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Sub 505 (Easy)|   Algebra|   Exponents|      
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Bunuel
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GMAT Club Around The World!!! (3^3+ 3)/3 + (3^2+3^2)/3^2 = 31 Dec 2020, 03:15
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C
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5% (low)

Question Stats:

99% (00:41) correct 1% (01:02) wrong based on 97 sessions

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\(\frac{3^3+ 3}{3} + \frac{3^2+3^2}{3^2} =\)

A. 1
B. 5
C. 12
D. 17
E. 30



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C
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GMAT Club Around The World!!! (3^3+ 3)/3 + (3^2+3^2)/3^2 = 31 Dec 2020, 03:28
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((27+3)/3) + ((9+9)/3)
=(30/3)+(18/9)
=10+2=12

Answer C

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GMAT Club Around The World!!! (3^3+ 3)/3 + (3^2+3^2)/3^2 = 31 Dec 2020, 03:39
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((3^3 + 3) /3 ) + (3^2 + 3^2 /3^2) = 10 + 2 = 12

so answer is c) 12
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GMAT Club Around The World!!! (3^3+ 3)/3 + (3^2+3^2)/3^2 = 31 Dec 2020, 04:15
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\(3^3\)+3/3 = 27+3/3=10
\(3^2\)+\(3^2\)/\(3^2\) = 9+9/9 = 2

10+2=12

IMO Option C
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GMAT Club Around The World!!! (3^3+ 3)/3 + (3^2+3^2)/3^2 = 31 Dec 2020, 04:27
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IMO C

After Simplification we get

10 + 2 = 12
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GMAT Club Around The World!!! (3^3+ 3)/3 + (3^2+3^2)/3^2 = 31 Dec 2020, 05:24
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The question is equal to :

(3^4+3^2+3^2+3^2)/3^2-->3^2(3^2+3)/3^2-->9+3-->12

PUSH C
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GMAT Club Around The World!!! (3^3+ 3)/3 + (3^2+3^2)/3^2 = 31 Dec 2020, 06:21
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The answer is C

(3^3+ 3)/3 + (3^2+3^2)/3^2 = (3^2 + 1) + (1+1) = 12
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GMAT Club Around The World!!! (3^3+ 3)/3 + (3^2+3^2)/3^2 = 31 Dec 2020, 07:50
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IMO C

\(\frac{(3^3+3)}{3} + \frac{(3^2+3^2)}{3^2}\)
= \(3^2\) + 1 + 1 + 1
= 12
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GMAT Club Around The World!!! (3^3+ 3)/3 + (3^2+3^2)/3^2 = 31 Dec 2020, 08:34
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IMO C
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GMAT Club Around The World!!! (3^3+ 3)/3 + (3^2+3^2)/3^2 = 31 Dec 2020, 11:22
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(3^3 +3)/2+(3^2+3^2)/3^2= 10+2 =12.

So, It is C. :)
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GMAT Club Around The World!!! (3^3+ 3)/3 + (3^2+3^2)/3^2 = 31 Dec 2020, 16:03
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IMO:C -12
(3^3 + 3)/3 +( 3^2 +3^2)/3^2
By simplifying we get (3^2 + 1) + (1+1) = 12
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GMAT Club Around The World!!! (3^3+ 3)/3 + (3^2+3^2)/3^2 = 31 Dec 2020, 21:17
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(3^3+3)/3+ (3^2+3^2)/3^2=

(3^3+3)/3 + (3^2+3^2)/3^2
= (27+3)/3 + 9+9/9
=30/3 + 18/9
= 10 + 2
=12
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GMAT Club Around The World!!! (3^3+ 3)/3 + (3^2+3^2)/3^2 = 01 Jan 2021, 07:29
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Correct answer C
it's easy but if go by the process

3 (3^2 +1)/3 + 2* 3^2/3^2
= 10 + 2
=12
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GMAT Club Around The World!!! (3^3+ 3)/3 + (3^2+3^2)/3^2 = 01 Jan 2021, 07:47
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Imo-C

3^3 +3=27+3= 30
3^2+3^2= 18
3^2=9

30/3 +18/9
=10+2
=12

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GMAT Club Around The World!!! (3^3+ 3)/3 + (3^2+3^2)/3^2 = 02 Jan 2021, 17:54
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(3^3+3)/3 + (3^2+3^2)/3^2
3(3^2+1)/3 + 2*3^2/3^2
3^2+1+2
9+1+2
12
The answer will be C
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GMAT Club Around The World!!! (3^3+ 3)/3 + (3^2+3^2)/3^2 = 03 Jan 2021, 04:07
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Bunuel
\(\frac{3^3+ 3}{3} + \frac{3^2+3^2}{3^2} =\)

A. 1
B. 5
C. 12
D. 17
E. 30



Happy New Year Chatham Islands/New Zealand!

Dec 31 Event: GMAT Club Around The World!
(38 new questions posted every hour time zone on Dec 31!)

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After simplifying the expression, following expression comes:

3^2 + 1 + 1 + 1 = 12

Option C is the answer IMO.
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GMAT Club Around The World!!! (3^3+ 3)/3 + (3^2+3^2)/3^2 = 03 Jan 2021, 04:22
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\(\frac{3^{3}+3}{3}\)+\(\frac{3^2+3^2}{3^{2}}\)

\(\frac{3^{3}}{3}\)+\(\frac{3}{3}\)+\(\frac{3^{2}}{3^{2}}\)+\(\frac{3^{2}}{3^{2}}\)

\(3^{3-1}\)+\(1+3^{2-2}+3^{2-2}\) => 9+1+1+1 => 12.

The OA is
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