EgmatQuantExpert wrote:

Question:

There’s a party in town and Mike can’t decide what to wear. However, he has decided to follow the following:

1. He will wear tie and shoes

2. He may or may not wear socks.

Mike has \(3\) ties, \(4\) pairs of shoes and \(5\) pairs of socks.

In how many ways can Mike dress for the party?

Options: There are two ways in which Mike can go to the party in town

1. Wears tie and shoes but no socks

There are 3*4 = 12 ways in which he can dress for the party

2. Wears tie, shoes, and socks

There are 3*4*5 = 60 ways in which he can dress for the party

Therefore, Mike could go to the party in 12+60 =

72 ways(Option C)

_________________

You've got what it takes, but it will take everything you've got