In a party both Veg and Non–Veg variants were served.

Question

In a party both Veg and Non–Veg variants were served. If 60% of the people who attended the party took exactly one of the two variants, what percentage of the people who attended the party took only Veg food?

(1) 25% of the people who had Veg also had Non–Veg.

(2) 20% of the people who had at least one of the two variants had both the variants.

TarunTilokani · Accepted Answer

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deushyant · Answer

Can someone please help me out? The second statement completely threw me off.

Posted from my mobile device

DavidTutorexamPAL · Answer

1) the information about those who took both tells us nothing about the breakdown of the 60% who took only one of two (it could be anywhere between 0% and 60% only veg). . Insufficient! 
2) once again, this only tells the size of the "both" group, not the "only veg". insufficient!

Combined - both statements describe the "both" group in different ways, so we know that 20% of the total equals 25% of the veg group. If we call the only veg group y, this gives us the following equation: 
y/4=(60 + y/4)/5 
5y/4=60+y/4
4y/4=60
y=60 
sufficient!

akurathi12 · Answer

I am also cofused with statmenent 2. I am requesting experts to expain this.

DavidTutorexamPAL · Answer

check my response out - tell me if it helps

anmolsd1995 · Answer

Still not understanding the answer. Please Help

Ansh777 · Answer

Please note a minor correction in the two equations:

Statement 1:  25% of the people who had Veg also had Non–Veg. 
Person who had veg according to vein diagram= a+b
 i.e. 25%*(a+b)=b 
i.e. 25%a=75%b
b=a/3
cannot solve further, Not sufficient

Statement 2: 20% of the people who had   at least one   of the two variants had both the variants.

i.e. 20% * ( a+b+c) =b 
or 20% *60=80%b
b=15
Cannot solve for a, Not sufficient

Combining
a=3*15 = 45

Answer: C

harshilNori · Answer

Hey as per question, isnt a+c -b = 60. Cause they mentioned exactly one variant. and a -> all who ate Veg and b -> all who ate non veg. a+b = all veg + all non veg. This would include those who ate veg + non veg twice. So we need to subtract b. Is my understanding correct?

juanar · Answer

I think this is a poor quality question since you don't how how many people didn't take neither Vegan nor Non-vegan food. Without that information you can't know the answer...

aditya0289 · Answer

The second statement says that  20% of the people who had at least one variant , so. shouldn't the equation be 20% of (a+b+c)?

RitwikAgrawal · Answer

Can someone please explain why aren't we considering the case of so guests who did not have any of the variant? Since there is no evidence that each had guest had at least one variant.

NoeticImbecile · Answer

Hello, shouldn't it be 25% of (a+b) = b?

In a party both Veg and Non–Veg variants were served.

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In a party both Veg and Non–Veg variants were served.

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