sum to 32 32=16+16 thus, the four integers are -16,16,16,16 B

Last edited by gracie on 31 Aug 2017, 14:45, edited 2 times in total.

The average of four integers is 8. If the greatest of the four intege [#permalink]

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31 Aug 2017, 14:42

Bunuel wrote:

The average of four integers is 8. If the greatest of the four integers is 16, what is the minimum possible value of the least of the four integers

A. -32 B. -16 C. -13 D. 0 E. 1

If the average of four integers is 8, their sum is 32.

The greatest integer of the four is 16.

Nothing in the problem says the integers cannot be the same.

The least of the four integers will be the smallest when the two "middle" values are equal to the greatest possible integer, which is given as 16 -- because we "weight" the average heavily on the high end, which allows one value, with less weight, to be very small.

So if three of the four = 16, the least possible value of the fourth is

The average of four integers is 8. If the greatest of the four integers is 16, what is the minimum possible value of the least of the four integers

A. -32 B. -16 C. -13 D. 0 E. 1

Using the formula average = sum/quantity, we see that the sum of the integers is 8 x 4 = 32. If the greatest integer is 16, the next two “smaller” integers can also be 16. So, the sum of the three largest integers is 16 x 3 = 48 and the smallest-value integer would be 32 - 48 = -16.

Answer: B
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Re: The average of four integers is 8. If the greatest of the four intege [#permalink]

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06 Sep 2017, 10:14

I think the main issue with this problem is how we translate the expression "If the greatest of the four integers is 16"

I've interpreted as there is no other number in the set bigger or even equal to 16, given me the lowest possible value -14, but it's not an answer option.

Could someone clarify the intent on this kind of language in GMAT exercises?

Re: The average of four integers is 8. If the greatest of the four intege [#permalink]

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06 Sep 2017, 10:38

The average of four integers is 8. If the greatest of the four integers is 16, what is the minimum possible value of the least of the four integers

The average of four integers is 8 -> (w+x+y+z)/4=8 Greatest of the four is 16 -> (16+x+y+z)/4=8

32= 16+x+y+z (multiple both sides by four) 16= x+y+z (subtract 16 from both sides)

If we are trying to find the minimum value of the smallest, then we can maximize the other two: 15 +14. Please remember 16 was the highest of all the numbers (given). Therefore the next two highest could be 29 (15+14). 29 + X =16. Therefore answer c (-13) is my response.

Please let me know your thoughts. First time posting, looking forward to this GMAT journey with all of you!

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