Bunuel
In the coordinate plane, Line A has a slope of -1 and an x-intercept of 1. Line B has a slope of 2 and a y-intercept of -2. If the two lines intersect at the point (a,b), what is the sum a+b?
A. 0
B. 1
C. 2
D. 3
E. 4
Kudos for a correct solution.
VERITAS PREP OFFICIAL SOLUTION:When attempting to find where two lines intersect, it is typically best to get the lines in point-slope form (y = mx + b). For Line A, you know that the slope is -1, so you have a head start in that m = -1. So you're starting with y = -x + b. And then remember - the x-intercept is the point at which y = 0, so that point is (1, 0). You can then plug that point into the equation to find b:
0 = -(1) + b, so b = 1. You know now that Line A has the equation y = -x + 1.
For Line B, you know that the slope is 2 (so y = 2x + b) and that when x is 0, y = -2. Plug that into the line equation to solve for b and you have -2 = 2(0) + b, so b = -2. Now you know the equation for Line B: y = 2x + 4.
Since y = -x + 1 and y = 2x + 4, the two lines will intersect where -x + 1 = 2x + 4. Algebraically that leads you to -3 = 3x, so x = -1. Plug that back into either line to find y, and you'll find that y = 2. Since the point of intersection is (-1, 2), the sum a+b=1, making B the correct answer.
I am confused here. Why line B equation is y = 2x +4 ? We are given the slope (2) and the y-intercept (-2). Shouldn't the equation be y = 2x - 2 ?