DavidTutorexamPALI understood the part of stmnt 1 but in the case of stmn 2 we have determined the value of x as 10
now we know that since x is 10 so possible perfect squares between which 10 comes are
(1,16)( 4,16) ( 4,25) ( 9,16) .. so on
we get yes that x is purple when two perfect squares are ( 4,16)
and no that x is not purple when the two perfect squares are ( 9,16) (1,16) or any other set of perfect square
why is that even though we are getting both yes & no as the answer for stmnt 2 , we are still validating to be true as 'purple' when its not the case always..
BunuelGMATinsightchetan2uplease advise on solution for #2 ..
DavidTutorexamPAL
Bunuel
A number can be considered “purple” if it halfway between two perfect squares. Is x purple?
(1) The product of x and 2 is equal to the sum of two squares.
(2) The average of x and the square of 2 is 7.
Instead of trying to explicitly solve, we'll use numbers to show us the logic.
This is an Alternative approach.
(1) Lets choose two squares: 1 and 4. Then 2x = 5 so x=2.5 Is x in the middle of two squares? Well, the only square smaller than x is 1 and the first square larger than x is 4. Since 2.5 = (1+4)/2) then x is in the middle between them. But wait, this is exactly how we calculated x! If 2x = square + square then x = (square + square)/2 meaning it is in the middle of 2 squares.
Sufficient.
(2) So (x + 4)/2 = 7 and x = 10. Is x in the middle of two squares? If it were in the middle of 1 and a square then 10 + (10-1) = 19 would be a square which it is not. If it were in the middle of 4 and a square then 10 + (10 - 4) = 16 would be a square, which it is. Then x is in the middle of 4 and 16 and the answer is YES.
Sufficient.
(D) is our answer.