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Bunuel
If \(0 < 10^n < 1,000,000\), where n is a non-negative integer, what is the greatest value of \(\frac{1}{2^n}\)?


A. 1/2
B. 1
C. 5
D. 32
E. 64

\(0 < 10^n < 1,000,000\)

0 < 10^n < 10^6

So, n could be 0,1,2,3,4,5 since n is a non-negative integer.

The greatest value of \(\frac{1}{2^n}\) could be achieved if 2^n is the smallest, i.e. for n = 0 at which the fraction becomes 1/2^0
or 1/1 = 1.

Ans B) 1
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0<10^n<1,000,0000
since , n is a non negative integer , n = 0,1,2,3,4,5
to get max of 1/2^n , n must be 0 (min value )
so, the required value = 1/2^0 = 1
correct answer B
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