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28 Jul 2017, 04:01
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
72% (01:53) correct
28%
(01:56)
wrong
based on 253
sessions
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Time
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Not Attempted Yet
If the average (arithmetic mean) of six numbers j, k, m, n, p, and q is 56, how many of the numbers are equal to 56?
(1) The sum of j and p is 128.
(2) The sum of m, n, and q is 152.
(1) The sum of j and p is 128.
(2) The sum of m, n, and q is 152.
28 Jul 2017, 05:46
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When you use both statements here, you find j+p+m+n+q = 280, and since the sum of all six numbers is 336, the remaining number k must be equal to 336 - 280 = 56. So using both statements, at least one value in the set is exactly 56. But it's certainly possible other values are also 56. Looking at Statement 1, we might have j = 56 and p = 72, for example, in which case we'd have at least one other value equal to 56, but there's no need for one of j or p to be 56 -- we could have j = 0 and p = 128, say. Similarly, some of m, n and q might equal 56, but there's no need for that to be true. So the answer is E.
It would perhaps be a more interesting question if it asked whether at least one of the numbers was equal to 56. In that case, the two statements would be sufficient together.
It would perhaps be a more interesting question if it asked whether at least one of the numbers was equal to 56. In that case, the two statements would be sufficient together.
28 Jul 2017, 11:43
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I think this is not a high quality question. It is clear that one or more of the numbers could equal 56.
