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04 Jul 2025, 08:59
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Bunuel
Rate of thor = \(\frac{k}{m}\)
Rate of loki = \(\frac{k}{n}\)
Difference in rate = \(\frac{k}{m} - \frac{k}{n}\)
If Both start drinking together 2k liters of beer, the time they would take = \(\frac{2k}{ \frac{k}{m} - \frac{k}{n}}\)
Extra beer that thor drinks = difference in rate * time
= \( \frac{k}{m} - \frac{k}{n} * \frac{2k}{ \frac{k}{m} - \frac{k}{n}}\)
= \(\frac{nk-mk}{mn} * \frac{2k*mn}{mk+nk}\)
= \(\frac{2k*(n-m)}{(n+m)}\)
Option C
04 Jul 2025, 09:04
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Hi,
Here is my approach to solve this question.
Given:
Thor rate = k/m L per min
Loki rate = k/n L per min
Now they need to consume 2k L together. And then we need to find the difference in amount they drank.
As soon as I read this, I can think of them as a relative speed question.
Imagine Thor and Loki start running towards each other with their respective speeds as k/m and k/n, total distance they need to cover is 2k.
So, time at which they will meet would be = total distance / relative speed
Total distance = 2k
Relative Speed = k/m + k/n
Time (t) = 2k / ( k/m + k/n) = 2mn/(m+n)
Distance Thor travelled would be = speed * time = k/m * 2mn/(m+n) = 2kn/(m+n)
Distance Loki travelled would be = speed * time = k/n * 2mn/(m+n) = 2km/(m+n)
Difference in distance or Difference in amount they drank = 2kn/(m+n) - 2km/(m+n) = 2k(n-m)/(n+m)
Hence Answer is C
Here is my approach to solve this question.
Given:
Thor rate = k/m L per min
Loki rate = k/n L per min
Now they need to consume 2k L together. And then we need to find the difference in amount they drank.
As soon as I read this, I can think of them as a relative speed question.
Imagine Thor and Loki start running towards each other with their respective speeds as k/m and k/n, total distance they need to cover is 2k.
So, time at which they will meet would be = total distance / relative speed
Total distance = 2k
Relative Speed = k/m + k/n
Time (t) = 2k / ( k/m + k/n) = 2mn/(m+n)
Distance Thor travelled would be = speed * time = k/m * 2mn/(m+n) = 2kn/(m+n)
Distance Loki travelled would be = speed * time = k/n * 2mn/(m+n) = 2km/(m+n)
Difference in distance or Difference in amount they drank = 2kn/(m+n) - 2km/(m+n) = 2k(n-m)/(n+m)
Hence Answer is C
Emkicheru
Joined: 12 Sep 2023
Last visit: 12 Sep 2025
Posts: 119
Given Kudos: 11
Location: Kenya
Schools: Anderson (UCLA) Sloan (MIT) Columbia '27
GMAT 1: 780 Q50 V48
GRE 1: Q167 V164
GPA: 3.7
04 Jul 2025, 09:07
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Bunuel
Thor speed is K/m,Loki speed is K/n therefore total consumption is 1/m*2K+1/n*2K
2K(1/m+1/n)
Thor is faster therefore time is les
2K(n-m)/m+n is what Thor drink more than
