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22 Jun 2020, 18:37
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TheUltimateWinner
Bunuel
vanam52923
marcusaurelius
The hypotenuse of a right triangle is 10 cm. What is the perimeter, in centimeters, of the triangle?
(1) The area of the triangle is 25 square centimeters.
(2) The 2 legs of the triangle are of equal length.
Bunuel(1) The area of the triangle is 25 square centimeters.
(2) The 2 legs of the triangle are of equal length.
chetan2u
Plz help me on this doubt:
if triangle is a right triangle and hyp is 10 , should not the legs be 6 and 8 as per Pythagorean triplets?
You are assuming with no ground for it that the lengths of the sides are integers. Knowing that hypotenuse equals to 10 DOES NOT mean that the sides of the right triangle necessarily must be in the ratio of Pythagorean triple - 6:8:10. Or in other words: if \(a^2+b^2=10^2\) DOES NOT mean that \(a=6\) and \(b=8\), certainly this is one of the possibilities but definitely not the only one. In fact \(a^2+b^2=10^2\) has infinitely many solutions for \(a\) and \(b\) and only one of them is \(a=6\) and \(b=8\).
For example: \(a=1\) and \(b=\sqrt{99}\) or \(a=2\) and \(b=\sqrt{96}\) ...
Can we consider hypotenuse=10; and height=10 in statement 2? I asked this question because there is no strict condition that the base and height MUST be the equal legs.
Thanks__
Hi TheUltimateWinner,
Since we're dealing with a RIGHT TRIANGLE and we're told that the hypotenuse = 10, we can set up the following equation:
A^2 + B^2 = 10^2
With this right triangle, the other two sides (the two 'legs') must both be LESS than 10 (since a triangle cannot have a side length equal to 0). Thus, the height CANNOT be 10 (and in broader terms, with a right triangle, the hypotenuse is always the largest side).
GMAT assassins aren't born, they're made,
Rich
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29 Apr 2021, 09:38
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ScottTargetTestPrep
marcusaurelius
The hypotenuse of a right triangle is 10 cm. What is the perimeter, in centimeters, of the triangle?
(1) The area of the triangle is 25 square centimeters.
(2) The 2 legs of the triangle are of equal length.
(1) The area of the triangle is 25 square centimeters.
(2) The 2 legs of the triangle are of equal length.
We are given that the hypotenuse of a right triangle is 10 cm and we need to determine the perimeter of the triangle. We can let the other two sides (i.e., the two legs) of the right triangle be a and b. Since it’s a right triangle, by the Pythagorean theorem, we have a^2 + b^2 = 10^2, or a^2 + b^2 = 100. If we can find the values of a and b, then we can determine the perimeter of the triangle, since it will be a + b + 10.
Statement One Alone:
The area of the triangle is 25 square centimeters.
We are given a right triangle and we’ve let the two non-hypotenuse sides be a and b. Recall that the two non-hypotenuse sides of a right triangle are actually the base and height of the triangle, so the area of this triangle is A = ab/2. From the aforementioned equation a^2 + b^2 = 100, we can solve b as b = √(100 - a^2). Since we are given that A = 25, and substituting b = √(100 - a^2) in A = ab/2, we can say:
25 = [a√(100 - a^2)]/2
We see that we can solve for a (though we don’t have to actually solve for it). And once we’ve solved for a, we can determine the value of b, since b = √(100 - a^2). Therefore, we can determine the perimeter of the triangle, since we can determine the values of both a and b. Statement one alone is sufficient to answer the question.
Statement Two Alone:
The 2 legs of the triangle are of equal length.
Since a^2 + b^2 = 100 and we are given that a = b, we can say:
a^2 + a^2 = 100
We see that we can solve for a (though we don’t have to actually solve for it). And once we’ve solved for a, we can determine the value of b, since b = a. Therefore, we can determine the perimeter of the triangle, since we can determine the values of both a and b. Statement two alone is sufficient to answer the question.
Answer: D
Something I always struggle with when given an equation with exponents such as the one Scott solved for in statement (1) (25 = [a√(100 - a^2)]/2) is how do we know that there aren't multiple solutions to the equation? (i.e. like when you're factoring the form of aX^2+bx+c). Is there any indication that there will NOT be multiple possible solutions from the equation without fully factoring out/solving?
Sarabjeets746
30 Apr 2021, 03:55
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I think there is a faster way to evaluate statement 1.
Area=25 => b*h=50 => b and h are factors of 50. Possible pairs: (1,50); (2,25); (5,10).
Remember: this triangle is a right triangle, which means the hypotenuse is supposed to be the largest side of this triangle.
So out of these three pairs only one pair (5,10). Sufficient. Bunuel VeritasKarishma what do you think?
Area=25 => b*h=50 => b and h are factors of 50. Possible pairs: (1,50); (2,25); (5,10).
Remember: this triangle is a right triangle, which means the hypotenuse is supposed to be the largest side of this triangle.
So out of these three pairs only one pair (5,10). Sufficient. Bunuel VeritasKarishma what do you think?
