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Bunuel
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The given number is not a multiple of 6
For a number to be a multiple of 6, it has to be a multiple of 2 and 3 both.

Sum of the digits of the the given number = 22 i.e not a multiple of of 3

hence k =0
and expression \(6^k−k\) = 1-0 = 1
D is the answer IMO

Bunuel
If k is a non-negative integer, and \(6^k\) is a factor of 345,136 what is \(6^k−k\)?

A. −6
B. −1
C. 0
D. 1
E. 6
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6^k is factor of 345136

Let's see if 345136 is divisible by 6 -> no
Hence k = 0 -> 6^k - k = 1 - 0 = 1 D
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since both 345 and 126 aren't divisible by 6, k=0 , therefore, answer is 1
option- D
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6^k is a factor of 345,136 what is 6^k−k
Sum of all the digits of the number = 3+4+5+1+3+6 =22
Not divisible by 3

Clearly not div by 6
k = 0
6^k - k = 1 -0 = 1

IMO D
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Bunuel -- pls clarify if 345,136 is a single number or 2 different numbers
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Sanya15
Bunuel -- pls clarify if 345,136 is a single number or 2 different numbers
_________________________
It's one number: 345,136.
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Bunuel
If k is a non-negative integer, and \(6^k\) is a factor of 345,136 what is \(6^k−k\)?

A. −6
B. −1
C. 0
D. 1
E. 6


As 345,136 is not divisible by 3, It's also not divisible by 6;

So the only value of k it is valid is k=0 which is 1;

IMO D
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