gvij2017
I ordered distileries in A,B, C, D, E, F,G and H.
1. 4 distileries having the longest continuous operation are: B, D, G, H and their productions are 1700, 2500, 2200, 2200. Therefore, the average is 1900.
Average production for other four: 1000,1500,5800,115; average is 20xx.
Therefore, Ans is NO.
2. The median of peating level of peated whiskies is 35 and that of unpeated whiskies is 2.5. So the difference is <35.
Ans is No
3. Two contender for this problem is C= 2012-1881/2012-2001~ 130/11 and E= 2012-1846/2012-1974~170/26
Ans is Yes.
So in summary Answers are
NO
NO
YES
Please appraise my solution and point out if something wrong I have done here.
Dear
gvij2017you are the first who has decided to outline the solution of the task - well done!
Mere notice, for the first question you properly selected two range of whisky distilleries, just silly math mistake.
Sum of the first 4 company is 1700, 2500, 2200, 2200 = 8600
Sum of the second 4 company is 1000,1500,5800,115 = 8415
Hence, the mean of the first group will be greater then the mean of the second.
The answer is
Yes.
For the second question, there are 6 peated and 2 untpeated style.
Thus, median of 6 is (6+1) = 3.5 between 3-4. Peated: (35+35)/2 = 35
The median of 2 is (2+1) = 1.5 between 1-2. Unpeated (3.5+1.5)/2 = 2.5
35-2.5 = 32.5
Yet, the question asks more then 35ppt, thus the answer is
NoFor the 3d one, I do not certain that my approach is correct.
Pursuant to the statement: greatest ration of years since founding to year of continuous operation to the present. R = foundation Year/ continuous Year / current Year
Bruichladdich = 1881/2001/2021 = 0.000467.
Ardbeg = 0.000451
Caol Il = 0.000464
The answer is
Yes