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Am I missing sth?
1-2-3-4-5 is -14 and not -13, right? so the correct answer would be D
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Am I missing sth?
1-2-3-4-5 is -14 and not -13, right? so the correct answer would be D

1 - 2 - 3 - 4 - 5 = -13 not -14.
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honchos
T is the set of all numbers that can be written as the following sum involving distinct non-zero integers a, b, c and d: |a|/a + 2(|b|/b) + 3(|c|/c) + 4(|d|/d) + 5(|abcd|/abcd). What is the range of T?

A. 15
B. 20
C. 28
D. 29
E. 30

\(\frac{|x|}{x}\) is 1 when \(x>0\) and -1 when \(x<0\). For example, if \(x=2\), then \(\frac{|x|}{x}=1\) and if \(x=-2\), then \(\frac{|x|}{x}=-1\).

Thus the maximum value of \(\frac{|a|}{a} + 2(\frac{|b|}{b}) + 3(\frac{|c|}{c}) + 4(\frac{|d|}{d}) + 5(\frac{|abcd|}{abcd})\) is obtained when each of a, b, c and d are positive: 1+2+3+4+5=15.

As for the minimum value: notice that all a, b, c, d and abcd cannot simultaneously be negative. For example if a, b, c and d are negative then abcd will be positive. Thus the minimum value is obtained when a is positive and b, c and d are negative: 1-2-3-4-5=-13.

The range = 15 - (-13) = 28.

Answer: C.

Hey Bunuel..there are many values in between that we can never achieve..say 0..so how is range defined in such cases...is it just the max-min..
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Bunuel
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T is the set of all numbers that can be written as the following sum involving distinct non-zero integers a, b, c and d: |a|/a + 2(|b|/b) + 3(|c|/c) + 4(|d|/d) + 5(|abcd|/abcd). What is the range of T?

A. 15
B. 20
C. 28
D. 29
E. 30

\(\frac{|x|}{x}\) is 1 when \(x>0\) and -1 when \(x<0\). For example, if \(x=2\), then \(\frac{|x|}{x}=1\) and if \(x=-2\), then \(\frac{|x|}{x}=-1\).

Thus the maximum value of \(\frac{|a|}{a} + 2(\frac{|b|}{b}) + 3(\frac{|c|}{c}) + 4(\frac{|d|}{d}) + 5(\frac{|abcd|}{abcd})\) is obtained when each of a, b, c and d are positive: 1+2+3+4+5=15.

As for the minimum value: notice that all a, b, c, d and abcd cannot simultaneously be negative. For example if a, b, c and d are negative then abcd will be positive. Thus the minimum value is obtained when a is positive and b, c and d are negative: 1-2-3-4-5=-13.

The range = 15 - (-13) = 28.

Answer: C.

Hey Bunuel..there are many values in between that we can never achieve..say 0..so how is range defined in such cases...is it just the max-min..

Yes, the range is always the difference between the largest and smallest.
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Bunuel
honchos
T is the set of all numbers that can be written as the following sum involving distinct non-zero integers a, b, c and d: |a|/a + 2(|b|/b) + 3(|c|/c) + 4(|d|/d) + 5(|abcd|/abcd). What is the range of T?

A. 15
B. 20
C. 28
D. 29
E. 30

\(\frac{|x|}{x}\) is 1 when \(x>0\) and -1 when \(x<0\). For example, if \(x=2\), then \(\frac{|x|}{x}=1\) and if \(x=-2\), then \(\frac{|x|}{x}=-1\).

Thus the maximum value of \(\frac{|a|}{a} + 2(\frac{|b|}{b}) + 3(\frac{|c|}{c}) + 4(\frac{|d|}{d}) + 5(\frac{|abcd|}{abcd})\) is obtained when each of a, b, c and d are positive: 1+2+3+4+5=15.

As for the minimum value: notice that all a, b, c, d and abcd cannot simultaneously be negative. For example if a, b, c and d are negative then abcd will be positive. Thus the minimum value is obtained when a is positive and b, c and d are negative: 1-2-3-4-5=-13.

The range = 15 - (-13) = 28.

Answer: C.

I took abcd as a 4 digit number.
Bunuel , could you please edit the question and replace abcd with a*b*c*d , for clarity. :)
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Bunuel
honchos
T is the set of all numbers that can be written as the following sum involving distinct non-zero integers a, b, c and d: |a|/a + 2(|b|/b) + 3(|c|/c) + 4(|d|/d) + 5(|abcd|/abcd). What is the range of T?

A. 15
B. 20
C. 28
D. 29
E. 30

\(\frac{|x|}{x}\) is 1 when \(x>0\) and -1 when \(x<0\). For example, if \(x=2\), then \(\frac{|x|}{x}=1\) and if \(x=-2\), then \(\frac{|x|}{x}=-1\).

Thus the maximum value of \(\frac{|a|}{a} + 2(\frac{|b|}{b}) + 3(\frac{|c|}{c}) + 4(\frac{|d|}{d}) + 5(\frac{|abcd|}{abcd})\) is obtained when each of a, b, c and d are positive: 1+2+3+4+5=15.

As for the minimum value: notice that all a, b, c, d and abcd cannot simultaneously be negative. For example if a, b, c and d are negative then abcd will be positive. Thus the minimum value is obtained when a is positive and b, c and d are negative: 1-2-3-4-5=-13.

The range = 15 - (-13) = 28.

Answer: C.

I took abcd as a 4 digit number.
Bunuel , could you please edit the question and replace abcd with a*b*c*d , for clarity. :)

If abcd were a 4-digit number if would have been mentioned explicitly. Without that, abcd can only be a*b*c*d since only multiplication sign (*) is usually omitted.
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I am wondering why no one asked why we are considering "a" positive, why not b or c or d ?
well the answer is: as we are looking for minimum value we should add as less as possible, thus á is considered +ve value.
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I am confused absolute regarding values. Could some clarify a bit?
As per theory |x| is +ve if x>0 and -ve when x<0
And also as per theory and solutions in multiple questions |-3| is taken as 3.

Aren't the two statements contradictory?
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realslimsiddy
I am confused absolute regarding values. Could some clarify a bit?
As per theory |x| is +ve if x>0 and -ve when x<0
And also as per theory and solutions in multiple questions |-3| is taken as 3.

Aren't the two statements contradictory?

The part I've highlighted in red is not correct. |x| is never negative; |x| can be zero, when x is zero, and in all other cases |x| is positive.

What is true is the following:

• When x > 0, |x| = x
• When x < 0, |x| = -x

But in this second case, when x < 0, notice that -x is a positive number (because if x is negative, -x will be positive), so in both cases, |x| is positive.

Sometimes test takers find this confusing at first, because "-x" looks like a negative number. But it only sometimes is -- it all depends on whether x itself is positive or negative.
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realslimsiddy
I am confused absolute regarding values. Could some clarify a bit?
As per theory |x| is +ve if x>0 and -ve when x<0
And also as per theory and solutions in multiple questions |-3| is taken as 3.

Aren't the two statements contradictory?

The part I've highlighted in red is not correct. |x| is never negative; |x| can be zero, when x is zero, and in all other cases |x| is positive.

What is true is the following:

• When x > 0, |x| = x
• When x < 0, |x| = -x

But in this second case, when x < 0, notice that -x is a positive number (because if x is negative, -x will be positive), so in both cases, |x| is positive.

Sometimes test takers find this confusing at first, because "-x" looks like a negative number. But it only sometimes is -- it all depends on whether x itself is positive or negative.


Thank you so much. This was very helpful.
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honchos
T is the set of all numbers that can be written as the following sum involving distinct non-zero integers a, b, c and d: |a|/a + 2(|b|/b) + 3(|c|/c) + 4(|d|/d) + 5(|abcd|/abcd). What is the range of T?

A. 15
B. 20
C. 28
D. 29
E. 30
I fell again on this type of question. Here's how i analysed.
So, from the given condition 15 can never be the range. Eliminate A.
As we can take a,b,c and d negative the lowest TRAP value we get is -5(-1 - 2 - 3 - 4 + 5). This gives us one of the trap answers 20.

Hence our next step should be to get the least value of the T. This can be done by taking the lowest values of components whose coefficient are larger so that sum is least(largest negative). Only way to do this is taking value of 'a' positive and rest negative so that 5(|abcd|/abcd) give -5('a*b*c*d' should be negative).
Hence the least value if 1 - 2 - 3 - 4 - 5 = -13.
Range = 15 - (-13) = 28.

Answer C.
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Bunuel
honchos
T is the set of all numbers that can be written as the following sum involving distinct non-zero integers a, b, c and d: |a|/a + 2(|b|/b) + 3(|c|/c) + 4(|d|/d) + 5(|abcd|/abcd). What is the range of T?

A. 15
B. 20
C. 28
D. 29
E. 30

\(\frac{|x|}{x}\) is 1 when \(x>0\) and -1 when \(x<0\). For example, if \(x=2\), then \(\frac{|x|}{x}=1\) and if \(x=-2\), then \(\frac{|x|}{x}=-1\).

Thus the maximum value of \(\frac{|a|}{a} + 2(\frac{|b|}{b}) + 3(\frac{|c|}{c}) + 4(\frac{|d|}{d}) + 5(\frac{|abcd|}{abcd})\) is obtained when each of a, b, c and d are positive: 1+2+3+4+5=15.

As for the minimum value: notice that all a, b, c, d and abcd cannot simultaneously be negative. For example if a, b, c and d are negative then abcd will be positive. Thus the minimum value is obtained when a is positive and b, c and d are negative: 1-2-3-4-5=-13.

The range = 15 - (-13) = 28.

Answer: C.


Why are we not including '0' in the range?
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Bunuel
honchos
T is the set of all numbers that can be written as the following sum involving distinct non-zero integers a, b, c and d: |a|/a + 2(|b|/b) + 3(|c|/c) + 4(|d|/d) + 5(|abcd|/abcd). What is the range of T?

A. 15
B. 20
C. 28
D. 29
E. 30

\(\frac{|x|}{x}\) is 1 when \(x>0\) and -1 when \(x<0\). For example, if \(x=2\), then \(\frac{|x|}{x}=1\) and if \(x=-2\), then \(\frac{|x|}{x}=-1\).

Thus the maximum value of \(\frac{|a|}{a} + 2(\frac{|b|}{b}) + 3(\frac{|c|}{c}) + 4(\frac{|d|}{d}) + 5(\frac{|abcd|}{abcd})\) is obtained when each of a, b, c and d are positive: 1+2+3+4+5=15.

As for the minimum value: notice that all a, b, c, d and abcd cannot simultaneously be negative. For example if a, b, c and d are negative then abcd will be positive. Thus the minimum value is obtained when a is positive and b, c and d are negative: 1-2-3-4-5=-13.

The range = 15 - (-13) = 28.

Answer: C.


Why are we not including '0' in the range?

What do you mean by "Why are we not including '0' in the range"?

The range of a set is the difference between the largest and smallest elements of the set. The largest element = 15 and the smallest = -13. The range = 15 - (-13) = 28.
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This is a question and a half !! Great one.
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