"The combined time Anton and Beatrice took to finish the race was exactly 3 hours longer than the time Carl took." -> T_A + T_B = T_C +3
D = RT, D = 30 km
T_A = 30/R_A, T_B = 30/R_B, T_AC = 30/R_C
Question : "Did Carl win the race?" -> T_C < T_A AND T_C < T_B ?
"(1) None of the three ran faster than 6 kilometers per hour."
Let's check for 1 one extreme: Anton and Beatrice at 6 KpH:
R_A = R_B = 6km/1h
T_A + T_B = 30/R_A + 30/R_B = 30/6 + 30/6 = 5+5=10
T_A + T_B = T_C +3 - > T_C = T_A + T_B - 3 = 10-3=7
T_A = T_B = 5 h < T_C = 7h
Now Let's check for 1 one other extreme: Anton at 6 KpH and and Beatrice at 1 KpH:
T_A + T_B = 30/R_A + 30/R_B = 30/6 + 30/1 = 5+30=35
T_A + T_B = T_C +3 - > T_C = T_A + T_B - 3 = 35-3=32
T_A = 5 h < T_C = 32h AND T_B = 30h < T_C = 32h
Now Let's check for the last extreme: Anton at 1 KpH and and Beatrice at 1 KpH:
T_A + T_B = 30/R_A + 30/R_B = 30/1 + 30/1 = 30+30=60
T_A + T_B = T_C +3 - > T_C = T_A + T_B - 3 = 60-3=57
T_A = 30 h < T_C = 32h AND T_B = 30h < T_C = 57h
Answer choice A is sufficient - > Eliminate Answer choices B, C and E.
"(2) Anton finished before Beatrice."
First extreme case:
Anton finished 1 nanoseconde before Beatrice -> T_A almost equal T_B:
T_A + T_B = T_C +3 ->T_A + T_A = T_C +3 -> 2*T_A = T_C +3
T_A = (2T_C + 3)/2
If T_C < T_A then :
T_C < (2T_C + 3)/2 -> 2* T_C < T_C +3 -> T_C < 3h.
T_C = 1h:
T_A + T_A = T_C +3 -> 2* T_A = 4 -> T_A = T_B = 2h so T_C < T_A and T_B
T_C = 3h minus 0.1 second):
A + T_A = T_C +3 -> 2* T_A = 6 (minus 0.1 second) -> 2* T_A = 5.99 h -> T_A = T_B = 5.99h/ 2 = 2.995h so T_C > T_A and T_B
Second extreme case:
Anton finished 100 hours before Beatrice -> T_B = T_A + 100
T_A + T_B = T_C +3 -> T_A + T_A +100 = T_C +3 -> T_C = 2*T_A
+ 97
If we want T_C<T_A - > 2*T_A + 97 < T_A -> T_A < -97 -> IMPOSSIBLE
-> Not sufficient -> Eliminate Answer choice D
Answer choice A.