If k=x/5^az^by^c, and k is expressed as a decimal, will that decimal t

Question

If  k=\frac{x}{5^az^by^c} , and k is expressed as a decimal, will that decimal terminate?

(1) y = 3
(2) z = 2

Balajikarthick1990 · Answer

I will go with C since...any number if it has dr in the form 2^a*5^b results in terminating decimal.

chetan2u · Answer

Always be careful, when we do not know anything about the variables.. 
combined...
we do not know anything about x, a,b, or c.. if any of them is 0 or fraction or -ive.. 
Insuff
E

Himanshu9818 · Answer

If  k=\frac{x}{5^az^by^c} , and k is expressed as a decimal, will that decimal terminate?

(1) y = 3
(2) z = 2

I think the answer should be A because if any fraction having 3 in its denominator. That should be non terminating. 
I can be wrong also but i will go with A.

Abhishek009 · Answer

Completely agree with  chetan2u

The answer has to be (E) , you simply can not solve this problem without knowing the other variables...

Himanshu9818 · Answer

Completely agree with  chetan2u

The answer has to be (E) , you simply can not solve this problem without knowing the other variables...
[/colorHimanshu

but it is given in the question that k is expressed as a decimal

Abhishek009 · Answer

Have a look at this discussion here about terminating decimals : https://gmatclub.com/blog/2012/04/gmat-m ... -decimals/ Further as per your last You have assumed that since the denominator has 3 , it will be a terminating decimal, thats true but not always.. Consider it this way - 12/3 =4 { Terminating whole number } 1/3 = 0.3333 { Non Terminating decimal } Here in this case we need to have the value of denominator as well as the numerator.... Say x = 9 , y = 3 {as given in option 1} and c = 2 The we can have a terminating decimal... Hope it helps !!

chetan2u · Answer

Yes if a 3 is in denomnator, answer should be a non terminating decimal, BUT the fraction has to be in simplest form..
examples
 k=\frac{x}{5^az^by^c} ..
a) x= 9, c=2..
 k=\frac{9}{5^az^b3^2}  =  k=\frac{1}{5^az^b} .. so 3 is cancelled out. we do ot know what z is. so CAN'T say..
b) x=12, c=2
 k=\frac{12}{5^az^b3^2}  =  k=\frac{4}{5^az^b*3} .. so 3 isin denominator. again MAY be, But if z is 1/3 and b=1...NO
you can actually make so many combinations of these variables..
Neither it is given that these are Integers or Fraction ; -ive or +ive
Clearly Insuff

Emily1122 · Answer

Terminating decimals 
The question never says they are integers. If the prime factors are 2, 5, or 2 and 5, then it will terminate.

1) y = 3, if z = 1/3 (assume a,b,c = 1), then it terminates. If y = 3, z = 1, then it does not terminate. 
similar logic for statement 2).

If k=x/5^az^by^c, and k is expressed as a decimal, will that decimal t

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