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The figure shown above consists of a shaded 9 - sided polygon and 9 un [#permalink]
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Updated on: 16 Jun 2017, 08:12
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The figure shown above consists of a shaded 9-sided polygon and 9 unshaded isosceles triangles.For each isosceles triangle,the longest side is a side of the shaded polygon and the two sides of equal length are extensions of the two adjacent sides of the shaded polygon.What is the value of a ?
The figure shown above consists of a shaded 9 - sided polygon and 9 un [#permalink]
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16 Jun 2017, 08:24
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In an n-sided polygon the sum of internal angles is (n-2)*180 degree So, the 9-sided polygon has sum of internal angles as 7*180 degree, making each of the individual angles \(\frac{7*180}{9}\) = 140 degree
Lets name the other two angles of the triangle with angle a as b and c. Since we know that the triangles(isosceles) has two sides of equal length as extensions, we know that 1. b=c (angles opposite equal sides are equal in magnitude) 2. a+b+c =180 degree (sum of angles in a triangle is 180 degree)
Since the sum of the angles in a straight line is 180 degree, b+140 = 180. Thus b = c = 40 degree
Using this information in a+b+c =180 degree, we can deduce that a = 100(Option A) _________________
You've got what it takes, but it will take everything you've got
The figure shown above consists of a shaded 9 - sided polygon and 9 un [#permalink]
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25 Jun 2017, 10:50
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AR15J wrote:
In the question, it is not mentioned that this polygon is a regular polygon, how can we calculate the individual angle of 9-sided polygon?
Since the triangles are isosceles, two of their angles will be equal. Now, as both of those equal angles are supplements of the vertices of the nonagon (9-sided polygon), and one vertex of the nonagon is a common supplement of any two adjacent triangles, all the angles of the nonagon will be equal.
The figure shown above consists of a shaded 9-sided polygon and 9 unshaded isosceles triangles.For each isosceles triangle,the longest side is a side of the shaded polygon and the two sides of equal length are extensions of the two adjacent sides of the shaded polygon.What is the value of a ?
Although the 9-sided polygon is NOT a regular polygon (with equal angles and equal sides), we CAN show that the angles are all equal. The key here is that each of the unshaded triangles is an isosceles triangle.
So, for example, we know that the two angles with the red dots are equal.
Since the next angle over is opposite the angle with the red dot, we know that that angle is also equal to the other two angles (see the diagram below)
Since the next triangle is ISOSCELES, we know that its other angle is equal to the first (see the diagram below)
We can continue applying the same rules and logic to see that all of the red dotted angles are all equal.
Next, if all of the red-dotted angles are equal, then all of the angles denoted with x are all equal, since each of those angles is on a line with the red-dotted angle.
To determine the value of x, we'll use the following rule: the sum of the angles in an n-sided polygon = (n - 2)(180º) So, in a 9-sided polygon, the sum of ALL 9 angles = (9 - 2)(180º) = (7)(180º) So, EACH individual angle = (7)(180º)/9 = 140º Also, since the red-dotted angle is on the line with the 140º, the red-dotted angle = 40º Let's add this information to the diagram below:
Since the unshaded triangle is isosceles, the other angle is also 40º
Since all three angles in the triangle must add to 180º, the last remaining angle (aº) must be 100º
The figure shown above consists of a shaded 9 - sided polygon and 9 un [#permalink]
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26 Nov 2017, 16:26
pushpitkc wrote:
In an n-sided polygon the sum of internal angles is (n-2)*180 degree So, the 9-sided polygon has sum of internal angles as 7*180 degree, making each of the individual angles \(\frac{7*180}{9}\) = 140 degree
Lets name the other two angles of the triangle with angle a as b and c. Since we know that the triangles(isosceles) has two sides of equal length as extensions, we know that 1.b = c (angles opposite equal sides are equal in magnitude) 2.a+b+c =180 degree(sum of angles in a triangle is 180 degree) Since angles in a straight line are 190degree, b+140 = 180. Thus b = c = 40degree
Using this information in a+b+c =180 degree, we can deduce that a = 100(Option A)
Thanks for the great breakdown!
(I think you meant "Since angles in a straight line are 180 degrees")
_________________
Re: The figure shown above consists of a shaded 9 - sided polygon and 9 un [#permalink]
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29 Nov 2017, 12:54
Hadrienlbb wrote:
pushpitkc wrote:
In an n-sided polygon the sum of internal angles is (n-2)*180 degree So, the 9-sided polygon has sum of internal angles as 7*180 degree, making each of the individual angles \(\frac{7*180}{9}\) = 140 degree
Lets name the other two angles of the triangle with angle a as b and c. Since we know that the triangles(isosceles) has two sides of equal length as extensions, we know that 1.b = c (angles opposite equal sides are equal in magnitude) 2.a+b+c =180 degree(sum of angles in a triangle is 180 degree) Since angles in a straight line are 190degree, b+140 = 180. Thus b = c = 40degree
Using this information in a+b+c =180 degree, we can deduce that a = 100(Option A)
Thanks for the great breakdown!
(I think you meant "Since angles in a straight line are 180 degrees")
The figure shown above consists of a shaded 9 - sided polygon and 9 un [#permalink]
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07 Jan 2018, 11:54
pushpitkc wrote:
In an n-sided polygon the sum of internal angles is (n-2)*180 degree So, the 9-sided polygon has sum of internal angles as 7*180 degree, making each of the individual angles \(\frac{7*180}{9}\) = 140 degree
Lets name the other two angles of the triangle with angle a as b and c. Since we know that the triangles(isosceles) has two sides of equal length as extensions, we know that 1. b=c (angles opposite equal sides are equal in magnitude) 2. a+b+c =180 degree (sum of angles in a triangle is 180 degree)
Since the sum of the angles in a straight line is 180 degree, b+140 = 180. Thus b = c = 40 degree
Using this information in a+b+c =180 degree, we can deduce that a = 100(Option A)
In the 9-sided polygon, each and every internal angle is equal to 140 degree. Using the property that sum of angles in a straight line equal 180 degree, we can deduce that one of the angles in the triangle is equal to 40 degree. Lets call that c, which is equal to 40 degree
We know that the sum of angles in a triangle is 180 degree. a + b + c = 180 Since angles opposite equal sides are equal in magnitude(b=c=40)
a + 80 =180 a = 100
Hope this help you!
_________________
You've got what it takes, but it will take everything you've got
In the 9-sided polygon, each and every internal angle is equal to 140 degree. Using the property that sum of angles in a straight line equal 180 degree, we can deduce that one of the angles in the triangle is equal to 40 degree. Lets call that c, which is equal to 40 degree
We know that the sum of angles in a triangle is 180 degree. a + b + c = 180 Since angles opposite equal sides are equal in magnitude(b=c=40)
Re: The figure shown above consists of a shaded 9 - sided polygon and 9 un [#permalink]
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06 May 2018, 07:13
pushpitkc wrote:
In an n-sided polygon the sum of internal angles is (n-2)*180 degree So, the 9-sided polygon has sum of internal angles as 7*180 degree, making each of the individual angles \(\frac{7*180}{9}\) = 140 degree
Lets name the other two angles of the triangle with angle a as b and c. Since we know that the triangles(isosceles) has two sides of equal length as extensions, we know that 1. b=c (angles opposite equal sides are equal in magnitude) 2. a+b+c =180 degree (sum of angles in a triangle is 180 degree)
Since the sum of the angles in a straight line is 180 degree, b+140 = 180. Thus b = c = 40 degree
Using this information in a+b+c =180 degree, we can deduce that a = 100(Option A)
pushpitkc , one thing i dont get if penthagon has following properties:
and if it is an Isosceles traingle which means two angles are equal then i though that these two equal angles are of 72degrees each, which mean that \(a\) should be 36 degrees
Re: The figure shown above consists of a shaded 9 - sided polygon and 9 un [#permalink]
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06 May 2018, 08:03
1
dave13 wrote:
pushpitkc wrote:
In an n-sided polygon the sum of internal angles is (n-2)*180 degree So, the 9-sided polygon has sum of internal angles as 7*180 degree, making each of the individual angles \(\frac{7*180}{9}\) = 140 degree
Lets name the other two angles of the triangle with angle a as b and c. Since we know that the triangles(isosceles) has two sides of equal length as extensions, we know that 1. b=c (angles opposite equal sides are equal in magnitude) 2. a+b+c =180 degree (sum of angles in a triangle is 180 degree)
Since the sum of the angles in a straight line is 180 degree, b+140 = 180. Thus b = c = 40 degree
Using this information in a+b+c =180 degree, we can deduce that a = 100(Option A)
pushpitkc , one thing i dont get if penthagon has following properties:
and if it is an Isosceles traingle which means two angles are equal then i though that these two equal angles are of 72degrees each, which mean that \(a\) should be 36 degrees
It is important to understand that in an isosceles triangle, the angles opposite to the equal sides are equal. If you observe the diagram, you will see that the angles "b" and "c" are opposite to the sides which are equal.
Hope this helps you!
_________________
You've got what it takes, but it will take everything you've got
gmatclubot
Re: The figure shown above consists of a shaded 9 - sided polygon and 9 un
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06 May 2018, 08:03