BrentGMATPrepNow
If j and k are positive integers, what is the value of j?
(1) 4j + 3k = 18
(2) |64k² + 32kj + 4j²| = (-22)²
I created this question to highlight a common mistake students make.
Target question: What is the value of j? Given: j and k are positive integers Statement 1: 4j + 3k = 18 Many students will see this equation with 2 variables and automatically conclude that there are infinitely many solutions, in which case, statement 1 is not sufficient.
Under most conditions, this conclusion would be correct. However, the given information tells us that j and k are
positive integers, which severely limits the possible solutions.
In fact, there is only ONE pair of positive integers that satisfy the equation: j = 3 and k = 2.
So, we can be certain that
j = 3Since we can answer the
target question with certainty, statement 1 is SUFFICIENT
Statement 2: |64k² + 32kj + 4j²| = (-22)² First factor the part inside the absolute value to get: |(8k + 2j)²| = (-22)²
This means that EITHER (8k + 2j)² = (-22)² OR (8k + 2j)² = -(-22)²
We can quickly dismiss the second case, (8k + 2j)² = -(-22)², since (8k + 2j)² must be greater than or equal to zero. So, it could never equal -(-22)²
So, what about (8k + 2j)² = (-22)² ?
This means that either 8k + 2j = 22 or 8k + 2j = -22
If j and k are both
positive, we know that 8k + 2j will be positive, which means there are no solutions to the equation 8k + 2j = -22
What about the equation 8k + 2j = 22?
If we take this equation and divide both sides by 2, we get a simpler (yet equivalent) equation: 4k + j = 11
Under the restriction that j and k are POSITIVE INTEGERS, there are two possible solutions.
Case a: k = 1 and j = 7. In this case, the answer to the target question is
j = 7Case b: k = 2 and j = 3. In this case, the answer to the target question is
j = 3Since we can’t answer the
target question with certainty, statement 2 is NOT SUFFICIENT
Answer: A
Cheers,
Brent