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VP
Joined: 18 May 2008
Posts: 1258

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08 Feb 2009, 23:13
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Manager
Joined: 27 May 2008
Posts: 200

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09 Feb 2009, 00:26
selvae wrote:
ritula wrote:

D

exterior angle problems...

From the problem:

1) PSR = PSQ = 90

we need to get X where PRS = X + PRQ! ---1)

Stmt 1: states QPR = 30

So by right angle triangle PSR,
letz say SPR = p,
So PRS = 90 - p ---2)

And by right angle triangle PSQ,
letz say PQS = q
q = 60-p ----- 3)

sub 2) and 3) in 1) we get X So SUFF

Stmt 2: says PQR + PRQ = 150
which means QPR = 30 same as Stmt 1. So SUFF
SVP
Joined: 07 Nov 2007
Posts: 1789
Location: New York

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09 Feb 2009, 09:55
1
KUDOS
PRS = X1
PQS=X2
RPS = Y1
QPS=Y 2

stat1
X1+Y1 =90 -->(1)
X2+Y1+Y2=90 -->(2)

(1)-(2) -->

X1-X2 -Y2=0 (Given Y2=30)
X1-X2 = 30
statement2 is same as 1

D
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VP
Joined: 18 May 2008
Posts: 1258

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09 Feb 2009, 21:33
OA is D indeed. +1 from me
x2suresh wrote:
PRS = X1
PQS=X2
RPS = Y1
QPS=Y 2

stat1
X1+Y1 =90 -->(1)
X2+Y1+Y2=90 -->(2)

(1)-(2) -->

X1-X2 -Y2=0 (Given Y2=30)
X1-X2 = 30
statement2 is same as 1

D
Re: triangle   [#permalink] 09 Feb 2009, 21:33
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