OFFICIAL EXPLANATION:
Argument Construction
Situation - Juvenile horseshoe crabs withstand tidal currents by burrowing in the sand.
This action makes barnacles less likely to cling to their shells. Adult horseshoe crabs can
withstand currents, so they do not burrow, and barnacles become more likely to cling to
their shells. Surprisingly, however, juvenile horseshoe crabs that do not burrow, because
tidal currents do not threaten them, do not have significant numbers of barnacles clinging
to their shells.
Reasoning - What would most help explain the finding that nonburrowing juvenile
horseshoe crabs do not have significant barnacle populations? The finding suggests that
there is some way in which nonburrowing juvenile horseshoe crabs either discourage
barnacles from clinging to their shells, or get rid of the barnacles that do cling to their
shells. Identifying how this is accomplished will explain the finding.
A. This gives a reason why juvenile horseshoe crabs that do not burrow would have
significant barnacle populations.
B. If barnacles in areas of weak tidal currents readily attach themselves to horseshoe
crabs, then it would be more likely for juvenile horseshoe crabs in such areas to
have significant barnacle populations.
C. The areas under discussion are those where tidal currents are very weak. The
strength of currents may vary widely there, but presumably they are still weak
compared to other areas.
D. The surprising finding under discussion is why certain juvenile horseshoe crabs do
not have significant barnacle populations, despite failing to engage in behavior that
dislodges barnacles. That a very large barnacle population can hurt a horseshoe crab
does not help explain such a finding.
E. Correct. This statement properly identifies something that helps explain the
surprising finding: If juvenile horseshoe crabs regularly shed their shells, they also
regularly shed the barnacles that cling to those shells. Thus juvenile horseshoe
crabs would most likely be found not to have significant barnacle populations.
The correct answer is E.