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the language of the question statement is tricky.
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Hi Marty,

How are you calculating the median method?
MartyMurray
In a music contest, a panel of 100 audience members ranked each of 4 performers with integer ranks—from 1 to 4. For each performer, the table indicates the number of audience members who assigned each rank to the given performer. For example, exactly 49 audience members assigned rank 4 to Performer A. Two methods—the Mode Method and the Median Method—are used to assign final ranks to the performers based on these audience rankings.

Mode Method: Assign to each performer a final rank equal to the audience rank the performer received most often.

Median Method: Compute the median audience ranking for each performer. The ordering of the final rankings will be the same as the ordering of these medians.

­
Rank
Performer1234
A510049
B235720
C59500
D2102851
(Sort ↕ the table by clicking on the headers)­
________________________________________________________________
For each of the following final ranks, select Same if the two final ranking methods assigned the same performer the given rank. Otherwise, select Not same.


Rank 1

Using the mode method for Rank 1, we see that the only performer who received Rank 1 most often was Performer A, who received Rank 1 from 51 audience members.

Also, the median ranking for Performer A was Rank 1 since over half of Performer A's rankings were Rank 1, so the middle ranking for Performer A was Rank 1. Also, no other performer had a median ranking of Rank 1.

So, Performer A was assigned Rank 1 both ways.

Select Same.

Rank 2

Using the mode method for Rank 2, we see that the only performer who received Rank 2 most often was Performer C, who received Rank 2 from 95 audience members.

Also, the median ranking for Performer C was Rank 2 since over half of Performer C's rankings were Rank 2, so the middle ranking for Performer C was Rank 2. Also, no other performer had a median ranking of Rank 2.

So, Performer C was assigned Rank 2 both ways.

Select Same.

Rank 3

Using the mode method for Rank 3, we see that the only performer who received Rank 3 most often was Performer B, who received Rank 3 from 7 2 audience members.

Also, the median ranking for Performer B was Rank 3 since over half of Performer B's rankings were Rank 3, so the middle ranking for Performer B was Rank 3. Also, no other performer had a median ranking of Rank 3.

So, Performer B was assigned Rank 3 both ways.

Select Same.

Correct answer: Same, Same, Same­
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To calculate median you take every data point and order it from least to greatest. You then find the middle of the ordered data set and that number is the median.

For example: 1,3,6,1,8,2,4
Ordered: 1,1,2,3,4,6,8
Median is 3 because it is the midpoint in the dataset.


In this case, take performer A for instance:

He had 51 ratings for rank 1 and 49 for rank 4.

If we ordered them all: 1,1,1,1,1,1.....4,4,4,4,4,4 the middle data point would be 1, as he received more than half rank 1 ratings.
Therefore his median ranking is 1

AditiDeokar
Hi Marty,

How are you calculating the median method?
MartyMurray
In a music contest, a panel of 100 audience members ranked each of 4 performers with integer ranks—from 1 to 4. For each performer, the table indicates the number of audience members who assigned each rank to the given performer. For example, exactly 49 audience members assigned rank 4 to Performer A. Two methods—the Mode Method and the Median Method—are used to assign final ranks to the performers based on these audience rankings.

Mode Method: Assign to each performer a final rank equal to the audience rank the performer received most often.

Median Method: Compute the median audience ranking for each performer. The ordering of the final rankings will be the same as the ordering of these medians.

­
Rank
Performer1234
A510049
B235720
C59500
D2102851
(Sort ↕ the table by clicking on the headers)­
________________________________________________________________
For each of the following final ranks, select Same if the two final ranking methods assigned the same performer the given rank. Otherwise, select Not same.


Rank 1

Using the mode method for Rank 1, we see that the only performer who received Rank 1 most often was Performer A, who received Rank 1 from 51 audience members.

Also, the median ranking for Performer A was Rank 1 since over half of Performer A's rankings were Rank 1, so the middle ranking for Performer A was Rank 1. Also, no other performer had a median ranking of Rank 1.

So, Performer A was assigned Rank 1 both ways.

Select Same.

Rank 2

Using the mode method for Rank 2, we see that the only performer who received Rank 2 most often was Performer C, who received Rank 2 from 95 audience members.

Also, the median ranking for Performer C was Rank 2 since over half of Performer C's rankings were Rank 2, so the middle ranking for Performer C was Rank 2. Also, no other performer had a median ranking of Rank 2.

So, Performer C was assigned Rank 2 both ways.

Select Same.

Rank 3

Using the mode method for Rank 3, we see that the only performer who received Rank 3 most often was Performer B, who received Rank 3 from 7 2 audience members.

Also, the median ranking for Performer B was Rank 3 since over half of Performer B's rankings were Rank 3, so the middle ranking for Performer B was Rank 3. Also, no other performer had a median ranking of Rank 3.

So, Performer B was assigned Rank 3 both ways.

Select Same.

Correct answer: Same, Same, Same­
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One way to solve this, determine what Mode and Median rank each performer is being assigned.

Like A, Mode rank: 1 , Median Rank:1
B, Mode rank:....

You will see there is no conflict and using both systems same ranks are being assigned hence Same for all the choices.
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MartyMurray

While the answer will remain the same, by Mode method I understood that from the ranks let's say A has gotten, which one has he gotten the most times is the Mode rank. So since A got Rank 1 51 times, that is the answer. Could you please clarigy - will be helpful for other questions with similar wordings
MartyMurray
In a music contest, a panel of 100 audience members ranked each of 4 performers with integer ranks—from 1 to 4. For each performer, the table indicates the number of audience members who assigned each rank to the given performer. For example, exactly 49 audience members assigned rank 4 to Performer A. Two methods—the Mode Method and the Median Method—are used to assign final ranks to the performers based on these audience rankings.

Mode Method: Assign to each performer a final rank equal to the audience rank the performer received most often.

Median Method: Compute the median audience ranking for each performer. The ordering of the final rankings will be the same as the ordering of these medians.

­
Rank
Performer1234
A510049
B235720
C59500
D2102851
(Sort ↕ the table by clicking on the headers)­
________________________________________________________________
For each of the following final ranks, select Same if the two final ranking methods assigned the same performer the given rank. Otherwise, select Not same.


Rank 1

Using the mode method for Rank 1, we see that the only performer who received Rank 1 most often was Performer A, who received Rank 1 from 51 audience members.

Also, the median ranking for Performer A was Rank 1 since over half of Performer A's rankings were Rank 1, so the middle ranking for Performer A was Rank 1. Also, no other performer had a median ranking of Rank 1.

So, Performer A was assigned Rank 1 both ways.

Select Same.

Rank 2

Using the mode method for Rank 2, we see that the only performer who received Rank 2 most often was Performer C, who received Rank 2 from 95 audience members.

Also, the median ranking for Performer C was Rank 2 since over half of Performer C's rankings were Rank 2, so the middle ranking for Performer C was Rank 2. Also, no other performer had a median ranking of Rank 2.

So, Performer C was assigned Rank 2 both ways.

Select Same.

Rank 3

Using the mode method for Rank 3, we see that the only performer who received Rank 3 most often was Performer B, who received Rank 3 from 7 2 audience members.

Also, the median ranking for Performer B was Rank 3 since over half of Performer B's rankings were Rank 3, so the middle ranking for Performer B was Rank 3. Also, no other performer had a median ranking of Rank 3.

So, Performer B was assigned Rank 3 both ways.

Select Same.

Correct answer: Same, Same, Same­
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As mode is defined as mode is the value that appears the most in a data set.

Accordingly for each speaker, as you pointed for A ; rank 1 it. is.
soumyab12
MartyMurray

While the answer will remain the same, by Mode method I understood that from the ranks let's say A has gotten, which one has he gotten the most times is the Mode rank. So since A got Rank 1 51 times, that is the answer. Could you please clarigy - will be helpful for other questions with similar wordings

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MODE METHOD = Which rank did the performer receive MOST OFTEN?
Look at each performer's row and find the highest number - that column header is their Mode rank.

From the table:
- Performer A: 51 votes for Rank 1 (highest) → Mode Rank = 1
- Performer B: 72 votes for Rank 3 (highest) → Mode Rank = 3
- Performer C: 95 votes for Rank 2 (highest) → Mode Rank = 2
- Performer D: 51 votes for Rank 4 (highest) → Mode Rank = 4

MEDIAN METHOD = The middle value when all 100 votes are arranged in order.
With 100 votes, the median is between the 50th and 51st vote.

For Performer A:
- 51 people gave Rank 1, 49 people gave Rank 4
- Votes in order: 1,1,1...(51 times)...4,4,4...(49 times)
- The 50th and 51st votes are both Rank 1 → Median = 1

For Performer C:
- 5 people gave Rank 1, 95 people gave Rank 2
- After the first 5 votes (all 1s), the 50th and 51st are both Rank 2 → Median = 2

For Performer B:
- 23 gave Rank 1, 5 gave Rank 2, 72 gave Rank 3
- Cumulative: 23 + 5 = 28 votes before Rank 3
- The 50th and 51st votes fall in Rank 3 → Median = 3

For Performer D:
- 21 gave Rank 1, 28 gave Rank 3, 51 gave Rank 4
- Cumulative: 21 + 28 = 49 votes before Rank 4
- The 50th and 51st votes are Rank 4 → Median = 4

COMPARING RESULTS:
Final RankMode MethodMedian MethodMatch?
Rank 1AASAME
Rank 2CCSAME
Rank 3BBSAME

Answer: Same, Same, Same

soumyab12
MartyMurray

While the answer will remain the same, by Mode method I understood that from the ranks let's say A has gotten, which one has he gotten the most times is the Mode rank. So since A got Rank 1 51 times, that is the answer. Could you please clarigy - will be helpful for other questions with similar wordings

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