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Two friends phil and andrew started running simultaneously from a poin

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Two friends phil and andrew started running simultaneously from a poin  [#permalink]

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New post 04 Nov 2019, 03:44
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Two friends Phil and Andrew started running simultaneously from a point P in the same direction along a straight running track. The ratio of speeds of Phil and Andrew was 2:5. Two hours later, Andrew turned back and started running running backwards at one-fifth of his original speed. He met Phil at a distance of 10 km from the point P. what was Phil's running speed ?

(A) 1.25 km/hr
(B) 2.25 km/hr
(C) 2.5 km/hr
(D) 3.75 km/hr
(E) 6.25 km/hr

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Two friends phil and andrew started running simultaneously from a poin  [#permalink]

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New post Updated on: 04 Nov 2019, 05:58
speed of Phil=2x
speed of Andrew=5x

Relative distance between Phil and Andrew after 2 hours= 2*(5x-2x)=6x

speed of A after he turned back= 5x/5=x

Time taken by them to meet= \(\frac{6x}{x+2x}\)= 2

Distance of meeting point from P= Total distance traveled by Phil = (2+2)*2x=8x

8x=10
2x= 2.5


Bunuel wrote:
Two friends Phil and Andrew started running simultaneously from a point P in the same direction along a straight running track. The ratio of speeds of Phil and Andrew was 2:5. Two hours later, Andrew turned back and started running running backwards at one-fifth of his original speed. He met Phil at a distance of 10 km from the point P. what was Phil's running speed ?

(A) 1.25 km/hr
(B) 2.25 km/hr
(C) 2.5 km/hr
(D) 3.75 km/hr
(E) 6.25 km/hr

Are You Up For the Challenge: 700 Level Questions

Originally posted by nick1816 on 04 Nov 2019, 04:41.
Last edited by nick1816 on 04 Nov 2019, 05:58, edited 1 time in total.
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Re: Two friends phil and andrew started running simultaneously from a poin  [#permalink]

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New post 04 Nov 2019, 05:53
nick1816
see highlighted part shouldnt it be (2+2)*2x = 8x?

nick1816 wrote:
speed of Phil=2x
speed of Andrew=5x

Relative distance between Phil and Andrew after 2 hours= 2*(5x-2x)=6x

speed of A after he turned back= 5x/5=x

Time taken by them to meet= \(\frac{6x}{x+2x}\)= 2

Distance of meeting point from P= Total distance traveled by Phil = (2*2)*2x=8x

8x=10
2x= 2.5


Bunuel wrote:
Two friends Phil and Andrew started running simultaneously from a point P in the same direction along a straight running track. The ratio of speeds of Phil and Andrew was 2:5. Two hours later, Andrew turned back and started running running backwards at one-fifth of his original speed. He met Phil at a distance of 10 km from the point P. what was Phil's running speed ?

(A) 1.25 km/hr
(B) 2.25 km/hr
(C) 2.5 km/hr
(D) 3.75 km/hr
(E) 6.25 km/hr

Are You Up For the Challenge: 700 Level Questions
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Re: Two friends phil and andrew started running simultaneously from a poin  [#permalink]

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New post 04 Nov 2019, 05:57
That was typo. You have a good eye ;)

Archit3110 wrote:
nick1816
see highlighted part shouldnt it be (2+2)*2x = 8x?

nick1816 wrote:
speed of Phil=2x
speed of Andrew=5x

Relative distance between Phil and Andrew after 2 hours= 2*(5x-2x)=6x

speed of A after he turned back= 5x/5=x

Time taken by them to meet= \(\frac{6x}{x+2x}\)= 2

Distance of meeting point from P= Total distance traveled by Phil = (2*2)*2x=8x

8x=10
2x= 2.5


Bunuel wrote:
Two friends Phil and Andrew started running simultaneously from a point P in the same direction along a straight running track. The ratio of speeds of Phil and Andrew was 2:5. Two hours later, Andrew turned back and started running running backwards at one-fifth of his original speed. He met Phil at a distance of 10 km from the point P. what was Phil's running speed ?

(A) 1.25 km/hr
(B) 2.25 km/hr
(C) 2.5 km/hr
(D) 3.75 km/hr
(E) 6.25 km/hr

Are You Up For the Challenge: 700 Level Questions
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Two friends phil and andrew started running simultaneously from a poin  [#permalink]

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New post 04 Nov 2019, 06:57
2
speed of P= 2x
speed of A = 5x
relative speed = 3x
2 hrs later the relative distance between P & A = 6x
after 2 hrs A speed ; 5x/5 = x
so relative speed of P & A = 3x
time at which they meet = 6x/3x ; 2 hrs
total distance covered by P = (2+2)*2 x; 8x
this 8x = 10km point where A met P
so 2x= 2.5
IMO C


Bunuel wrote:
Two friends Phil and Andrew started running simultaneously from a point P in the same direction along a straight running track. The ratio of speeds of Phil and Andrew was 2:5. Two hours later, Andrew turned back and started running running backwards at one-fifth of his original speed. He met Phil at a distance of 10 km from the point P. what was Phil's running speed ?

(A) 1.25 km/hr
(B) 2.25 km/hr
(C) 2.5 km/hr
(D) 3.75 km/hr
(E) 6.25 km/hr

Are You Up For the Challenge: 700 Level Questions
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Two friends phil and andrew started running simultaneously from a poin   [#permalink] 04 Nov 2019, 06:57
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Two friends phil and andrew started running simultaneously from a poin

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