IMO D1. Single-Digit Numbers (1 to 9):
• There are 9 single-digit numbers.
• Total digits contributed: 9×1=9
2. Two-Digit Numbers (10 to 99):
• There are 99−10+1=90 two-digit numbers.
• Total digits contributed: 90×2=180
3. Three-Digit Numbers (100 to 999):
• There are 999−100+1=900three-digit numbers.
• Total digits contributed: 900×3=2700
Cumulative Digits:
• Digits from single-digit numbers: 9
• Digits from two-digit numbers: 180
• Digits from three-digit numbers: 2700
Finding the 341st Digit:
• Digits from single-digit numbers: 9
• Digits from two-digit numbers: 180
• Total digits from single and two-digit numbers: 9+180=189
Since 341 is greater than 189, the 341st digit is within the three-digit numbers.
Calculating the Position in Three-Digit Numbers:
• Digits needed beyond the first 189 digits: 341−189=152
• Each three-digit number contributes 3 digits.
• Number of complete three-digit numbers contributing to the 152 digits: ⌊152/3⌋=50complete three-digit numbers.
• Digits contributed by these 50 three-digit numbers: 50×3=150
• Remaining digits needed: 152−150=2
Identifying the Specific Number and Digit:
• The 50th three-digit number starting from 100 is 100+50−1=149
• The first digit of the next number (150) will be the 151st digit.
• The second digit of 150 will be the 152nd digit.
Thus, the 341st digit in the sequence is the second digit of 150, which is 5.