Last visit was: 07 Sep 2026, 22:54 It is currently 07 Sep 2026, 22:54
Home
Messages
Tests
Schools
Events
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel
Back to Forum
Create Topic
   1   2   3   4   
805+ (Hard)|   Math Related|         
User avatar
ajain31
User avatar
Joined: 09 Nov 2024
Last visit: 07 Sep 2026
Posts: 70
Own Kudos:
57
 [1]
Given Kudos: 69
Location: United Kingdom
Schools: Wharton '27 Stanford '27 HBS '27 CBS '27
GPA: 71%
Schools: Wharton '27 Stanford '27 HBS '27 CBS '27
Posts: 70
Kudos: 57
 [1]
GMAT Club World Cup 2026 (Day 9): A plant uses the same group of 17 Jul 2026, 00:04
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
let there be n workers and let each worker produce u units per shift

every worker works one shift each day, total product from both shifts over 4 days is, 4Nu

conutngin evening shift workers(helps to draw a mini table on your scratch pad)

D Morning workers evening workers
1 N 0
2 2N/ N/3
3 4N/9 5N/9
4 8N/27 19N/27

total number of evening worker shifts is:
0 +N/3 + 5N/9 +19N/27

= 43N/27

total evening prod is
43Nu/27

ration is 43Nu/27/4Nu = 43/108

86/216 = 23/108

evening shift is 86
both shifts is 216
User avatar
vasu1104
User avatar
Joined: 10 Feb 2023
Last visit: 07 Sep 2026
Posts: 733
Own Kudos:
422
Given Kudos: 672
Location: Canada
Products:
GMAT Club Tests Forum Quiz
Posts: 733
Kudos: 422
GMAT Club World Cup 2026 (Day 9): A plant uses the same group of 17 Jul 2026, 00:53
Kudos
Add Kudos
Bookmarks
Bookmark this Post
total P people.

1st day morning = p, evening = 0
2nd day, morning= 2p/3, evening = p/3
3rd day, morning= 4p/9, evening = 2p/9+p/3 = 5p/9
4th day , morning= 8p/27, evening= 4p/27+2p/9+p/3 = 19p/27

total work on evening for 4 days= p/3+5p/9+19p/27 = 43p/27
so p must be multiple of 27. and when p = 52, work done = 86.

now total work in both shift.
morning = p+2p/3+4p/9+8p/27 = 38p/27
evening = 43p/27

total = 81p/27

so total work must be multiple of 81. and from choice its 162.

evening = 86
both = 162

Bunuel
A plant uses the same group of workers for a 4 day production run. Each worker works one shift per day, either the morning shift or the evening shift, and each worker produces the same number of units in any shift worked.

On Day 1, all workers work the morning shift. Once a worker is assigned to the evening shift, that worker remains on the evening shift for the rest of the production run. On Day 2, one third of the workers who worked the morning shift on Day 1 are assigned to the evening shift. On Day 3, one third of the workers who worked the morning shift on Day 2 are assigned to the evening shift. On Day 4, one third of the workers who worked the morning shift on Day 3 are assigned to the evening shift.

Select for Evening Shift the possible total number of units produced by the evening shift over the four days, and select for Both Shifts the possible total number of units produced by both shifts together over the four days, that would be jointly consistent with the given information. Make only two selections, one in each column.
Show more
User avatar
GamePine
User avatar
Joined: 31 May 2026
Last visit: 04 Aug 2026
Posts: 61
Own Kudos:
55
 [1]
Given Kudos: 1
GMAT Focus 1: 645 Q79 V85 DI82
GMAT Focus 1: 645 Q79 V85 DI82
Posts: 61
Kudos: 55
 [1]
GMAT Club World Cup 2026 (Day 9): A plant uses the same group of 17 Jul 2026, 01:02
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Every worker works one shift so total shifts = 4x where x is the number of workers. Then it needs to be multiplied by the number of units per shift to get total units. I set units per shift to y so 4xy = total units for both shifts.

Day 1 - x workers work the morning shift since they all did that day

Day 2 - 1/3 of morning workers move to evening so x/3 = evening and 2x/3 - morning. Since x must be a whole number this tells us that x must be divisible by 3

Day 3 1/3 of remaining morning moves to evening so (1/3)*(2x/3) = 2x/9, so x must be divisible by 9

Day 4 1/3 of remaining move to evening (1/3)*(2x/9) = 2x/27, x is divisible by 27.

total evening shift workers = Day 1 +Day 2 + Day 3 + Day 4 = 43x/27, so total units is y. We can set x to 27k where k is a constant because we know that x must be a multiple of 27 so we get 43ky units

Then for both shifts we had the unit formula at 4xy. We know x is a multiple of 27 so sub 27k you get 108ky where y is units.

We can then test different values of y. When y = 2, Both = 216k and evening =86k so i got 216 for both and 86 for evening.
User avatar
DishaSaha
User avatar
Joined: 03 Nov 2024
Last visit: 30 Aug 2026
Posts: 64
Own Kudos:
49
 [1]
Given Kudos: 24
GMAT Focus 1: 555 Q81 V75 DI78
GMAT Focus 1: 555 Q81 V75 DI78
Posts: 64
Kudos: 49
 [1]
GMAT Club World Cup 2026 (Day 9): A plant uses the same group of 17 Jul 2026, 01:25
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
MSESTotalProduct produced
Day1x(say)0xxa (a=product by each worker)
Day22x/3x/3xxa
Day34x/9x/3 + 2x/9xxa
Day48x/27x/3 +2x/9 + 4x/27xxa
PR65x/27x/3+x/3+ 2x/9 +x/3+ 2x/9 +4x/27=43x/27108x/27108xa/27

.: Total no of units produced by the evening shift over 4 days should be multiple of 43.
.: 86 satisfies the condistion.
.: Evening shift=86

.: Total no of units produced during both the shifts, should be multiple of 108 and xa has to be (2*27) to be consistent with the another option.
.: Both=216
Bunuel
A plant uses the same group of workers for a 4 day production run. Each worker works one shift per day, either the morning shift or the evening shift, and each worker produces the same number of units in any shift worked.

On Day 1, all workers work the morning shift. Once a worker is assigned to the evening shift, that worker remains on the evening shift for the rest of the production run. On Day 2, one third of the workers who worked the morning shift on Day 1 are assigned to the evening shift. On Day 3, one third of the workers who worked the morning shift on Day 2 are assigned to the evening shift. On Day 4, one third of the workers who worked the morning shift on Day 3 are assigned to the evening shift.

Select for Evening Shift the possible total number of units produced by the evening shift over the four days, and select for Both Shifts the possible total number of units produced by both shifts together over the four days, that would be jointly consistent with the given information. Make only two selections, one in each column.
Show more
User avatar
twinkle2311
User avatar
Joined: 05 Nov 2021
Last visit: 07 Sep 2026
Posts: 211
Own Kudos:
247
 [1]
Given Kudos: 54
Location: India
Concentration: Finance, Real Estate
Schools: ISB '27 Wharton '27
GPA: 9.041
Products:
Forum Quiz
Schools: ISB '27 Wharton '27
Posts: 211
Kudos: 247
 [1]
GMAT Club World Cup 2026 (Day 9): A plant uses the same group of 17 Jul 2026, 01:55
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Let the total no. of workers be N, and let each worker produce k units/shift.

No. of workers on the evening shift each day is:
Day 1 : 0
Day 2 : N/3
Day 3 : N/3 + 2N/9 = 5N/9
Day 4 : 5N/9 + 4N/27 = 19N/27

So the total evening production over the 4 days is kN (1/3 + 5/9 + 19/27) = 43kN/27

Total production by both shifts over the 4 days is = 4kN

Let kN = T. Then evening shift = 43T/27 and both shifts = 4T

T must be a must be a multiple of 27 for evening production to be an integer. So both shifts can only be 108 or 216.

If both shifts = 108, then T = 27 and Evening shift = 43 (not an option)
If both shifts = 216, then T = 54 and Evening Shift = 86

Ans : Evening Shift = 86 and Both Shifts = 216
User avatar
GreenPill
User avatar
Joined: 13 Jun 2026
Last visit: 07 Sep 2026
Posts: 37
Own Kudos:
25
 [1]
Products:
Forum Quiz
Posts: 37
Kudos: 25
 [1]
GMAT Club World Cup 2026 (Day 9): A plant uses the same group of 17 Jul 2026, 02:57
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
A plant uses the same group of workers for a 4 day production run. Each worker works one shift per day, either the morning shift or the evening shift, and each worker produces the same number of units in any shift worked.

On Day 1, all workers work the morning shift. Once a worker is assigned to the evening shift, that worker remains on the evening shift for the rest of the production run. On Day 2, one third of the workers who worked the morning shift on Day 1 are assigned to the evening shift. On Day 3, one third of the workers who worked the morning shift on Day 2 are assigned to the evening shift. On Day 4, one third of the workers who worked the morning shift on Day 3 are assigned to the evening shift.

Select for Evening Shift the possible total number of units produced by the evening shift over the four days, and select for Both Shifts the possible total number of units produced by both shifts together over the four days, that would be jointly consistent with the given information. Make only two selections, one in each column.
Show more
on day1 let x workers working in morning shift.
on day 2 morn= 2x/3 even = x/3
on day3 morn = 4x/9 even = 5x/9
on day4 morn = 8x/27 even = 19x/27
total even prod = 43x/27
for both shift = 4x
now from options only one pair is suitable 86 and 216
User avatar
patnaik1988
User avatar
Joined: 05 Oct 2024
Last visit: 07 Sep 2026
Posts: 84
Own Kudos:
19
 [1]
Given Kudos: 68
Posts: 84
Kudos: 19
 [1]
GMAT Club World Cup 2026 (Day 9): A plant uses the same group of 17 Jul 2026, 03:08
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Let no. of workers = x ; Let number of units produced/shift/worker = n ; Lets denote Morning Shift as M ; Evening shift as E
Day1 : M produce 'xn' units and E = 0;
Day2 : M= 2xn/3 ; E=xn/3 (as 1/3rd workers got shifted to E)
Day3 : M= 4xn/9 ; E= 5xn/9 (as 1/3rd workers got shifted to E)
Day4 : m= 8xn/27 ; E=19xn/27 (as 1/3rd workers shifted to E)
Total E = 0 + xn/3 + 5xn/9 + 19xn/27 = 43xn/27
Total 2 shifts = M + E = xn + 2xn/3 + 4xn/9 + 8xn/27 + 43xn/27 = 108xn/27

Ratio of Units produced is 108 : 43 ; From option choice Total 2 shifts =216 and Evening shift = 86 satisfies the Ratio.
Bunuel
A plant uses the same group of workers for a 4 day production run. Each worker works one shift per day, either the morning shift or the evening shift, and each worker produces the same number of units in any shift worked.

On Day 1, all workers work the morning shift. Once a worker is assigned to the evening shift, that worker remains on the evening shift for the rest of the production run. On Day 2, one third of the workers who worked the morning shift on Day 1 are assigned to the evening shift. On Day 3, one third of the workers who worked the morning shift on Day 2 are assigned to the evening shift. On Day 4, one third of the workers who worked the morning shift on Day 3 are assigned to the evening shift.

Select for Evening Shift the possible total number of units produced by the evening shift over the four days, and select for Both Shifts the possible total number of units produced by both shifts together over the four days, that would be jointly consistent with the given information. Make only two selections, one in each column.
Show more
User avatar
Amity007
User avatar
Joined: 12 Sep 2025
Last visit: 07 Sep 2026
Posts: 266
Own Kudos:
493
 [1]
Given Kudos: 1,866
Location: India
Schools: ISB
Products:
GMAT Club Tests
Schools: ISB
Posts: 266
Kudos: 493
 [1]
GMAT Club World Cup 2026 (Day 9): A plant uses the same group of 17 Jul 2026, 03:12
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
day 1 => morning ->x | evening -> 0
day 2=> morming -> (2/3)x | evening -> (1/3)x
day 3 => morning -> (4/9)x | evening -> (1/3)x + 2/9 x = 5/9 x
day 4 => morning -> (8/27)x | evening-> (1/3)x + (2/9)x + (4/27)x = 19/27 x

now lets total it.
Evening = 1/3 x + 5/9 x + 19/27 x = 9/27 + 15/27 + 19/27 = 43/27 x
Total all =. 4x

So the ration of evening/ total = (43/27)/4 = 43/108

the only options satisfy this relation is 86 and 216. Exactly double.
Evening - 86
Total - 216.


Bunuel
A plant uses the same group of workers for a 4 day production run. Each worker works one shift per day, either the morning shift or the evening shift, and each worker produces the same number of units in any shift worked.

On Day 1, all workers work the morning shift. Once a worker is assigned to the evening shift, that worker remains on the evening shift for the rest of the production run. On Day 2, one third of the workers who worked the morning shift on Day 1 are assigned to the evening shift. On Day 3, one third of the workers who worked the morning shift on Day 2 are assigned to the evening shift. On Day 4, one third of the workers who worked the morning shift on Day 3 are assigned to the evening shift.

Select for Evening Shift the possible total number of units produced by the evening shift over the four days, and select for Both Shifts the possible total number of units produced by both shifts together over the four days, that would be jointly consistent with the given information. Make only two selections, one in each column.
Show more
User avatar
jkkamau
User avatar
Joined: 25 May 2020
Last visit: 07 Sep 2026
Posts: 285
Own Kudos:
244
 [1]
Given Kudos: 147
Location: Kenya
Schools: Jones '26 (A$$)
GMAT 1: 730 Q50 V46
GPA: 3.5
Products:
GMAT Club Tests Forum Quiz
Schools: Jones '26 (A$$)
GMAT 1: 730 Q50 V46
Posts: 285
Kudos: 244
 [1]
GMAT Club World Cup 2026 (Day 9): A plant uses the same group of 17 Jul 2026, 03:18
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Since get pulled off in thirds three times then we can safely say the total is a multiple of 27 so 27K
Looking at the evening shifts from day 1 equals 0
Day 2: Total/3= 27K/3= 9K
Day 3: A third of the remaining in Day 2 27k-9k= 18k/3= 6k+9k= 15k
Day 4; A third of the remaining 27K-15K=12K/3= 4K+15K= 19K
Evening total is 9K+15K+19K= 43K Meaning evening is a factor of 43. We only have 86 as the suitable number
For total is 27kx4= 108k meaning total is a factor of 108 meaning we only have 216 as the suitable number
(86,216)
Bunuel
A plant uses the same group of workers for a 4 day production run. Each worker works one shift per day, either the morning shift or the evening shift, and each worker produces the same number of units in any shift worked.

On Day 1, all workers work the morning shift. Once a worker is assigned to the evening shift, that worker remains on the evening shift for the rest of the production run. On Day 2, one third of the workers who worked the morning shift on Day 1 are assigned to the evening shift. On Day 3, one third of the workers who worked the morning shift on Day 2 are assigned to the evening shift. On Day 4, one third of the workers who worked the morning shift on Day 3 are assigned to the evening shift.

Select for Evening Shift the possible total number of units produced by the evening shift over the four days, and select for Both Shifts the possible total number of units produced by both shifts together over the four days, that would be jointly consistent with the given information. Make only two selections, one in each column.
Show more
User avatar
Praful_0810
User avatar
Joined: 08 Jul 2023
Last visit: 07 Sep 2026
Posts: 36
Own Kudos:
14
 [1]
Given Kudos: 18
Location: India
GMAT Focus 1: 585 Q82 V75 DI80
GMAT 1: 550 Q47 V23
GMAT Focus 1: 585 Q82 V75 DI80
GMAT 1: 550 Q47 V23
Posts: 36
Kudos: 14
 [1]
GMAT Club World Cup 2026 (Day 9): A plant uses the same group of 17 Jul 2026, 04:19
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
We are given that a group of workers, having same rate of work, work 4 days either in evening or morning shift. Also, once a worker is assigned to the evening shift, that worker remains on the evening shift for rest of the days.

Also note that after Day1, around one-third of the workers from morning shift are assigned to evening shift and that too happened three consecutive days.

Lets assume that total work done by a group is 3*3*3 = 27X
So Days; Morning; Evening Total works
D1 M= 27x E = 0 Both = 27x
D2 M= 18x E = 9x Both = 27x
D3 M= 12x E = 9x+6x = 15x Both = 27x
D4 M= 8x E = 16x+4x = 19x Both = 27x

Total E = 43x Both = 108x

In option 108 is given. However, 43 is not there.
If we multiply 108*2 = 216, and 43*2 = 86. Both options are available.

Evening shift = 86, and Both shift = 216
User avatar
priyanka06
User avatar
Joined: 10 Sep 2025
Last visit: 07 Sep 2026
Posts: 60
Own Kudos:
36
Given Kudos: 1
Products:
GMAT Club Tests Forum Quiz
Posts: 60
Kudos: 36
GMAT Club World Cup 2026 (Day 9): A plant uses the same group of 17 Jul 2026, 05:09
Kudos
Add Kudos
Bookmarks
Bookmark this Post
let X be the number of workers working per day , so total units of work done in 4 days= 4x

Calculate the division of workers in each shift per day:-
DAY 1: Morning =x, evening=0
day 2: morning= 2/3 x, evening= 1/3 x
day 3: morning= 4/9 x, evening= 5,9 x
day 4: morning= 8/27 x, evening= 19/27 x

total units of work done in evening shifts= 43/27 x

From the table we isolate multiples of 4 which are: 20, 108, 216
then find out value of x which is gives an integer when multiplied by 43/27

so total work done= 108
work done in evening shifts= 86

Bunuel
A plant uses the same group of workers for a 4 day production run. Each worker works one shift per day, either the morning shift or the evening shift, and each worker produces the same number of units in any shift worked.

On Day 1, all workers work the morning shift. Once a worker is assigned to the evening shift, that worker remains on the evening shift for the rest of the production run. On Day 2, one third of the workers who worked the morning shift on Day 1 are assigned to the evening shift. On Day 3, one third of the workers who worked the morning shift on Day 2 are assigned to the evening shift. On Day 4, one third of the workers who worked the morning shift on Day 3 are assigned to the evening shift.

Select for Evening Shift the possible total number of units produced by the evening shift over the four days, and select for Both Shifts the possible total number of units produced by both shifts together over the four days, that would be jointly consistent with the given information. Make only two selections, one in each column.
Show more
User avatar
Rishm
User avatar
Joined: 05 May 2024
Last visit: 07 Sep 2026
Posts: 370
Own Kudos:
78
 [1]
Given Kudos: 82
Location: India
Schools: Johnson '27 LBS '27 IESE '27
GPA: 10
WE:Consulting (Consulting)
Products:
GMAT Club Tests Forum Quiz
Schools: Johnson '27 LBS '27 IESE '27
Posts: 370
Kudos: 78
 [1]
GMAT Club World Cup 2026 (Day 9): A plant uses the same group of 17 Jul 2026, 05:34
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Day 1 shift remains the same, for evening hence the number will be the same. Let x be the number of people on morning shift in 2nd day, Hence 0+1/3+5/9+19/27=43/27, NOW TOTAL is 4 days. Hence 43/27x/4y=43/108 which is 86/108. E - 86, Both Shift - 216.
User avatar
Nsanghavi
User avatar
Joined: 08 Jul 2025
Last visit: 29 Aug 2026
Posts: 59
Own Kudos:
46
 [1]
Given Kudos: 20
Products:
GMAT Club Tests Forum Quiz
Posts: 59
Kudos: 46
 [1]
GMAT Club World Cup 2026 (Day 9): A plant uses the same group of 17 Jul 2026, 06:54
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Let w = total workers
u = number of units/shift
Since only 1 shift per day = Total worker shift = W
Total 4 days shift = 4W
Total units = 4W*u
Day 1 -> Evening Worker = 0, Morning Worker = W
Day 2 -> Evening Worker = 1/3 W, Morning Worker = 2/3W
Day 3 -> 1/3 of Day 2 morning workers, move to evening
Evening Worker = 1/3W+ 2/9W = 5/9W, Morning Worker = 4/9W
Day 4 -> 1/3 of Day 3 morning worker move to evening
Evening Worker = 5/9W+ 4/27W = 19/27W , Morining Worker = 8/27W

Total Evening Shifts = 0+1/3W+15/27W+19/27W = 43/27W
Total Evening Shifts Units = 43/27Wu
Ratio of Evening / Total Units = 43/27Wu/ 4Wu

As per options - I get Evening Shifts = 86 and Both shifts = 216
User avatar
redandme21
User avatar
Joined: 14 Dec 2025
Last visit: 01 Aug 2026
Posts: 157
Own Kudos:
144
 [1]
Posts: 157
Kudos: 144
 [1]
GMAT Club World Cup 2026 (Day 9): A plant uses the same group of 17 Jul 2026, 06:55
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
w = workers*units

Morning day by day: w, w-w/3=2w/3, 2w/3-2w/9=4w/9, 4w/9-4w/27=8w/27
Evening day by day: 0, w/3, w/3+2w/9=5w/9, 5w/9+4w/27=19w/27

Adding all in the morning: w + 2w/3 + 4w/9 + 8w/27 = 65w/27
Adding all in the evening: w/3 + 5w/9 + 19w/27 = 43w/27

evening = 43w/27
both = 65w/27 + 43w/27 = 108w/27 = 4w

Choosing w=54

Evening Shift = 86
Both Shifts = 216
User avatar
gaurikhanna17
User avatar
Joined: 16 Jan 2025
Last visit: 07 Sep 2026
Posts: 73
Own Kudos:
46
 [1]
Products:
GMAT Club Tests
Posts: 73
Kudos: 46
 [1]
GMAT Club World Cup 2026 (Day 9): A plant uses the same group of 17 Jul 2026, 07:08
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
imo : evening shift = 86
bth shift : 216
w = 27 k
d1 + d2+d3+d4 = 0 +9k =15k +19k = 43 k
evening production = 43ku
total for both shifts over 4 days = 4Wu = 4 . 27k . u = 108 ku
only these options satisfy : evening = 86
both = 216
User avatar
sunshineeee
User avatar
Joined: 17 May 2020
Last visit: 07 Sep 2026
Posts: 174
Own Kudos:
53
 [1]
Given Kudos: 267
Location: Indonesia
Schools: Stern '26 (WL) Tepper '26 (WL) BU'26 (A) Ross '26 Johnson '26
Products:
GMAT Club Tests Forum Quiz
Schools: Stern '26 (WL) Tepper '26 (WL) BU'26 (A) Ross '26 Johnson '26
Posts: 174
Kudos: 53
 [1]
GMAT Club World Cup 2026 (Day 9): A plant uses the same group of 17 Jul 2026, 07:13
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Let's say x=total workers
Criteria
- In each day, same group of total workers: x1=x2=x3=x4=x
- Once a worker in the evening shift, they will stay in the evening shift next day

Day 1: all worked in morning shift
- Morning: x
- Evening: 0

Day 2: 1/3 in M-D1 move to E-D2
- E: 1/3 * x = 1/3x
- So M: 2/3 x

Day 3: 1/3 in M-D2 move to E-D3
- E: 1/3 * (2/3x) = 2/9x add with 1/3x = 5/9x
- So M= 1-5/9x = 4/9x

Day 4: 1/3 in M-D3 move to E-D4
- E: 1/3 (4/9x) = 4/27x add with 5/9x = 19/27x
- So M: 1-19/27x = 1/27x

Then, calculate total units produced
Evening from Day 1 to Day 4
= 0 + 1/3x + 5/9x + 19/27x =
E (total) = 43/27x

M=(1+2/3+4/9+1/27)x = 58/27 x
M+E = 101/27 x

M+E : E = 101 : 43

Possible answer:
Evening: 43x2 = 86
Total: 101x2=202 ~ 216

So, 86 (Evening) and 216 (Total)


Bunuel
A plant uses the same group of workers for a 4 day production run. Each worker works one shift per day, either the morning shift or the evening shift, and each worker produces the same number of units in any shift worked.

On Day 1, all workers work the morning shift. Once a worker is assigned to the evening shift, that worker remains on the evening shift for the rest of the production run. On Day 2, one third of the workers who worked the morning shift on Day 1 are assigned to the evening shift. On Day 3, one third of the workers who worked the morning shift on Day 2 are assigned to the evening shift. On Day 4, one third of the workers who worked the morning shift on Day 3 are assigned to the evening shift.

Select for Evening Shift the possible total number of units produced by the evening shift over the four days, and select for Both Shifts the possible total number of units produced by both shifts together over the four days, that would be jointly consistent with the given information. Make only two selections, one in each column.
Show more
User avatar
geocircle
User avatar
Joined: 14 Dec 2025
Last visit: 27 Jul 2026
Posts: 150
Own Kudos:
143
 [1]
Posts: 150
Kudos: 143
 [1]
GMAT Club World Cup 2026 (Day 9): A plant uses the same group of 17 Jul 2026, 07:16
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
N workers

day 1:
morning N
evening 0

day 2:
morning 2N/3
evening N/3

day 3:
morning 4N/9
evening N/3+2N/9=5N/9

day 4:
morning 8N/27
evening 5N/9+4N/27=19N/27

morning N+2N/3+4N/9+8N/27 = 65N/27
evening N/3+5N/9+19N/27 = 43N/27
morning+evening = 65N/27+43N/27 = 108N/27 = 4N

units in the evening: 43N/27 * u -> if N*u=27*2=54 then units=86
units in both: 4N * u -> if N*u=54 then units=216

Evening Shift = 86 and Both Shifts = 216
User avatar
LibrarianTurtle
User avatar
Joined: 12 Nov 2024
Last visit: 06 Sep 2026
Posts: 36
Own Kudos:
24
 [1]
Given Kudos: 8
GPA: 3.9
Products:
GMAT Club Tests Forum Quiz
Posts: 36
Kudos: 24
 [1]
GMAT Club World Cup 2026 (Day 9): A plant uses the same group of 17 Jul 2026, 07:25
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
MorningUnitsEveningUnits
Day 1X workers\(X^2 \)units00
Day 2\(\frac{2x}{3 }\)workers\(\frac{2x^2}{3}\)units\(\frac{x}{3}\) workers\(\frac{x^2}{3} \)units
Day 3\(\frac{4x}{9}\)workers\(\frac{4x^2}{9}\) units\(\frac{5x}{9}\)workers\(\frac{5x^2}{9}\)units
Day 4\(\frac{8x}{27}\)workers\(\frac{8x^2}{27}\) units\(\frac{19x}{27}\) workers\(\frac{19x^2}{27} \)units
Evening total unit =\( \frac{43x^2}{27}\)
Total unit= \(\frac{108x^2}{27 }\)
Evening unit:Total Unit = \(\frac{43}{108}\)
Ans. Evening=86 Both=216
User avatar
topgmat25
User avatar
Joined: 15 Dec 2025
Last visit: 27 Jul 2026
Posts: 150
Own Kudos:
139
 [1]
Posts: 150
Kudos: 139
 [1]
GMAT Club World Cup 2026 (Day 9): A plant uses the same group of 17 Jul 2026, 07:31
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
In Day 1: x (morning), 0 (evening)
In Day 2: 2x/3 (morning), x/3 (evening)
In Day 3: 4x/9 (morning), x/3+2x/9=5x/9 (evening)
In Day 4: 8x/27 (morning), 5x/9+4x/27=19x/27 (evening)

In the 4 Days: (27+18+12+8)x/27=65x/27 (morning), (9+15+19)x/27=43x/27 (evening)

We can assume that each worker produces one unit per day without changing the problem.

In this case:
evening 43x/27
both 4x

if x=27*2=54

Evening Shift: 86
Both Shifts: 216
User avatar
firefox300
User avatar
Joined: 15 Dec 2025
Last visit: 27 Jul 2026
Posts: 151
Own Kudos:
140
 [1]
Posts: 151
Kudos: 140
 [1]
GMAT Club World Cup 2026 (Day 9): A plant uses the same group of 17 Jul 2026, 07:47
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
W = workers
U = units per worker per day

T=WU

Day1:
T in the morning and 0 in the evening

Day2:
2T/3 in the morning and T/3 in the evening

Day3:
4T/9 in the morning and T/3 + 2T/9 = 5T/9 in the evening

Day4:
8T/27 in the morning and 5T/9 + 4T/27 = 19T/27 in the evening

Evening T/3 + 5T/9 + 19T/27 = 43T/27 units
Both must be 4T (W*U*4 days)

T must be divisible by 27:
T=27, then Evening=43 (not in the options)
T=54, then Evening=86 and Both=216

Evening Shift is 86
Both Shifts is 216
   1   2   3   4   
Moderators:
Bunuel
Math Expert
113225 posts
FrozenDragon
DI Forum Moderator
409 posts