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Total number of ways: \(^3{C_1} * ^4{C_1} * ^6{C_1} * ^8{C_3}\)

=> 3 * 4 * 6 * 56

=> 4,032

Answer A
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[quote="MathRevolution"]Total number of ways: \(^3{C_1} * ^4{C_1} * ^6{C_1} * ^8{C_3}\)

=> 3 * 4 * 6 * 56

=> 4,032

Here it is mentioned upto 3 which according to me means that the sandwich can have 0-3 choices of veggies , doesn't it?

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Bunuel I didn't get why A is correct. For veggies a person can choose up to 3 veggies, it can be 0,1,2 or 3. Please help why 8C3 is correct.
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Bunuel
Rick’s Sandwich Shop lets customers create their own sandwiches by choosing from among a certain number of ingredients. When ordering Rick’s Rockin’ Sandwich, the customer must choose 1 of 3 breads, 1 of 6 meats, and 1 of 4 cheeses. The customer can also add up to 3 of 8 different veggies. How many unique Rick’s Rockin’ Sandwiches could a customer order?


A. 4,032

B. 6,624

C. 6,696

D. 24,192

E. 28,932

Anyone else wants to try?
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Meat, Bread and Cheeses can be selected in 6C1*3C1*4C1 = 72 ways
Veggies portion is Optional.
Anyone can include veggies in their sandwiches up to 3 options out of 8

Let say there are 4 persons
=> A want sandwich with all 3 veggies kind
=> B want sandwich with 2 veggies kind
=> C want sandwich with only 1 veggie kind
=> D want sandwich with No Veggie

=> A can take sandwich in 8C3*72 = 4032 ways
=> B can take sandwich in 8C2*72 = 2016 ways
=> C can take sandwich in 8C1*72 = 576 ways
=> D can take sandwich in 8C0*72 = 72 ways (8C0 = 1)

Total ways = 4032+2016+576+72 = 6696 ways.

Answer is C

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IMO- C
In this question
Choose of veggies is optional
Customer can choose veggies in 4 ways
No veggies- 3C1*6C1*4C1*8C0. =72
1 veggies - 3C1*6C1*4C1*8C1 =576
2 veggies- 3C1*6C1*4C1*8C2. =2016
3 veggies- 3C1*6C1*4C1*8C3. =4032
Total ways. To select a sandwich. =72+576+2016+4032
=6696

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Bunuel
Rick’s Sandwich Shop lets customers create their own sandwiches by choosing from among a certain number of ingredients. When ordering Rick’s Rockin’ Sandwich, the customer must choose 1 of 3 breads, 1 of 6 meats, and 1 of 4 cheeses. The customer can also add up to 3 of 8 different veggies. How many unique Rick’s Rockin’ Sandwiches could a customer order?


A. 4,032

B. 6,624

C. 6,696

D. 24,192

E. 28,932


Doing any calculation more than needed is a waste of time here.

We know that there are 3C1 ways of choosing the bread, 6C1 ways of choosing the meats, and 4C1 ways of choosing the cheese.
So that makes 3 * 6 * 4 = 72

Now, we can choose 0, 1, 2, or 3 of the 8 vegetables.
That is (8C0 + 8C1 + 8C2 + 8C3) = 93

Since one of the aforementioned combinations of vegetables will always be chosen with the calculated combination of bread, meats, and cheese.
it's 72 * 93

Looking at ones place of both those numbers, 2 * 3 = 6. Only C has 6 in it's unit place.
So, C
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= [3C1*6C1*4C1] x [8C0+8C1+8C2+8C3]
= 72 x 93
= 6696
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