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02 Apr 2015, 05:20
Kudos
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
68% (02:02) correct
32%
(02:31)
wrong
based on 452
sessions
History
Date
Time
Result
Not Attempted Yet
If k is a non-negative integer and 15^k is a divisor of 759,325 then 3^k - k^3 =
A. 0
B. 1
C. 37
D. 118
E. 513
A. 0
B. 1
C. 37
D. 118
E. 513
Updated on: 02 Apr 2015, 07:51
Originally posted by Harley1980 on 02 Apr 2015, 05:31.
Last edited by Harley1980 on 02 Apr 2015, 07:51, edited 1 time in total.
Last edited by Harley1980 on 02 Apr 2015, 07:51, edited 1 time in total.
Kudos
Bookmarks
Bunuel
If k is a non-negative integer and 15^k is a divisor of 759,325 then 3^k - k^3 =
A. 0
B. 1
C. 37
D. 118
E. 513
Kudos for a correct solution.
A. 0
B. 1
C. 37
D. 118
E. 513
Kudos for a correct solution.
At first we should understand whether 759325 divisible by 15.
15 is equal to 3 * 5 so 759325 should be divisible on these integers
759325 is divisible by 5 because of last digit 5
but not divisible by 3 because sum of its digits doesn't divisible by 3: 7 + 5 + 9 + 3 + 2 + 5 = 31 and 31 doesn't divisible by 3
so 759325 can be divisible by 15^k only if k = 0 and 15^k = 1
so 3^k - k^3 = 1 - 0 = 1
answer is B
General Discussion
02 Apr 2015, 05:37
Kudos
Bookmarks
Bunuel
If k is a non-negative integer and 15^k is a divisor of 759,325 then 3^k - k^3 =
A. 0
B. 1
C. 37
D. 118
E. 513
Kudos for a correct solution.
A. 0
B. 1
C. 37
D. 118
E. 513
Kudos for a correct solution.
7+5+9+3+2+5=31=4
Therefore, 759,325 is not divisble by 15.
Hence, k=0
3^k - k^3 =1-0=1
Answer: B
