There are 100 employees in a room. 99% are managers. How man

Question

There are 100 employees in a room. 99% are managers. How many managers must leave the room to bring down the percentage of manager to 98%?

(A) 1
(B) 2
(C) 50
(D) 49
(E) 97

Please give kudos if you like the sum :D 
 The interesting thing here is the base i.e. 100 is also changing as the no. of managers change. Either plug values or use the formula (99-x)/(100-x) = 98/100
Where x = no. of managers leaving.

PareshGmat · Accepted Answer

Managers.......... Non Managers............. Total

99........................ 1 ............................ 100

Let's say x managers leave the room, no new table is

99-x ..................... 1 ................................ (100-x)

Setting up the equation

99-x = \frac{98}{100} * (100-x)

x = 50

Answer = C

Bunuel · Answer

Another approach: We have 99 managers and 1 director. That 1 director to compose 2% of the total number of people, there must be 50 people in the room, hence 50 managers must leave. Answer: C. Similar questions to practice: each-of-the-cucumbers-in-100-pounds-of-cucumbers-is-composed-102354.html five-kilograms-of-oranges-contained-98-of-water-141401.html fresh-dates-contain-90-water-while-dry-dates-contain-143245.html if-grapes-are-92-water-and-raisins-are-20-water-then-how-159030.html Hope this helps.

PareshGmat · Answer

One more approach (Not sure if I would be able to explain properly

) 100 Employees = 99 Managers + 1 Non-Manager ............. (1) Here Non-Managers constitute 1% = 1 We require to make Non-Managers constitute 2% = 1 2% of what is 1 ?? 2 out of 100 = 1 out of 50 If total Employees = 50, then 1 (Non-Managers) will constitute its 2% 50 - 1 = 49 Managers ............. (2) Managers to be removed = (1) - (2) = 99 - 49 = 50 Answer = C

PareshGmat · Answer

One more method of setting up equation

1 = \frac{2}{100} * (100-x)

100 = 200 - 2x

x = 50

Answer = C

mvictor · Answer

try plugging in the numbers, it doesn't take that much time as writing the equation
if 1 manager leaves, we have 98 managers 99 people. 98/99 - is not 98%
if 2 managers leave, we have 97/98 - this is not 98
if 50 managers leave, we have 49 managers, and 50 people, that is 49/50, multiply by 2-> 98/100 or 98%. C.

rohit8865 · Answer

as number of managers changing...other employees remain same
so number of other employees before and after removal of managers are same
1% of 100=2%of(100-x) where x=no. of managers removed out of total 100 employees.
1=2/100(100-x)
x=50
ans C

JeffTargetTestPrep · Answer

Since there are 100 employees in a room and 99% are managers, there are 99 managers. We can let n = the number of managers to take out and create following equation:

(99 - n)/(100 - n) = 98/100

100(99 - n) = 98(100 - n)

9900 - 100n = 9800 - 98n

100 = 2n

n = 50

Answer: C

lincy93 · Answer

There are 100 managers in total.
So T=100
Let 'x' be the no.of managers leaving the room.
 99-x/100-x *100 = 98
x=50

Bounce1987 · Answer

99-x/100-x=98/100
Plug in values from answer choices.
C wins!

varunjoshi31 · Answer

Let number of managers to leave be x.

Equation will be formed is :

99-x = 98/100(100 - x) -> to form 98% managers we remove x managers from existing 99... the total employees would be 100 - x.

Solve this to get value of x as 50

ABHISEKGMAT123 · Answer

Previous (Manager: Others)=99:1
Later (Manager: Others)= 98:2
Later (Manager: Others)= 49:1
Others will remain the same

--->99-49= 50  is the answer

bumpbot · Answer

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There are 100 employees in a room. 99% are managers. How man

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