Bunuel
Tough and Tricky questions: Sequences.
If m > 0, y > 0, and x is m percent of 2y, then, in terms of y, m is what percent of x?
A. y/200
B. 2y
C. 50y
D. 50/y
E. 5000/y
Kudos for a correct solution.I did this problem differently than DaVagabond, using some algebraic manipulation as well as properties of fractions and decimals as percentages. My solution is as follows:
For this problem, one needs to know a little about converting to percentages. First, when saying x is m percent of 2y, this means we need to know how to write some number m as a percentage. As percent implies (per one hundred) dividing m by 100 gives us m as a percentage. So we have x is m percent of 2y, or x = (m/100)*2y. This is because when saying x is a certain percentage of another number, you can find x by multiplying the given number by that percentage.
The next property we need to know is how to convert a fraction into a percentage. The problem wants us to find out what percentage m is of x. This value will be equal to (m/x)*100. Whenever finding what percentage some number m is of some number x, one can simply divide m/x and then multiply by 100. For example, when finding what percent 2 is of 3, 2/3 as a percentage, is 200/3, or 66.7%.
Now that we have our equation and our conversion property, we just need to solve.
We need to manipulate x = (m/100)*2y and get a term of (m/x). In doing so we find (m/x) = 50/y. To find (m/x) as a percentage, we just multiply 50/y * 100 which gives us an answer of 5000/y.
So the answer is choice E.