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AbdurRakib
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10 Jun 2016, 04:28
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
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78% (01:55) correct
22%
(02:23)
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based on 506
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For all real numbers x, the operation Δ is defined as xΔ =x+\(\frac{x}{4}\) . If (bΔ)Δ =\(\frac{25}{8}\) , what is the value of b ?
(A) 1.5
(B) 2
(C) 2.5
(D) 3
(E)3.5
(A) 1.5
(B) 2
(C) 2.5
(D) 3
(E)3.5
25 Nov 2018, 04:49
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Hope this helps.
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General Discussion
10 Jun 2016, 04:41
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AbdurRakib
xΔ =x+\(\frac{x}{4} = \frac{5x}{4}\)...
so \((bΔ)Δ = \frac{5}{4}*\frac{5b}{4}\)=\(\frac{25}{8}\).................\(\frac{25b}{16}= \frac{25}{8}\)........b=2
B
