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sherxon
Joined: 28 May 2021
Last visit: 22 Aug 2026
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Location: Uzbekistan
Concentration: Strategy, General Management
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GMAT 1: 740 Q50 V40
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Schools: Carlson (A$$$) Kenan-Flagler '25 (A$$$$) Goizueta '25 (A$$$) Olin '25 (A$$$$) Fuqua '25 (M$$$$) Marshall '25 (A$$$$)
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Posts: 130
02 Jun 2021, 02:47
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
64% (01:56) correct
36%
(02:29)
wrong
based on 506
sessions
History
Date
Time
Result
Not Attempted Yet
The fruit in a box weighs a ton and has a moisture content of 82.0%. After some time under the sun, moisture content has dropped to 70%. What is the current weight of the fruit in kg?
A. 810
B. 900
C. 600
D. 720
E. 780
A. 810
B. 900
C. 600
D. 720
E. 780
02 Jun 2021, 04:01
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sherxon
The weight of moisture is 82% of 1 ton or 1000kg, that is 82*1000/100=820kg.
Weight of the remaining portion =1000-720=180. Now this remains constant in weight even after moisture reduces, but now becomes 100-70 or 30% overall.
So 180=30% of new weight. Thus new weight = 180*100/30=600
C
General Discussion
02 Jun 2021, 09:26
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Given: The fruit in a box weighs a ton and has a moisture content of 82.0%. After some time under the sun, moisture content has dropped to 70%.
Asked: What is the current weight of the fruit in kg?
Before evaporation: -
Weight = 1000 kg
Moisture = 820 kg
Other = 180 kg
After evaporation: -
Other = 180 kg
Weight = 180/30% = 18000/30 = 600 kg
IMO C
Asked: What is the current weight of the fruit in kg?
Before evaporation: -
Weight = 1000 kg
Moisture = 820 kg
Other = 180 kg
After evaporation: -
Other = 180 kg
Weight = 180/30% = 18000/30 = 600 kg
IMO C
