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If k=x/5^az^by^c, and k is expressed as a decimal, will that decimal t
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30 Apr 2016, 03:42
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If k=x/5^az^by^c, and k is expressed as a decimal, will that decimal t
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30 Apr 2016, 05:10
Bunuel wrote: If \(k=\frac{x}{5^az^by^c}\), and k is expressed as a decimal, will that decimal terminate?
(1) y = 3 (2) z = 2 I will go with C since...any number if it has dr in the form 2^a*5^b results in terminating decimal.
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Re: If k=x/5^az^by^c, and k is expressed as a decimal, will that decimal t
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30 Apr 2016, 05:16
Balajikarthick1990 wrote: Bunuel wrote: If \(k=\frac{x}{5^az^by^c}\), and k is expressed as a decimal, will that decimal terminate?
(1) y = 3 (2) z = 2 I will go with C since...any number if it has dr in the form 2^a*5^b results in terminating decimal. BUT THERE IS A 3 IN DR Always be careful, when we do not know anything about the variables.. combined... we do not know anything about x, a,b, or c.. if any of them is 0 or fraction or ive..Insuff E
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Re: If k=x/5^az^by^c, and k is expressed as a decimal, will that decimal t
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30 Apr 2016, 13:25
[quote="Bunuel"]If \(k=\frac{x}{5^az^by^c}\), and k is expressed as a decimal, will that decimal terminate?
(1) y = 3 (2) z = 2
I think the answer should be A because if any fraction having 3 in its denominator. That should be non terminating. I can be wrong also but i will go with A.



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Re: If k=x/5^az^by^c, and k is expressed as a decimal, will that decimal t
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30 Apr 2016, 13:42
Completely agree with chetan2uThe answer has to be (E) , you simply can not solve this problem without knowing the other variables...
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Re: If k=x/5^az^by^c, and k is expressed as a decimal, will that decimal t
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30 Apr 2016, 13:53
[quote="Abhishek009"]Completely agree with chetan2u[b][color=#ed1c24]The answer has to be (E) , you simply can not solve this problem without knowing the other variables... [/colorHimanshu but it is given in the question that k is expressed as a decimal



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Re: If k=x/5^az^by^c, and k is expressed as a decimal, will that decimal t
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30 Apr 2016, 14:04
Himanshu9818 wrote: but it is given in the question that k is expressed as a decimal
Have a look at this discussion here about terminating decimals : http://gmatclub.com/blog/2012/04/gmatm ... decimals/Further as per your last Quote: if any fraction having 3 in its denominator. You have assumed that since the denominator has 3 , it will be a terminating decimal, thats true but not always.. Consider it this way  12/3 =4 { Terminating whole number } 1/3 = 0.3333 { Non Terminating decimal } Here in this case we need to have the value of denominator as well as the numerator.... Say x = 9 , y = 3 {as given in option 1} and c = 2 The we can have a terminating decimal... Hope it helps !!
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Re: If k=x/5^az^by^c, and k is expressed as a decimal, will that decimal t
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30 Apr 2016, 19:41
Himanshu9818 wrote: Bunuel wrote: If \(k=\frac{x}{5^az^by^c}\), and k is expressed as a decimal, will that decimal terminate?
(1) y = 3 (2) z = 2
I think the answer should be A because if any fraction having 3 in its denominator. That should be non terminating. I can be wrong also but i will go with A. Yes if a 3 is in denomnator, answer should be a non terminating decimal, BUT the fraction has to be in simplest form.. examples \(k=\frac{x}{5^az^by^c}\).. a) x= 9, c=2.. \(k=\frac{9}{5^az^b3^2}\) = \(k=\frac{1}{5^az^b}\).. so 3 is cancelled out. we do ot know what z is. so CAN'T say.. b) x=12, c=2 \(k=\frac{12}{5^az^b3^2}\) = \(k=\frac{4}{5^az^b*3}\).. so 3 isin denominator. again MAY be, But if z is 1/3 and b=1...NO you can actually make so many combinations of these variables.. Neither it is given that these are Integers or Fraction ; ive or +ive Clearly Insuff
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