Last year $48,000 of a certain store's profit was shared by its 2 owne

Question

Last year $48,000 of a certain store's profit was shared by its 2 owners and their 10 employees. Each of the 2 owners received 3 times as much as each of their 10 employees. How much did each owner receive from the $48,000 ?
 
A. $12,000
 
B. $9,000
 
C. $6,000
 
D. $4,000
 
E. $3,000

(PS17812)

KSBGC · Accepted Answer

let the amount received by each employee be x.

So, 10 employees got = 10x
each owner got = 3x

we can form an equation ,

3x+3x + 10x = 48000
16x = 48000
x = 3000

we are asked to find out the amount of each owner . 
3x
=3*3000
=9000

Thus , B is the best option.

BrentGMATPrepNow · Answer

Each owner received 3 times as much as each employee  
Let E = the amount (in dollars) that ONE employee received
So, 3E = the amount (in dollars) that ONE owner received

Last year $48,000 of a certain store's profit was shared by its 2 owners and their 10 employees.   
In other words: 3E + 3E + E + E + E + E + E + E + E + E + E + E = 48,000
Simplify: 16E = 48,000
So, E = 48,000/16
= 3,000

So, each EMPLOYEE received $3000, which means each OWNER received $9000
Answer: B

Cheers,
Brent

avigutman · Answer

Video solution from Quant Reasoning:
 https://www.youtube.com/watch?v=lNxHUpRE4tE

chetan2u · Answer

Two ways..
1) weighted average..
Owners : employees= 2*3:10..
So owners get  48000*\frac{6}{6+10}=18000 
So each owner gets half of it =18000/2=9000

2) let each employee get X, so owner gets 3x..
Total = 2*3x+10*X=48000.......16x=48000......X=3000
So each owner gets =3000*3=9000

B

GMATGuruNY · Answer

We can PLUG IN THE ANSWERS, which represent the share for each owner.
Since the share for each owner is 3 times the share for each employee, the correct answer is almost certainly a multiple of 3 (A, B, C or E).
When the correct answer is plugged in, the total profit = 48,000.

B: $9000 for each of the 2 owners, implying $3000 for each of the 10 employees
Total profit = (2*9000) + (10*3000) = 18000 + 30000 = 48,000.
Success!

B

BrentGMATPrepNow · Answer

Although I believe it's best to use one variable to solve this question, we can also use  two variables 
Let's see how that solution would look.

Let x = the amount (in dollars) that ONE employee received
Let y = the amount (in dollars) that ONE owner received

Each owner received 3 times as much as each employee  
So, we can write:  y = 3x

Last year $48,000 of a certain store's profit was shared by its 2 owners and their 10 employees.   
So, the total amount two owners received = y + y = 2y
The total amount 10 employees received = 10x
So, we can write:  10x + 2y = 48,000

At this point, we have the following system of linear equations:
 y = 3x 
 10x + 2y = 48,000

When we solve this system (I'll leave it to you to do this), we get x = 3000 and y = 9000
So, each each OWNER received $9000

Answer: B

Cheers,
Brent

ScottTargetTestPrep · Answer

We can let the employee share = n and thus the owner share = 3n, and we have:

48,000 = 2(3n) + 10n

48,000 = 16n

3,000 = n

So each owner received 3 x 3,000 = 9,000 dollars.

Answer: B

nust2017 · Answer

Hello everyone. Just want a quick opinion. Is plugging the answers, and comparing to the share for each owner, and then checking 3 times the amount received a sane way of approaching this question?

Thanks !

Ved22 · Answer

Since total amount is $48000, and considering 2owners and 10 employees so total makes 12. So each gets $48000/12 = $3000. Now since the 2 owners gets trice so each will get 3*3000 = $9000

shaonkarim · Answer

Let,

Each Employee get x

Each owner will get 3x

Now,

3x+3x+10x=48000

=>16x=48000

=>x=3000

So, each owner will get 3*3000 =9000

Answer: B

Posted from my mobile device

BijayKru · Answer

2 owner and 10 employees so total 12

let all get x amount initially
But owner get 3 times more then employees

So if emp. = x owner =3 x

Total will be divide on x* 10(emp.) + x*3 (1 owner)+ x*3 (2owner) =16 x

So 16x = 48000
x = 3000

So owner will get 3*x = 9000

fauji · Answer

Approach: 
- Total people: 10+2
- Employee received: x
- Owner received(3 times of an employee): 3x

Total: 10(x)+2(3x) = 48000 => x = 3000

Each Owner received: 3x or 3*3000 = $9000

Option B

Carlosfernando25 · Answer

Profit= $48,000
Employee= x
Owner= y

x=3y
2(3y)+10y =48,000

16y=48,000

y= 3,000

x=3(3,000)

x=9,000

GMATinsight · Answer

Answer: Option B

Video solution by  GMATinsight

https://www.youtube.com/watch?v=0TfOm9Y_n1o

Kinshook · Answer

Given: Last year $48,000 of a certain store's profit was shared by its 2 owners and their 10 employees. Each of the 2 owners received 3 times as much as each of their 10 employees. 
Asked: How much did each owner receive from the $48,000 ?
 
There are (2*3 + 10 = 16) parts of $48000 profits
Each part = $3000

Owner's part = 3*$3000 = $9000

IMO B

Rainman91 · Answer

Start from Answer choice C. 6k times 2 = 12k. 6k/3 = 2k multiplied with 10 = 20k. 12 + 20 = 32. We need more money. Go to B. 9K x 2 = 18k. 3k x 10 = 30k. 30 + 18 = 48.

jaysoorya · Answer

wait how is this even right ?? 48,000/12 =4 , 4*3 =12

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Last year $48,000 of a certain store's profit was shared by its 2 owne

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