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Tom drove from X to Y and then from Y to X and took different routes b

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Tom drove from X to Y and then from Y to X and took different routes b  [#permalink]

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New post 03 Jul 2017, 03:31
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Tom drove from X to Y and then from Y to X and took different routes back and forth. It took him 40 miles per hour to move from X to Y. Meanwhile, it took him 50 miles per hour to come from Y to X. What was the average speed for his entire travel?

1) The distance from the return trip was 4/5 of the entire distance.
2) The distance from the return trip was 160 miles.
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Re: Tom drove from X to Y and then from Y to X and took different routes b  [#permalink]

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New post 03 Jul 2017, 03:41
Bunuel
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Re: Tom drove from X to Y and then from Y to X and took different routes b  [#permalink]

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New post 03 Jul 2017, 03:59
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Tom drove from X to Y and then from Y to X and took different routes back and forth. It took him 40 miles per hour to move from X to Y. Meanwhile, it took him 50 miles per hour to come from Y to X. What was the average speed for his entire travel?

\(Average \ speed = \frac{(Total \ distance)}{(Total \ time)}\)

(1) The distance from the return trip was 4/5 of the entire distance. Say the entire distance is d, then the distance from Y to X is 4d/5 and the distance from X to Y is d/5.

\(Average \ speed = \frac{(Total \ distance)}{(Total \ time)}=\frac{d}{\frac{(\frac{d}{5})}{40}+\frac{(\frac{4d}{5})}{50}}=\frac{1}{\frac{(\frac{1}{5})}{40}+\frac{(\frac{4}{5})}{50}}\) (by reducing d). Sufficient.


(2) The distance from the return trip was 160 miles. Not sufficient.

Answer: A.

Hope it's clear.
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Re: Tom drove from X to Y and then from Y to X and took different routes b  [#permalink]

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New post 01 Aug 2018, 05:36
1
haardiksharma wrote:
Tom drove from X to Y and then from Y to X and took different routes back and forth. It took him 40 miles per hour to move from X to Y. Meanwhile, it took him 50 miles per hour to come from Y to X. What was the average speed for his entire travel?

1) The distance from the return trip was 4/5 of the entire distance.
2) The distance from the return trip was 160 miles.


Dear Moderator,
Found this DS question while going through the PS problems in Rate/Distance , Hope you will do the needful. Thank you.
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Re: Tom drove from X to Y and then from Y to X and took different routes b  [#permalink]

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New post 01 Aug 2018, 06:09
stne wrote:
haardiksharma wrote:
Tom drove from X to Y and then from Y to X and took different routes back and forth. It took him 40 miles per hour to move from X to Y. Meanwhile, it took him 50 miles per hour to come from Y to X. What was the average speed for his entire travel?

1) The distance from the return trip was 4/5 of the entire distance.
2) The distance from the return trip was 160 miles.


Dear Moderator,
Found this DS question while going through the PS problems in Rate/Distance , Hope you will do the needful. Thank you.


Moved to DS forum. Thank you.
_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
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Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


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Re: Tom drove from X to Y and then from Y to X and took different routes b  [#permalink]

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New post 01 Aug 2018, 06:54
Bunuel wrote:
Tom drove from X to Y and then from Y to X and took different routes back and forth. It took him 40 miles per hour to move from X to Y. Meanwhile, it took him 50 miles per hour to come from Y to X. What was the average speed for his entire travel?

\(Average \ speed = \frac{(Total \ distance)}{(Total \ time)}\)

(1) The distance from the return trip was 4/5 of the entire distance. Say the entire distance is d, then the distance from Y to X is 4d/5 and the distance from X to Y is d/5.

\(Average \ speed = \frac{(Total \ distance)}{(Total \ time)}=\frac{d}{\frac{(\frac{d}{5})}{40}+\frac{(\frac{4d}{5})}{50}}=\frac{1}{\frac{(\frac{1}{5})}{40}+\frac{(\frac{4}{5})}{50}}\) (by reducing d). Sufficient.


(2) The distance from the return trip was 160 miles. Not sufficient.

Answer: A.

Hope it's clear.


Hello, I was wondering about this part - "the distance from Y to X is 4d/5 and the distance from X to Y is d/5."

I understood why the distance from Y to X is 4d/5, but how did we conclude that the distance from X to Y is d/5?

Posted from my mobile device
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Joined: 02 Sep 2009
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Re: Tom drove from X to Y and then from Y to X and took different routes b  [#permalink]

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New post 01 Aug 2018, 07:05
vedanths wrote:
Bunuel wrote:
Tom drove from X to Y and then from Y to X and took different routes back and forth. It took him 40 miles per hour to move from X to Y. Meanwhile, it took him 50 miles per hour to come from Y to X. What was the average speed for his entire travel?

\(Average \ speed = \frac{(Total \ distance)}{(Total \ time)}\)

(1) The distance from the return trip was 4/5 of the entire distance. Say the entire distance is d, then the distance from Y to X is 4d/5 and the distance from X to Y is d/5.

\(Average \ speed = \frac{(Total \ distance)}{(Total \ time)}=\frac{d}{\frac{(\frac{d}{5})}{40}+\frac{(\frac{4d}{5})}{50}}=\frac{1}{\frac{(\frac{1}{5})}{40}+\frac{(\frac{4}{5})}{50}}\) (by reducing d). Sufficient.


(2) The distance from the return trip was 160 miles. Not sufficient.

Answer: A.

Hope it's clear.


Hello, I was wondering about this part - "the distance from Y to X is 4d/5 and the distance from X to Y is d/5."

I understood why the distance from Y to X is 4d/5, but how did we conclude that the distance from X to Y is d/5?

Posted from my mobile device


(1) The distance from the return trip was 4/5 of the entire distance.

So, if the total distance is d, then the distance from Y yo X is 4/5*d and the distance from X to Y is d - 4/5*d = d/5.
_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

Re: Tom drove from X to Y and then from Y to X and took different routes b &nbs [#permalink] 01 Aug 2018, 07:05
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