Last visit was: 23 Apr 2026, 22:40 It is currently 23 Apr 2026, 22:40
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
BillyZ
User avatar
Current Student
Joined: 14 Nov 2016
Last visit: 24 Jan 2026
Posts: 1,135
Own Kudos:
22,610
 [26]
Given Kudos: 926
Location: Malaysia
Concentration: General Management, Strategy
GMAT 1: 750 Q51 V40 (Online)
GPA: 3.53
Products:
3
Kudos
Add Kudos
23
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
BrentGMATPrepNow
User avatar
Major Poster
Joined: 12 Sep 2015
Last visit: 31 Oct 2025
Posts: 6,733
Own Kudos:
36,452
 [7]
Given Kudos: 799
Location: Canada
Expert
Expert reply
Posts: 6,733
Kudos: 36,452
 [7]
4
Kudos
Add Kudos
3
Bookmarks
Bookmark this Post
General Discussion
User avatar
lorenzo393
Joined: 23 Jan 2017
Last visit: 29 Mar 2025
Posts: 12
Own Kudos:
Given Kudos: 3
Posts: 12
Kudos: 13
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
BillyZ
User avatar
Current Student
Joined: 14 Nov 2016
Last visit: 24 Jan 2026
Posts: 1,135
Own Kudos:
22,610
 [1]
Given Kudos: 926
Location: Malaysia
Concentration: General Management, Strategy
GMAT 1: 750 Q51 V40 (Online)
GPA: 3.53
Products:
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
ziyuenlau

Tricky question.



For consecutive integers \(x\) and \(y\), where \(x>y\), what is the value of \(x\)?

(1) \(x^2−y^2=37\)
(2) \(x^2+y^2=685\)

Official solution from Veritas Prep.

This problem rewards two important GMAT concepts. One relates directly to Data Sufficiency as a question type, for which you want to always Leverage Assets; here that means taking the definition "consecutive integers" and turning that into a mathematical operation \((x−y=1)\). The other relates to fluency with the Common Algebraic Equations, and in particular here the Difference of Squares equation:

\(x^2−y^2=(x+y)(x−y)\)

Once you see that Statement 1 fits the Difference of Squares, you should immediately factor it so that you see the equation both ways.

\(x^2−y^2=37\)

Also means that:

\((x+y)(x−y)=37\)

If you then pair that with the equation \(x−y=1\), which you derived from the definitions "consecutive integers" and \(x>y,\) you then know that: \(1(x+y)=37\). And for two consecutive integers to sum to 37, that must mean that \(x=19\) and \(y=18\). Therefore, you have sufficient information with Statement 1 to determine that \(x=19\). With Statement 1, you can also leverage the information \(x−y=1\), manipulation that equation to know that \(y=x−1\). That allows you to get close, substituting that into the given equation:

\(x^2+(x−1)^2=685\)

That then allows you to expand the parenthetical:

\(x^2+x^2−2x+1=685\)

And then combine like terms:

\(2x^2−2x=684\)

Then divide by 2:

\(x^2−x=342\)

By this point, you should see that this quadratic will lead to multiple solutions for x (those solutions are 19 and −18), meaning that Statement 2 is not sufficient. Note that you can save those algebraic steps if you test the numbers you've already identified as possible consecutive integers from statement 1. 192 and 182 will sum to 685, but since both terms are squares the consecutive integer pairing will work with both positive numbers and negative numbers, so you cannot determine which pair from this statement alone).
User avatar
GMATBusters
User avatar
GMAT Tutor
Joined: 27 Oct 2017
Last visit: 23 Apr 2026
Posts: 1,922
Own Kudos:
Given Kudos: 241
WE:General Management (Education)
Expert
Expert reply
Posts: 1,922
Kudos: 6,856
Kudos
Add Kudos
Bookmarks
Bookmark this Post
(1) \(x^2−y^2=37\)
(x-y)(x+y)= 37
As x>y and x and y are consecutive integer, x-y = 1
(x+y)= 37
x+x-1= 37
2x=38
x= 19
Sufficient

(2) \(x^2+y^2=685\)
It is very interesting to analyze St2

As it is sum of square of x and y, we can straightaway say that we will not be able to find a unique of x and y
as the values can be negative or positive.

Taking a simple example
\( 4^2+3^2=25\\
(-3)^2+(-4)^2=25\)

Statement 2 is NOT sufficient

Answer A

BillyZ

Tricky question.



For consecutive integers \(x\) and \(y\), where \(x>y\), what is the value of \(x\)?

(1) \(x^2−y^2=37\)
(2) \(x^2+y^2=685\)
­
Moderators:
Math Expert
109802 posts
498 posts
212 posts