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C
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Difficulty:
15%
(low)
Question Stats:
82% (01:11) correct
18%
(01:31)
wrong
based on 466
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History
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A certain population of bacteria doubles every 10 minutes. If the number of bacteria in the population initially was 10^5, then what was the number in the population 1 hour later?
A) 2(10^5)
B) 6(10^5)
C) (2^6)(10^5)
D) (10^6)(10^5)
E) (10^5)^6
Source: Chili Hot GMAT
A) 2(10^5)
B) 6(10^5)
C) (2^6)(10^5)
D) (10^6)(10^5)
E) (10^5)^6
Source: Chili Hot GMAT
03 Dec 2014, 20:08
Kudos
Bookmarks
Answer = C) (2^6)(10^5)
Initial value \(= 10^5\)
Interval = 10 Minutes
Intervals in 60 Minutes \(= \frac{60}{10} = 6\)
In one hour, value \(= 2^6 * 10^5\)
Initial value \(= 10^5\)
Interval = 10 Minutes
Intervals in 60 Minutes \(= \frac{60}{10} = 6\)
In one hour, value \(= 2^6 * 10^5\)
General Discussion
03 Dec 2014, 09:09
Kudos
Bookmarks
x bacteria would become 2x in 10 mins, which would become 4x in the next 10 (total 20 mins)...
So in 60 mins x becomes 2^6 times into x
Therefore Answer is C, (2^6)(10^5)
So in 60 mins x becomes 2^6 times into x
Therefore Answer is C, (2^6)(10^5)
