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MathRevolution
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The employees in a company ordered pizza or spaghetti. One-half of th Updated on: 23 Jul 2020, 00:49
Originally posted by MathRevolution on 21 Jul 2020, 03:14.
Last edited by MathRevolution on 23 Jul 2020, 00:49, edited 1 time in total.
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

25% (medium)

Question Stats:

78% (02:13) correct 22% (02:18) wrong based on 107 sessions

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[GMAT math practice question]

The employees in a company ordered pizza or spaghetti. One-half of the employees ordered pizza, \(\frac{3}{5}\) of the employees ordered spaghetti, and 30% of the employees order both pizza and spaghetti. Six employees ordered neither. How many employees work for the company?

A. \(15\)

B. \(20\)

C. \(25\)

D. \(30\)

E. \(35\)
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D
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The employees in a company ordered pizza or spaghetti. One-half of th 21 Jul 2020, 03:30
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x/5+3x/5-30+6 =x
this gives x = 260.
What did I miss
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The employees in a company ordered pizza or spaghetti. One-half of th 21 Jul 2020, 04:20
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In question, it should be "30%" , instead of 30 of the employees order both pizza and spaghetti.

6 employees = 20% [ neither]
so , total = 30 employees

Option D
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The employees in a company ordered pizza or spaghetti. One-half of th Updated on: 21 Jul 2020, 08:18
Originally posted by VERBAL1 on 21 Jul 2020, 05:00.
Last edited by VERBAL1 on 21 Jul 2020, 08:18, edited 1 time in total.
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MathRevolution Bunuel ...is this question worded correctly ??

As per question 3/5 and 1/2 of employees exist

Which means option a c e are gone

As per question , 30 ordered both so B not possible

Left with D

But minimum people should be 36?

Posted from my mobile device
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The employees in a company ordered pizza or spaghetti. One-half of th 21 Jul 2020, 07:27
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There is an error in the question please correct it
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The employees in a company ordered pizza or spaghetti. One-half of th 23 Jul 2020, 02:25
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=>

Attachment:
7.21ps(a).png
7.21ps(a).png [ 2.87 KiB | Viewed 1778 times ]

Assume \(a + b + c + d = 100\)%.

We have \(a + c = 50\)%, \(a + b = 60\)% and \(a = 30\)%.

Substituting \(a = 30\)% into the other 2 equations gives us, \(a + c = 50\)%, \(30\)% \(+ c = 50\)%, \(c = 20\)% and \(a + b = 60\)%, \(30\)% \(+ b = 60\)%, \(b = 30\)%.

We have \(d = 20\)% since \(a + b + c + d = 100\)% and \(a + b + c = 80\)%.

Since \(6\) employees make up \(20\)% of the total employees we have \(\frac{6}{e} = \frac{20}{100}. \) Cross multiplying gives us \(20e = 600\), and the total number of employees = \(30\).

Therefore, D is the correct answer.
Answer: D
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