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Sub 505 (Easy)|   Sequences|      
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Bunuel
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If the first term in an arithmetic sequence is 15 and the 132th term 15 Jul 2020, 01:48
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

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5% (low)

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89% (01:45) correct 11% (02:00) wrong based on 104 sessions

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If the first term in an arithmetic sequence is 15 and the 132th term is 3,290, what is the common difference between any two consecutive terms?

A. 10
B. 15
C. 25
D. 30
E. 35
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C
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chipsy
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If the first term in an arithmetic sequence is 15 and the 132th term 15 Jul 2020, 01:51
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a+131d = 3290
Since a = 15

15+131d = 3290
d = 3275/131
d = 25

Option C

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If the first term in an arithmetic sequence is 15 and the 132th term 15 Jul 2020, 23:17
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Bunuel
If the first term in an arithmetic sequence is 15 and the 132th term is 3,290, what is the common difference between any two consecutive terms?

A. 10
B. 15
C. 25
D. 30
E. 35
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132 term = 3290
=> a + 131d = 3290
=> 131d = 3275
=> d = 25

Hence, OA is (C).
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If the first term in an arithmetic sequence is 15 and the 132th term 19 Apr 2021, 03:07
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Difference between 1st term and 132nd term is 131*d.

Therefore, 131*d= 3290 - 15
131*d= 3275
d= 25.

Hence, option C , 25 is the common difference.

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If the first term in an arithmetic sequence is 15 and the 132th term 20 Apr 2021, 01:26
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a = 15 and a + 131d = 3,290

=> 15 + 131d = 3,290

=> 131d = 3,290 - 15 = 3,275

=> d = 25

Answer C
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