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Bunuel
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So first of all, find the equations of both lines.

Line A: Slope=-1, X Intercept =1.

Find the Y Intercept

X Int=-b/-1=1
-b=-1
b=1

Line A: Y=-X+1

Line B Slope=2, Y Intercept=-2

Line B Y=2X-2

-X+1=2X-2
3=3X
X=1

Plug X into any equation, Y=0

The answer is A
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Bunuel
In the coordinate plane, Line A has a slope of -1 and an x-intercept of 1. Line B has a slope of 2 and a y-intercept of -2. If the two lines intersect at the point (a,b), what is the sum a+b?

A. 0
B. 1
C. 2
D. 3
E. 4


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Equation of line 1
y=mx+c
=>y=-x+c
It passes through point (1,0)
hence 0=-1+c =>c=1
equation of line 1 becomes
y=-x+1 =>y+x=1
it will also pass through point (a,b)
hence a+b=1

We don't need the equation of line in this case :-D .

Ans: B
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Bunuel
In the coordinate plane, Line A has a slope of -1 and an x-intercept of 1. Line B has a slope of 2 and a y-intercept of -2. If the two lines intersect at the point (a,b), what is the sum a+b?

A. 0
B. 1
C. 2
D. 3
E. 4


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VERITAS PREP OFFICIAL SOLUTION:

When attempting to find where two lines intersect, it is typically best to get the lines in point-slope form (y = mx + b). For Line A, you know that the slope is -1, so you have a head start in that m = -1. So you're starting with y = -x + b. And then remember - the x-intercept is the point at which y = 0, so that point is (1, 0). You can then plug that point into the equation to find b:

0 = -(1) + b, so b = 1. You know now that Line A has the equation y = -x + 1.

For Line B, you know that the slope is 2 (so y = 2x + b) and that when x is 0, y = -2. Plug that into the line equation to solve for b and you have -2 = 2(0) + b, so b = -2. Now you know the equation for Line B: y = 2x - 2.

Since y = -x + 1 and y = 2x - 2, the two lines will intersect where -x + 1 = 2x - 2. Algebraically that leads you to x = 1. Plug that back into either line to find y, and you'll find that y = 0. Since the point of intersection is (1, 0), the sum a+b=1, making B the correct answer.
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Bunuel
In the coordinate plane, Line A has a slope of -1 and an x-intercept of 1. Line B has a slope of 2 and a y-intercept of -2. If the two lines intersect at the point (a,b), what is the sum a+b?

A. 0
B. 1
C. 2
D. 3
E. 4


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Quite simply, you just need to set both equations equal in this problem and then plug in the value of x into both equations ( well it's not actually necessary to plug into both because if they equations are equal then x plugged into either will give you the same value for y but sometimes its fine to double check) in order to solve for X. Secondly, you just take the sum of the x and y value and you have the answer.

2x-2 = -x +1
3x= 3
x = 1

2(1)-2= 0 so "y" is 0
-(1) +1 = 0 same thing

1 + 0 = 0

Thus
B
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Bunuel
Bunuel
In the coordinate plane, Line A has a slope of -1 and an x-intercept of 1. Line B has a slope of 2 and a y-intercept of -2. If the two lines intersect at the point (a,b), what is the sum a+b?

A. 0
B. 1
C. 2
D. 3
E. 4


Kudos for a correct solution.

VERITAS PREP OFFICIAL SOLUTION:

When attempting to find where two lines intersect, it is typically best to get the lines in point-slope form (y = mx + b). For Line A, you know that the slope is -1, so you have a head start in that m = -1. So you're starting with y = -x + b. And then remember - the x-intercept is the point at which y = 0, so that point is (1, 0). You can then plug that point into the equation to find b:

0 = -(1) + b, so b = 1. You know now that Line A has the equation y = -x + 1.

For Line B, you know that the slope is 2 (so y = 2x + b) and that when x is 0, y = -2. Plug that into the line equation to solve for b and you have -2 = 2(0) + b, so b = -2. Now you know the equation for Line B: y = 2x + 4.

Since y = -x + 1 and y = 2x + 4, the two lines will intersect where -x + 1 = 2x + 4. Algebraically that leads you to -3 = 3x, so x = -1. Plug that back into either line to find y, and you'll find that y = 2. Since the point of intersection is (-1, 2), the sum a+b=1, making B the correct answer.

I am confused here. Why line B equation is y = 2x +4 ? We are given the slope (2) and the y-intercept (-2). Shouldn't the equation be y = 2x - 2 ?
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TheBunk
Bunuel
Bunuel
In the coordinate plane, Line A has a slope of -1 and an x-intercept of 1. Line B has a slope of 2 and a y-intercept of -2. If the two lines intersect at the point (a,b), what is the sum a+b?

A. 0
B. 1
C. 2
D. 3
E. 4


Kudos for a correct solution.

VERITAS PREP OFFICIAL SOLUTION:

When attempting to find where two lines intersect, it is typically best to get the lines in point-slope form (y = mx + b). For Line A, you know that the slope is -1, so you have a head start in that m = -1. So you're starting with y = -x + b. And then remember - the x-intercept is the point at which y = 0, so that point is (1, 0). You can then plug that point into the equation to find b:

0 = -(1) + b, so b = 1. You know now that Line A has the equation y = -x + 1.

For Line B, you know that the slope is 2 (so y = 2x + b) and that when x is 0, y = -2. Plug that into the line equation to solve for b and you have -2 = 2(0) + b, so b = -2. Now you know the equation for Line B: y = 2x + 4.

Since y = -x + 1 and y = 2x + 4, the two lines will intersect where -x + 1 = 2x + 4. Algebraically that leads you to -3 = 3x, so x = -1. Plug that back into either line to find y, and you'll find that y = 2. Since the point of intersection is (-1, 2), the sum a+b=1, making B the correct answer.

I am confused here. Why line B equation is y = 2x +4 ? We are given the slope (2) and the y-intercept (-2). Shouldn't the equation be y = 2x - 2 ?

Yes, the OE had typos. Edited. Thank you!
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Equation of line is y = mx + c or x = my + c

For line A: m = -1 and the x-intercept is 1

=> x = (-1)y + 1

=> x + y = 1---------------(1)


For line B: m = 2 and the y-intercept is -2

=> y = (2)x - 2

=> 2x + y = 2---------------(1)


Both line intersects at (a,b). Therefore, lets find value of x and y:

=> x + x + y = 2

=> x + 1 = 2

=> x = 1 and therefore y = 0

=> (x,y) ---> (1,0)---->(a,b)-----> (a + b) -----> (1 + 0 = 1)

Answer B
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