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Bunuel
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Since, it is asked 'could be true' we can use any 1 case which satisfies the equation and consider it as true.
x>0

I. x^3 > x^2 --> 10^3>10^2 -- true
II. x^2 = x --> 1^2 = 1 -- true
III. x^2 > x^3 --> (1/2)^2>(1/2)^3 -- true

Ans. D) All of the above
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For x>0;

I. x^3 > x^2 .............. when x>1
II. x^2 = x ..................when x=1
III. x^2 > x^3.............. when x<1
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Bunuel

Tough and Tricky questions: Must or Could be True Questions.



If x > 0, which of the following could be true?

I. x^3 > x^2
II. x^2 = x
III. x^2 > x^3

A) I only
B) I & II
C) II & III
D) All of the above
E) None of the above

Kudos for a correct solution.


Source: Chili Hot GMAT


I. x^3 > x^2
This statement is true for any x > 1.

So C and E cannot be correct option.

II. x^2 = x

This statement is true for x = 1.

So A cannot be correct option.

III. x^2 > x^3

This is true for any x > 0 but < 1 say x = (1/2)

So Correct Answer is D
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The world could be defines the entire logic of this question: Cases like this, one needs only one case to hold the question

Option one for any number bigger than one is true.
Option two for number one, Variable X, is true and
Option three for any number between 0 and 1 is true.

Should the world "could be" be "must be", instead, none would be true. Cases that ask for must be trough, on the other hand, one needs all examples to hold which makes its refuge very easy by bringing only example that doesn't hold.
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solved by taking values
x^3> x^2
take x = 2
x^3>x^2
x^2= x
take x = 1
x^2> x^3
take x = 1/2
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for statement 1, why we do not consider fractional number because it says x>0 only for example x= 1/2 ,1/4
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Bunuel

Tough and Tricky questions: Must or Could be True Questions.



If x > 0, which of the following could be true?

I. x^3 > x^2
II. x^2 = x
III. x^2 > x^3

A) I only
B) I & II
C) II & III
D) All of the above
E) None of the above

Kudos for a correct solution.

Source: Chili Hot GMAT

If x=2; x^3>x^2
If x=1; x^2=x
If x=.5;x^2>x^3

IMO D

Posted from my mobile device
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Concept tested: anomaly of [-1,1] bracket. Good sum!

Could be true means there is a possibility that equation holds-

I. x^3 > x^2, true for x=5, so could be true.
II. x^2 = x true for x=1, so could be true.
III. x^2 > x^3 true for x=0.5, so could be true.

All I+II+III could be true.

Chili Hot GMAT :lol:


Bunuel

Tough and Tricky questions: Must or Could be True Questions.



If x > 0, which of the following could be true?

I. x^3 > x^2
II. x^2 = x
III. x^2 > x^3

A) I only
B) I & II
C) II & III
D) All of the above
E) None of the above

Kudos for a correct solution.

Source: Chili Hot GMAT
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If x > 0, which of the following could be true?

This is a could-be-true question so we can take cases where the option will hold true

I. x^3 > x^2 true for x>1
II. x^2 = x true for x=1
III. x^2 > x^3 true for x<1


Hence D
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Why did we not consider fractions and decimals? Like in case of 0.5, only 3 is true
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thelady02
Why did we not consider fractions and decimals? Like in case of 0.5, only 3 is true

Note that the question asks "which of the following could be true?" not "which of the following must be true?". Since each option could be true for some values of x, the answer is D.
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Bunuel
If x > 0, which of the following could be true?

I. x^3 > x^2
II. x^2 = x
III. x^2 > x^3

A) I only
B) I & II
C) II & III
D) All of the above
E) None of the above



Source: Chili Hot GMAT


Note, we're only looking for could be true and not must be true.
If x > 0
I. x^3 > x^2 .. Yes, integer greater than 1
II. x^2 = x .. Yes, x can be equal to 1
III. x^2 > x^3 .. Yes, x can be a positive fraction

Hence
D) All of the above
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