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enigma123
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I think the question lacks a bit of information. It mentions that both the integers should be greater than 1 but does not mention that both integers should be different. However, still, when prime numbers are squared, the number of different factors increases by 1 which is a product of the prime no multiplied by the prime number.
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Can the positive integer k be expressed as the product of two integers, each of which is greater than 1?

Question basically asks whether k is a prime number. If it is, then it cannot be expressed as the product of two integers, each of which is greater than 1 (definition of a prime number).

Bunuel - I take it you mean product of two DIFFERENT integers, each of which is greater than 1.
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If k is some composite number greater than 1, then it has more than 2 factors --> So K will be prime or not? Am I reading something wrong Bunuel?
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If k is some composite number greater than 1, then it has more than 2 factors --> So K will be prime or not? Am I reading something wrong Bunuel?

A prime number is a natural number with exactly two distinct natural number divisors: 1 and itself. Otherwise a number is called a composite number.

So, composite numbers are not primes.

We are considering 3 cases for (1):
k=prime;
k=composite>1;
K=1;

And get that k can be only a prime number.

enigma123
Can the positive integer k be expressed as the product of two integers, each of which is greater than 1?

Question basically asks whether k is a prime number. If it is, then it cannot be expressed as the product of two integers, each of which is greater than 1 (definition of a prime number).

Bunuel - I take it you mean product of two DIFFERENT integers, each of which is greater than 1.

It doesn't really matter. Can you express a prime as the product of two same integers?
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Can the positive integer \(k\) be expressed as the product of two integers, each of which is greater than 1?
(1) \(k^2\) has one more positive factor than k.
(2) \(11 < k < 19\)

I don't understand well this explanation of the OE. Please, your help:
The only types of numbers k such that k2 has exactly one more positive factor than k are primes. Prime numbers have two factors and their squares have three. If k had more than two factors, the number of factors would increase by more than 1 when squared. Thus, k must be prime, answering the question.
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danzig
Can the positive integer \(k\) be expressed as the product of two integers, each of which is greater than 1?
(1) \(k^2\) has one more positive factor than k.
(2) \(11 < k < 19\)

I don't understand well this explanation of the OE. Please, your help:
The only types of numbers k such that k2 has exactly one more positive factor than k are primes. Prime numbers have two factors and their squares have three. If k had more than two factors, the number of factors would increase by more than 1 when squared. Thus, k must be prime, answering the question.

Note, for a number K the factors are K,1 and 'few other' depending upon whether it is prime or not
for number k^2 - the factors are 1, k and k^2 and 'few other'

The 'few other' factors depend on the fact whether K is divisible by a number or not.

For example:
factors of 5 : 1, 5 and ? - nothing else
factors of 6: 1, 6 and ? - (2,3)

Similarly,
factors of 25: 1,5, 25 and ? - nothing else ( because 5 is not divisible by anything else and hence can not be broken into any other number)
factors of 36: 1,6,36 and ? - (2,3,4,9, 12,18)

Therefore if you notice the pattern only for a prime number, number of factors of k^2 is one more than number of factors for k.


Now with this concept target the question
stem 1 : it shows us k is prime using above mentioned concept. can a prime number be a product of 2 integers each greather than 1? no. So we have a sufficient statement to say No.
stem 2: K could be anything from 12 to 18. So ans would be if k is 12 then yes, but if k is 13 then no. hence insufficient.

Therefore ans A (only statement 1 is sufficient) it is.

Hope it is clear.
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danzig
Can the positive integer \(k\) be expressed as the product of two integers, each of which is greater than 1?
(1) \(k^2\) has one more positive factor than k.
(2) \(11 < k < 19\)

I don't understand well this explanation of the OE. Please, your help:
The only types of numbers k such that k2 has exactly one more positive factor than k are primes. Prime numbers have two factors and their squares have three. If k had more than two factors, the number of factors would increase by more than 1 when squared. Thus, k must be prime, answering the question.

Basically, what the question asks is whether k is not a prime number.

1)k is prime. Sufficient.
2)k can be 12,13,14,15,16,17,18. Both primes and non primes appear in this set. Insufficient

Answer is A.

Kudos Please... If my post helped.
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danzig
Can the positive integer \(k\) be expressed as the product of two integers, each of which is greater than 1?
(1) \(k^2\) has one more positive factor than k.
(2) \(11 < k < 19\)

I don't understand well this explanation of the OE. Please, your help:
The only types of numbers k such that k2 has exactly one more positive factor than k are primes. Prime numbers have two factors and their squares have three. If k had more than two factors, the number of factors would increase by more than 1 when squared. Thus, k must be prime, answering the question.

Merging similar topics. Please refer to the solutions above.
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kys123
Statement 1: K^2 has one more factor. Let's say if K was a 4 (non-prime ) then it will have 4 factors. [1,2,4]. If you square 4, 16 has 5[1,2,4,8,16] factors. The factors increased by 2. The only way for a factor to increase by 1 is if the number is prime. 13 has 2 factors [1,13]. 169 has 3 factors [1,13,169].

This mean K is a prime. The only 2 numbers that can multiple to 13 is 13 and 1. Therefore we know the answer for the question is NO.

Answer A is sufficient

K may or may not be prime. Who said anything about the factor other than k being not equal to 1?
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