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Sub 505 Level|   Word Problems|                  
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The only contents of a parcel are 25 photographs and 30 negatives. What is the total weight, in ounces, of the parcel's contents?
(1) The weight of each photograph is 3 times the weight of each negative.
(2) The total weight of 1 of the photographs and 2 of the negatives is i ounce.

What is 25P+30N?
Statement 1: 1P=3N. Not sufficient
Statement 2: 1P+2N = 1 ounce. Not sufficient

C. We can solve using both statements.
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Theres a little mistake. St(2) should say: The total weight of 1 of the photographs and 2 of the negatives is 1/3 ounce.

Lets call the weight of the photographs "P" and negatives "N"

St(1) dosent give us much. Just that \(P=3N\). Insufficient.
St(2) tells us that \(P+2N=1/3\). Also Insufficient.

Putting them together we get: \(3N+2N=1/3\)
So we can find N and P

Ans is C.
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The only contents of a parcel are 25 photographs and 30 negatives. What is the total weight, in ounces, of the parcel's contents?

(1) The weight of each photograph is 3 times the weight of each negative.

\(p = 3n\)

\(25(3n) + 30n = 75n + 30n = 105n\)

As we are not aware of the value of n we cannot determine the total weight.

Hence, (1) =====> is NOT SUFFICIENT

(2) The total weight of 1 of the photographs and 2 of the negatives is 1/3 ounce.

\(1p + 2n = \frac{1}{3}\)

We still cannot determine the value of total weight as we are not aware of the values of p & n

Hence, (2) =====> is NOT SUFFICIENT

Combining (1) & (2)

Substituting the value obtained from (1) in (2) should give us total weight.

Hence, cobnined (1) & (2) =====> is SUFFICIENT

Hence, Answer is C
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What if the question was 25 photographs and 50 negatives? Would statement two be sufficient then? Because for statement two to be sufficient we would have to assume all the photographs weigh the same and all the negatives weigh the same? so is it safe to assume so?­
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