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Let the total amount paid be x

Now coming to the individual split's we use the information given in the question stem

Ken's split = x/6 + 9 = 10x/60 + 9
Justin's split = 2x/5 - 8 = 24x/60 - 8
Dan's split = x/12 + 1 = 5x/60 + 1
Melissa's split = 40$

Total = Ken's split + Justin's split + Dan's split + Mellisa's split
x = 39x/60 +42
21x/60 = 42
x = 120(Option B)
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Bunuel
Four friends split their lunch bill such that Ken paid $9 more than 1/6 of the total, Justin paid $8 less than 2/5 of the total, Dan paid $1 more than 1/12 of the total, and Melissa paid the remaining $40. How much was the total bill?

A. $84
B. $120
C. $144
D. $180
E. $216

Let Total bill be \(T\).
Ken paid \(= 9 + \frac{1}{6}T\)
Justin paid \(= \frac{2}{5}T - 8\)
Dan paid \(= 1 + \frac{1}{12}T\)
Melissa paid \(= $40\)

\(T = 40 + 9 + \frac{1}{6}T + \frac{2}{5}T - 8 + 1 + \frac{1}{12}T = 42 + \frac{10T + 24T + 5T}{60} = \frac{39T}{60} + 42\)

\(T - \frac{39T}{60} = 42\) ==> \(60T - 39T = 42*60\) ==> \(21T = 42*60\)

\(T = \frac{42*60}{21}\)

\(T = $120\) . Answer B...
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Bunuel
Four friends split their lunch bill such that Ken paid $9 more than 1/6 of the total, Justin paid $8 less than 2/5 of the total, Dan paid $1 more than 1/12 of the total, and Melissa paid the remaining $40. How much was the total bill?

A. $84
B. $120
C. $144
D. $180
E. $216


Hi,

of course the method above by all is the one to find answer, at times a bit of logic can get the answer for you or get you close to the answer, if you are clueless..

the fractions given are 1/6 , 2/5, 1/12...
so our answer has to be MULTIPLE of LCM of 6,5,12, or multiple of 60
ONLY B and D are left..
atleast the probability has come up to 50% from 20%, in some other Q it may just give you the answer
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K = T/6 + 9
J = 2T/5 - 8
D = T/12 + 1
M = 40

K+J+D+M = T
Solve for T.

T = K+J+D+M
T = T/6 + 9 + 2T/5 - 8 + T/12 + 1 + 40
T= 39T/60 + 42
21T/60T = 42
T = 120
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Bunuel
Four friends split their lunch bill such that Ken paid $9 more than 1/6 of the total, Justin paid $8 less than 2/5 of the total, Dan paid $1 more than 1/12 of the total, and Melissa paid the remaining $40. How much was the total bill?

A. $84
B. $120
C. $144
D. $180
E. $216

LCM of 6, 5 & 12 = 60

So, the total bill amount must be a multiple of 60 , Only options (B) and (D) remains..

Check any one option to mark the answer...

Let's check option (B) -

Total Bill amount is 120
Ken paid = 29
Justin paid = 40
Dan paid = 11
Melissa paid = 40

Total = 29+40+11+40 = 120

Hence, (B) is the correct answer...
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Bunuel
Four friends split their lunch bill such that Ken paid $9 more than 1/6 of the total, Justin paid $8 less than 2/5 of the total, Dan paid $1 more than 1/12 of the total, and Melissa paid the remaining $40. How much was the total bill?

A. $84
B. $120
C. $144
D. $180
E. $216

We can let the total bill = t.

Ken paid 9 + (1/6)t, Justin paid (2/5)t - 8, Dan paid (1/12)t + 1, and Melissa paid 40. Thus:

9 + (1/6)t + (2/5)t - 8 + (1/12)t + 1 + 40 = t

42 + (1/6)t + (2/5)t + (1/12)t = t

Multiplying the equation by 60, we have:

2,520 + 10t + 24t + 5t = 60t

2520 = 21t

120 = t

Answer: B
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